Vue Router 中组件的条件导入

Question

我有这个问题，我想在同一条路线上导入不同的组件。

这个很好用

import Mycomponent from '@/views/Mycomponent'

{
  name: 'My component name',
  path: somepath,
  component: Mycomponent,
}

这行不通

import Mycomponent from '@/views/Mycomponent'
import MycomponentDifferent from '@/views/MycomponentDifferent'

{
  name: 'My component name',
  path: somepath,
  component: () => {
    if(true) {
     console.log(Mycomponent) // You can see in console whole component
     return Mycomponent
    } else {
     return MycomponentDifferent
    }
  }
}

这也行不通

import Mycomponent from '@/views/Mycomponent'

{
  name: 'My component name',
  path: somepath,
  component: () => {
    return HomepageView
  }
}

Answer 1

是否在某个地方记录了您可以使用 component 的函数？
您可以使用 getter:

而不是函数

import Mycomponent from '@/views/Mycomponent'
import MycomponentDifferent from '@/views/MycomponentDifferent'

{
  name: 'My component name',
  path: somepath,
  get component() {
    if(true) {
     console.log(Mycomponent) // You can see in console whole component
     return Mycomponent
    } else {
     return MycomponentDifferent
    }
  }
}