如何根据给定的匹配键获取特定的嵌套数组？

Question

如何使用 PHP 内置函数

根据给定的匹配键获取特定的嵌套数组

场景

$id = 1035; // Searching ID

$a = [
    'id'=> 291,    
    'children' => [
        [
            'id'        => 1034,
            'children'  => [
                [
                    'id'      => 111,
                    'name'    => 'ABC',
                    'figure'  => '6 digits',  
                    'children'=> []  
                ],
                [
                    'id'        => 1035,
                    'lft'       => 'LEFT',
                    'children'  => [
                        [
                            'id'        => 1036,
                            'children'  => [
                                [
                                    'id'      => 222,
                                    'someKey' => 'some value',
                                    'children'=> []  
                                ]
                            ]
                        ],
                        [
                            'id'      => 333,
                            'someKey' => 'some value',
                            'children'=> []  
                        ]
                    ],
                ]
            ],
         ],
         [
            'id'        => 1024,
            'title'     => 'ABC',    
            'children'  => [

            ],
        ]
    ]
];

请注意，'id' 和 'children' 键始终存在。如何获取“1035”ID的"children"..?

预期输出

[
    [
        'id'        => 1036,
        'children'  => [
            [
                'id'      => 222,
                'someKey' => 'some value',
                'children'=> []  
            ]
        ],
    ],
    [
        'id'      => 333,
        'someKey' => 'some value',
        'children'=> []  
    ]
];

尝试过

function getRecursiveCategoryIds($key, $categories = []){
    $return = null;
    try {
        array_walk_recursive($categories, function($v, $k) use ($key, &$return){

            if (null != $return) {

                 // Run loop to get the next immediate "children" key
                 if ($k == 'children') {  // It's not matching anymore

                     $return = $v;
                     //return false;
                     throw new Exception;

                 }
             } else if($v == $key) {
                 // Found
                 $return = $v;
             }
        });
    } catch(Exception $e) {}

    return $return;
}

$d = getRecursiveCategoryIds($id, $a);
echo '<pre>D: '; print_r($d); die;    

我用上面的代码试过了，但是"if ($k == 'children') {"不再匹配了..！

欢迎提出任何建议...（PHP 的内置函数最受青睐！）

Answer 1

我做到了。请查看代码中的注释：

<?php
    $id = 1035; // Searching ID
    $myObj = array();

    $a = [
        'id'=> 291,    
        'children' => [
            [
                'id'        => 1034,
                'children'  => [
                    [
                        'id'      => 111,
                        'name'    => 'ABC',
                        'figure'  => '6 digits',  
                        'children'=> []  
                    ],
                    [
                        'id'        => 1035,
                        'lft'       => 'LEFT',
                        'children'  => [
                            [
                                'id'        => 1036,
                                'children'  => [
                                    [
                                        'id'      => 222,
                                        'someKey' => 'some value',
                                        'children'=> []  
                                    ]
                                ]
                            ],
                            [
                                'id'      => 333,
                                'someKey' => 'some value',
                                'children'=> []  
                            ]
                        ],
                    ]
                ],
            ],
            [
                'id'        => 1024,
                'title'     => 'ABC',    
                'children'  => [

                ],
            ]
        ]
    ];

    function findObject($id, $obj) {
        global $myObj;
        // This is an object.
        if (isset($obj["id"])) {
            echo "Checking {$obj["id"]}<br />";
            // Check the id to what we need.
            if ($obj["id"] == $id) {
                // Yay! We found it. Return the object.
                echo "Yay we found {$obj["id"]}<br />";
                $myObj = $obj;
            }
            else {
                echo "Checking children of {$obj["id"]}<br />";
                // See if it has any children
                if (isset($obj["children"]) && count($obj["children"]) > 0) {
                    echo "There are children for {$obj["id"]}<br />";
                    foreach ($obj["children"] as $child) {
                        findObject($id, $child);
                    }   
                }
            }
        }
    }

    findObject($id, $a);
    print_r($myObj);

输出

Checking 291
Checking children of 291
There are children for 291
Checking 1034
Checking children of 1034
There are children for 1034
Checking 111
Checking children of 111
Checking 1035
Yay we found 1035
Need to find a way to break out!
Checking 1024
Checking children of 1024

Found it!
Array
(
    [id] => 1035
    [lft] => LEFT
    [children] => Array
        (
            [0] => Array
                (
                    [id] => 1036
                    [children] => Array
                        (
                            [0] => Array
                                (
                                    [id] => 222
                                    [someKey] => some value
                                    [children] => Array
                                        (
                                        )
                                )
                        )
                )
            [1] => Array
                (
                    [id] => 333
                    [someKey] => some value
                    [children] => Array
                        (
                        )
                )
        )
)

演示：

• https://ideone.com/UoKqrU
• https://3v4l.org/rWkPq

Answer 2

您可以在其他检查中使用函数：

$id=1035;
$a = [
    'id'=> 291,    
    'children' => [
        [
            'id'        => 1034,
            'children'  => [
                [
                    'id'      => 111,
                    'name'    => 'ABC',
                    'figure'  => '6 digits',  
                    'children'=> []  
                ],
                [
                    'id'        => 1035,
                    'lft'       => 'LEFT',
                    'children'  => [
                        [
                            'id'        => 1036,
                            'children'  => [
                                [
                                    'id'      => 222,
                                    'someKey' => 'some value',
                                    'children'=> []  
                                ]
                            ]
                        ],
                        [
                            'id'      => 333,
                            'someKey' => 'some value',
                            'children'=> []  
                        ]
                    ],
                ]
            ],
         ],
         [
            'id'        => 1024,
            'title'     => 'ABC',    
            'children'  => [

            ],
        ]
    ]
];


function nigsearch($arr,$id)
{
    if(gettype($arr) == 'array')
    foreach($arr as $key =>$list)
{

    if(gettype($list) == 'array'){
    if(isset($list['id']))
    {
        if($list['id'] ==$id)
            print_r($list['children']);


    }
        nigsearch($list,$id);
    }
}

}

foreach($a as $key)
{

    nigsearch($key,$id);


}