yii2 如何连接两个表并在 gridview 中显示？

Question

我有三张桌子？ s(s#,firstName,lastName)、p(p#,name) 和 sp(s#,p#,qty)。 s模型（由gii创建）中有所有关系。

代码：

public function actionIndex()
    {


        $dataProvider = new ActiveDataProvider([
            'query' =>s::find(),

        ]);

        return $this->render('index', [
            'dataProvider' => $dataProvider,
        ]);
    }

在索引视图中：

<?= GridView::widget([
    'dataProvider' => $dataProvider,
    'columns' => [
        ['class' => 'yii\grid\SerialColumn'],


        'firstName',
        'lastName',

        [
         'attribute'=>'qty',
         'value'=>'sp.qty'

        ]

        ['class' => 'yii\grid\ActionColumn'],
    ],
]); ?>

我想在网格视图中显示数量。但它没有显示。我想在 gridview 中显示以下查询：

select firstName,lastName,qty from s join sp on s.s#=sp.s#

有什么问题？

Answer 1

创建搜索class

class sSearch extend s {
    public $name;
    public $qnt;
    public functioin search()
    {
        return new ActiveDataProvider([
            'query' =>self::find()
               ->select([
                 's.*',
                 'sp.qnt'
               ])
               ->innerJoin('sp','s.s = sp.s'),

        ]);
    }
}

搜索class添加到操作

public function actionIndex()
{
    $search = new sSearch()
    return $this->render('index', [
        'dataProvider' => $search->search(),
    ]);
}

Answer 2

有很多方法可以做到这一点。

方法一：

public function actionIndex()
    {
        $dataProvider = new ActiveDataProvider([
            'query' =>p::find(),

        ]);

        return $this->render('index', [
            'dataProvider' => $dataProvider,
        ]);
    }

在您的网格视图中：

<?= GridView::widget([
    'dataProvider' => $dataProvider,
    'columns' => [
        ['class' => 'yii\grid\SerialColumn'],

        [
            //to be declared in PSearch Model
            'attribute' => 'first_name',
            'value' => function ($data) {
                // Relation will be setup in the model
                if ($data->sp) {
                    return $data->sp->s->first_name;
                } 
                return 'Display whatever is required';
            },
        ],

        [
            //to be declared in PSearch Model
            'attribute' => 'last_name',
            'value' => function ($data) {
                // Relation will be setup in the model
                if ($data->sp) {
                    return $data->sp->s->last_name;
                } 
                return 'Display whatever is required';
            },
        ],

        'name',


        [
            //to be declared in PSearch Model
            'attribute' => 'quantity',
            'value' => function ($data) {
                // Relation will be setup in the model
                if ($data->sp) {
                    return $data->sp->quantity;
                } 
                return 'Display whatever is required';
            },
        ],

        ['class' => 'yii\grid\ActionColumn'],
    ],
]); ?>

如果这没有帮助，请发表评论。谢谢！！

Answer 3

首先你应该检查你的关系：应该是 hasOne 而不是 hasMany

getSps() {
 return $this->hasOne(Sp::className(), ['sId' => 'id']); 
}

并且您必须要求与 sps 建立关系，而不仅仅是 sp 因为您的关系名称是 getSps

<?= GridView::widget([
    'dataProvider' => $dataProvider,
    'columns' => [
        ['class' => 'yii\grid\SerialColumn'],


        'firstName',
        'lastName',

        [
         'attribute'=>'qty',
         'value'=>'sps.qty'

        ]

        ['class' => 'yii\grid\ActionColumn'],
    ],
]); ?>

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