Android SearchView 图标作为搜索按钮

Android SearchView icon as search button

我有 SearchView,通过在软键盘中输入 ENTER 可以很好地工作,我希望搜索输入中显示的搜索图标也可以用作搜索按钮,如下图所示:(这与样式无关,只是让放大镜图标可点击)

可能吗?

最后我可以通过 R.id.search_mag_icon 访问搜索视图中的默认 mag 图标并在其上设置 OnClickListener 来解决这个问题。它不是干净的代码,但至少它对我有用。

搜索activity:

protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_search);
    final Intent intent = getIntent();
    listView=(ListView)findViewById(R.id.simple_list);
    final SearchManager searchManager = (SearchManager) getSystemService(Context.SEARCH_SERVICE);
    searchView = (SearchView) findViewById(R.id.sv);
    searchView.setSearchableInfo(searchManager.getSearchableInfo(getComponentName()));
    ImageView magImage = (ImageView) findViewById(R.id.search_mag_icon);
    magImage.setImageResource(R.drawable.search);
    magImage.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View view) {
            Intent intentSelected = new Intent(SearchActivity2.this, SearchActivity2.class);
            intentSelected.setAction(Intent.ACTION_SEARCH);
            CharSequence query = searchView.getQuery();
            intentSelected.setData(Uri.parse( query.toString() ));
            intentSelected.putExtra("QUERY", query.toString());
            startActivity(intentSelected);
            hideKeyboard(SearchActivity2.this);
            finish();
        }
    });
    if (Intent.ACTION_SEARCH.equals(intent.getAction())) {
        String query = intent.getStringExtra(SearchManager.QUERY);
        String button_query = intent.getStringExtra("QUERY");
        if(query==null && button_query!=null)
            query = button_query;
        if(query!=null) {
            searchView.setQuery(query, false);
            headers = db.doSearch(query);
            dataModels = new ArrayList<>();
            dataModels = setListItems(headers);
            adapter = new CustomListAdapter(dataModels, getApplicationContext());
            listView.setAdapter(adapter);
            listView.setEmptyView(findViewById(R.id.iv_noresult));
        }
    }