使用第一个索引 Swift 对数组中的数组重新排序

Reordering Arrays within Arrays using the First Index Swift

我正在尝试对数组进行排序,如下所示:

 var arrayTst = [
    [12443, "Starbucks", "Coffee1", "Coffee11", "Tea1", "Drinks1"],
    [12495, "Coffee Bean", "Coffee2", "Tea2", "Cookies2"],
    [13000, "GroceryMarket", "Tea3", "Bubble Tea3", "Shaved Ice3", "Mangoes"], 
    [10000, "Costco", "Soda4", "Salads4", "Pizza4"]
]

如何使用第一个索引(显示距离)从最小到最大对列表进行排序?例如,因为我希望这个数组按距离从最小到最大排序,所以我希望它排序为:

var arrayTst = [
    [10000, "Costco", "Soda4","Salads4","Pizza4"],
    [12443, "Starbucks", "Coffee1","Coffee11", "Tea1", "Drinks1"],
    [12495, "Coffee Bean", "Coffee2", "Tea2","Cookies2"],
    [13000, "GroceryMarket", "Tea3", "Bubble Tea3", "Shaved Ice3", "Mangoes"]
]

距离是使用 .distance(from: currentLocation) 计算的,并通过 for 循环放入数组中。

您需要重新考虑您的数据结构。而不仅仅是 Any 的数组,看起来你有一个…

的数组
struct Store {
    let distance: Double
    let name: String
    let products: [String]
}

那么……

var arrayTst = [
    Store(distance: 12443, name: "Starbucks", products: ["Coffee11", "Tea1", "Drinks1"]),
    Store(distance: 12495, name: "Coffee Bean", products: ["Coffee2", "Tea2", "Cookies2"]),
    etc…
]

let sortedArray = arrayTst.sorted { [=11=].distance < .distance }