Java 中不同类型类的相同方法

Question

我想对不同的 class 名称应用相同的方法：

    protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        InputStreamReader reader = new InputStreamReader(request.getInputStream());

        String l;
        StringBuilder sb1 = new StringBuilder();
        BufferedReader br = new BufferedReader(reader);
        while (( l = br.readLine()) != null) {
            sb1.append(l);
        }
        InputStream sb2 = new ByteArrayInputStream(sb1.toString().getBytes());
        sb1.toString();
        if(sb1.indexOf("CheckStatusRequest") != -1) {
            CheckStatusRequest checkStatusRequest = (CheckStatusRequest)testXmlToObject(sb2);
            System.out.println(checkStatusRequest.getClass());
        }else if(sb1.indexOf("CheckStatusResponse") != -1) {
            CheckStatusResponse checkStatusResponse = (CheckStatusResponse)testXmlToObject1(sb2);
            System.out.println(checkStatusResponse.getClass());
        }else if(sb1.indexOf("Consequences") != -1) {
            Consequences consequences = (Consequences)testXmlToObject2(sb2);
            System.out.println(consequences.getClass());
        }else if(sb1.indexOf("SubscriptionRequest") != -1) {
            SubscriptionRequest subscriptionRequest = (SubscriptionRequest)testXmlToObject3(sb2);
            System.out.println(subscriptionRequest.getClass());
        }else if(sb1.indexOf("TerminateSubscriptionRequest") != -1) {
            TerminateSubscriptionRequest terminateSubscriptionRequest = (TerminateSubscriptionRequest)testXmlToObject4(sb2);
            System.out.println(terminateSubscriptionRequest.getClass());
        }
    }
    public CheckStatusRequest testXmlToObject(InputStream line)  {
        try {
            JAXBContext jaxbContext = JAXBContext.newInstance(CheckStatusRequest.class);
            Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();
            CheckStatusRequest object = (CheckStatusRequest)jaxbUnmarshaller.unmarshal(line);
            return object;
        } catch (JAXBException e) {
            e.printStackTrace();
        }
        return null;
    }
    public CheckStatusResponse testXmlToObject1(InputStream line)  {
        try {
            JAXBContext jaxbContext = JAXBContext.newInstance(CheckStatusResponse.class);
            Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();
            CheckStatusResponse object = (CheckStatusResponse)jaxbUnmarshaller.unmarshal(line);
            return object;
        } catch (JAXBException e) {
            e.printStackTrace();
        }
        return null;
    }

所提供的解决方案有效，但我认为它实施不当。该方法对每个 class 的工作方式相同，变化只是返回对象的类型。基本上我对每个开关盒都有相同的方法。我尝试实现一个解决方案，其中方法被声明为 Object，当它被调用时进行了转换，但它没有按预期工作，我得到了 javax.xml.bind.UnmarshalException。你能简化这段代码吗？

Answer 1

您可以使用泛型来做到这一点。将您的 testXmlToObject 更改为：

public <T> T testXmlToObject(InputStream line, Class<T> classe)  {
    try {
        JAXBContext jaxbContext = JAXBContext.newInstance(classe);
        Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();
        T object = (T) jaxbUnmarshaller.unmarshal(line);
        return object;
    } catch (JAXBException e) {
        e.printStackTrace();
    }
    return null;
}

您将方法调用为 testXmlToObject(line, CheckStatusRequest.class)

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