在 UIPickerView 的单元格中使用 UIButton

Question

在我的应用程序中，我有一个设置页面，我想要一个用作复选框的 UIPickerView（列出项目，您可以启用或禁用它们）。我查找了不同的解决方案，我所能找到的只是使用 viewForRow 和使用 UIButton。我可以添加按钮，看起来不错，但按钮似乎不可点击。

这是我的实现：

func pickerView(_ pickerView: UIPickerView, viewForRow row: Int, forComponent component: Int, reusing view: UIView?) -> UIView{
    let button = UIButton(type: .system)
    button.addTarget(self, action: #selector(screenSelectorButtonPress(_:)), for: .touchUpInside)
    button.tag = 0
    if row == 0{
        button.setTitle(Array3[row], for: .normal)
    }else{
        button.setTitle("\u{2610} \(Array3[row])", for: .normal)
    }
    return button
}

@objc func screenSelectorButtonPress(_ sender:UIButton!){
    print("test")
}

所有单元格都正确填充，但点击它们没有任何反应。我想要的功能与在 safari 中看到的 here 完全一样。

是否有其他方法可以做到这一点，或者我对按钮做错了什么？另外是的，我可以只使用开关，但我们的 Android 版本的应用程序使用检查列表，就像 safari 一样，我们希望保持一致。

Answer 1

你应该实施

func pickerView(_ pickerView: UIPickerView, 
        didSelectRow row: Int, 
         inComponent component: Int)

//

self.pickerView.delegate = self

//

class ViewController: UIViewController , UIPickerViewDelegate,UIPickerViewDataSource , UIGestureRecognizerDelegate {

    let pickerView = UIPickerView()

    override func viewDidLoad() {

        super.viewDidLoad()

        pickerView.frame = CGRect(x: 0, y: 30, width: self.view.frame.width, height: 300)

        pickerView.delegate = self

        pickerView.dataSource = self

        view.addSubview(pickerView)

        let tap = UITapGestureRecognizer(target: self, action: #selector(pickerTapped))

        tap.delegate = self

        pickerView.addGestureRecognizer(tap)

    }
    func numberOfComponents(in pickerView: UIPickerView) -> Int {
        return 1
    }

    func pickerView(_ pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int {
        return Array3.count
    }

    func pickerView(_ pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int) {
        print(row)
    }


    func pickerView(_ pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String? {

        if row == 0 {

            return Array3[row]
        }
        else {

            return "\u{2610} \(Array3[row])"
        }

    }


    @objc func pickerTapped(tapRecognizer: UITapGestureRecognizer) {
        if tapRecognizer.state == .ended {
            let rowHeight = self.pickerView.rowSize(forComponent: 0).height
            let selectedRowFrame = self.pickerView.bounds.insetBy(dx: 0, dy: (self.pickerView.frame.height - rowHeight) / 2)
            let userTappedOnSelectedRow = selectedRowFrame.contains(tapRecognizer.location(in: self.pickerView))
            if userTappedOnSelectedRow {
                let selectedRow = self.pickerView.selectedRow(inComponent: 0)
                pickerView(self.pickerView, didSelectRow: selectedRow, inComponent: 0)
            }
        }
    }


    func gestureRecognizer(_ gestureRecognizer: UIGestureRecognizer, shouldRecognizeSimultaneouslyWith otherGestureRecognizer: UIGestureRecognizer) -> Bool {
        return true
    }


}

在 UIPickerView 的单元格中使用 UIButton

Using UIButton within the cell of UIPickerView

uipickerview

ios

swift