使用字段的输出作为 url

Question

我正在尝试编写一个应用程序，该应用程序接受 URL 的用户输入，然后移动到下一个视图并使用该 URL 在浏览器中加载。

我有输入页面，我想我已经保存了它，但不确定如何在最终视图中使用该数据并将其加载到浏览器中 - 我尝试的方法只是让屏幕变白 - 我在我希望输入 url 的位置包含一个 url - 请参阅下面的代码 -

//
//  ViewController.swift
//  webView
//
//  Created by Yash Patel on 18/10/17.
//  Copyright © 2017 Yash Patel. All rights reserved.
//

import UIKit
import WebKit


class lockdownfield {
weak var lockdowntest: UITextField? {

    func viewDidLoad() {
        UserDefaults.standard.setValue(lockdownfield?.self, forKey: "lockdowntest")
}
return nil }
}
class ViewController: UIViewController {

@IBOutlet weak var webview: WKWebView!

override func viewDidLoad() {
    super.viewDidLoad()
    let url = URL(string: "http://tablet.brainsplurge.co.uk/video-playlists/lancome-selfridges-oxford-st-1/")
    let request = URLRequest(url: url!)
    webview.load(request)
}

override var prefersStatusBarHidden: Bool {
    return true
}
}

Answer 1

嘿@Danny 这是解决方案。

class ViewController: UIViewController {
    override func viewDidLoad() {
        super.viewDidLoad()
    }
    @IBOutlet var txtField: UITextField!

    @IBAction func NextBtn(_ sender: Any) {
        let storyboard = UIStoryboard(name: "Main", bundle: nil)
        let vc = storyboard.instantiateViewController(withIdentifier: 
"ViewController2") as! ViewController2
        vc.passUrl = txtField.text!
        self.navigationController?.pushViewController(vc, animated: true)
    }  
}

//下一个Class是.

class ViewController2: UIViewController {

@IBOutlet var webView: UIWebView!
var passUrl = String()

override func viewDidLoad() {
    super.viewDidLoad()

    print(passUrl)
    let websiteUrl = URL(string: "http://\(passUrl)")
    //let websiteUrl = URL(string: "http://tablet.brainsplurge.co.uk")//open to check

    var urlRequest: URLRequest? = nil
    if let anUrl = websiteUrl {
        urlRequest = URLRequest(url: anUrl)
    }
    if let aRequest = urlRequest {
        webView.loadRequest(aRequest)
    }

}

Answer 2

这是我的解决方案，有点类似于 SAXENA 的，但更完整。

ViewController1:

class ViewController1: UIViewController {

    @IBOutlet var urlTextField: UITextField!

    override func viewDidLoad() {
        super.viewDidLoad()

        //If user is opening the app the second time, then we just redirect him directly to the webView with the saved URL
        let secondLoad = UserDefaults.standard.bool(forKey: "secondLoad")
        if secondLoad == true {
            let vc = storyboard?.instantiateViewController(withIdentifier: "ViewController2") as! ViewController2
            vc.userURL = UserDefaults.standard.url(forKey: "userURL") as! URL
            self.present(vc, animated: false, completion: nil)
        }
    }

    @IBAction func goToNextScreen(_ sender: UIButton) {

        let vc = storyboard?.instantiateViewController(withIdentifier: 
"ViewController2") as! ViewController2
        vc.userURL = URL(string: urlTextField.text!)
        //Save the URL for further usage
        UserDefaults.standard.set(userURL, forKey: "userURL")
        self.navigationController?.pushViewController(vc, animated: true)
        // if you don't have a navigationController embeded into your ViewController use this function instead
        //self.present(vc, animated: true, completion: nil)
    }  
}

ViewController2:

class ViewController2: UIViewController {

@IBOutlet var webView: UIWebView!
var userURL: URL!

override func viewDidLoad() {
    super.viewDidLoad()

    let urlRequest = URLRequest(url: userURL)
    webView.loadRequest(urlRequest)
    UserDefaults.standard.set(true, forKey: "secondLoad")

}

TODO:// 在将用户发送到下一页之前，您需要检查用户是否输入了有效的 URL。这是一个可以为您做到这一点的 pod： https://github.com/adamwaite/Validator

如果不是有效的URL，显示错误弹窗让用户输入正确的URL，否则不要将他发送到ViewController2。

使用字段的输出作为 url

Using output from field as url

ios

swift

wkwebview