如何连接MYSQL组中前N条记录的查询结果

Question

我有以下查询，它给出了按降序排列的用户 ID 分组的名称的计数。到目前为止，我已经达到了，但不能超越。我想连接每个用户前 2 条记录的名称列。

目前的查询是：

SELECT t.*, 
       IF(@grp = t.user_id, @rowno := @rowno + 1, @rowno := 1) AS rowno, 
       @grp := t.user_id AS u_id 
FROM   (SELECT notes.user_id, 
               t.name        name, 
               Count(t.name) ct 
        FROM   notes 
               INNER JOIN tags t 
                       ON notes.id = t.note_id 
        GROUP  BY notes.user_id, 
                  t.name 
        ORDER  BY notes.user_id, 
                  Count(t.name) DESC) t;

结果如下：

+---------+------------+----+-------+-----+
| user_id | name       | ct | rowno | uid |
+---------+------------+----+-------+-----+
| 282     | realifex   | 1  | 1     | 282 |
+---------+------------+----+-------+-----+
| 282     | clear      | 1  | 2     | 282 |
+---------+------------+----+-------+-----+
| 282     | thinking   | 1  | 3     | 282 |
+---------+------------+----+-------+-----+
| 282     | refreshing | 1  | 4     | 282 |
+---------+------------+----+-------+-----+
| 285     | solid      | 2  | 1     | 285 |
+---------+------------+----+-------+-----+
| 285     | clear      | 1  | 2     | 285 |
+---------+------------+----+-------+-----+
| 285     | thinking   | 1  | 3     | 285 |
+---------+------------+----+-------+-----+
| 287     | holidays   | 3  | 1     | 287 |
+---------+------------+----+-------+-----+
| 287     | Larry      | 3  | 2     | 287 |
+---------+------------+----+-------+-----+
| 287     | travel     | 2  | 3     | 287 |
+---------+------------+----+-------+-----+
| 287     | thinking   | 1  | 4     | 287 |
+---------+------------+----+-------+-----+

我正在尝试将每个用户组的前 2 个结果合并到一列中，如下所示：

+---------+----------------+
| user_id | name           |
+---------+----------------+
| 282     | realifex,clear |
+---------+----------------+
| 285     | solid,   clear |
+---------+----------------+
| 287     | Larry,travel   |
+---------+----------------+

Answer 1

我们 group_concat():

SELECT group_id, group_concat(name order by rn) as names
FROM (SELECT t.*, 
             (@rn := IF(@grp = t.user_id, @rowno := @rowno + 1, 
                        IF(@grp := t.user_id, 1, 1)
                       )
             )  as rn
      FROM (SELECT n.user_id, t.name, n.name,  Count(t.name) ct 
            FROM notes n INNER JOIN
                 tags t 
                 ON notes.id = t.note_id 
            GROUP BY n.user_id,  t.name 
            ORDER BY n.user_id, Count(t.name) DESC
           ) t CROSS JOIN
           (SELECT @rn := 0, @grp := -1) params
     ) t
WHERE rn <= 2
GROUP BY user_id;

注：

@rn 和 @grp 的表达式是单个表达式。 MySQL 不保证 SELECT 中表达式的求值顺序，因此单个表达式是安全分配两个变量的唯一方法。
变量已初始化。
WHERE 子句是确定 "top 2" 的地方。

如何连接MYSQL组中前N条记录的查询结果

How to concat query result of top N records from a group in MYSQL

mysql

sql

ruby-on-rails-3

ruby-on-rails-4