Pytest:删除由测试函数创建的文件
Pytest: deleting files created by the tested function
我正在测试一个函数,作为其执行的一部分,pickle 对象。测试后,我想删除pickle文件
如果是测试本身保存文件,pytest
的“tmpdir”夹具似乎是解决方案。但是,由于正在测试的函数是保存文件的创建者,而不是测试,我不确定测试后清理文件的正确方法是什么。
在这种情况下,文件保存在包含测试的“tests”目录中运行。我能想到的唯一选择是在每次测试后从测试目录中删除所有 *.pkl pickle 文件。我想知道我是否缺少 pytest 可能提供的更优雅的解决方案。
清理作为使用 pytest
测试的函数的副作用而生成的任何文件的标准方法是什么?
可以使用monkeypatch文件打开功能查看是否写入了新文件。在列表中收集新文件。然后,浏览列表并删除文件。示例:
# spam.py
import pathlib
import numpy
def plain_write():
with open('spam.1', 'w') as f:
f.write('eggs')
def pathlib_write():
with pathlib.Path('spam.2').open('w') as f:
f.write('eggs')
def pathlib_write_text():
pathlib.Path('spam.3').write_text('eggs')
def pathlib_write_bytes():
pathlib.Path('spam.3').write_bytes(b'eggs')
def numpy_save():
numpy.save('spam.4', numpy.zeros([10, 10]))
def numpy_savetxt():
numpy.savetxt('spam.5', numpy.zeros([10, 10]))
测试
根据您测试的功能,monkeypatching builtins.open
可能还不够:例如,要清理使用 pathlib
编写的文件,您还需要 monkeypatch io.open
.
import builtins
import io
import os
import pytest
import spam
def patch_open(open_func, files):
def open_patched(path, mode='r', buffering=-1, encoding=None,
errors=None, newline=None, closefd=True,
opener=None):
if 'w' in mode and not os.path.isfile(path):
files.append(path)
return open_func(path, mode=mode, buffering=buffering,
encoding=encoding, errors=errors,
newline=newline, closefd=closefd,
opener=opener)
return open_patched
@pytest.fixture(autouse=True)
def cleanup_files(monkeypatch):
files = []
monkeypatch.setattr(builtins, 'open', patch_open(builtins.open, files))
monkeypatch.setattr(io, 'open', patch_open(io.open, files))
yield
for file in files:
os.remove(file)
def test_plain_write():
assert spam.plain_write() is None
def test_pathlib_write():
assert spam.pathlib_write() is None
def test_pathlib_write_text():
assert spam.pathlib_write_text() is None
def test_pathlib_write_bytes():
assert spam.pathlib_write_bytes() is None
def test_numpy_save():
assert spam.numpy_save() is None
def test_numpy_savetxt():
assert spam.numpy_savetxt() is None
我正在测试一个函数,作为其执行的一部分,pickle 对象。测试后,我想删除pickle文件
如果是测试本身保存文件,pytest
的“tmpdir”夹具似乎是解决方案。但是,由于正在测试的函数是保存文件的创建者,而不是测试,我不确定测试后清理文件的正确方法是什么。
在这种情况下,文件保存在包含测试的“tests”目录中运行。我能想到的唯一选择是在每次测试后从测试目录中删除所有 *.pkl pickle 文件。我想知道我是否缺少 pytest 可能提供的更优雅的解决方案。
清理作为使用 pytest
测试的函数的副作用而生成的任何文件的标准方法是什么?
可以使用monkeypatch文件打开功能查看是否写入了新文件。在列表中收集新文件。然后,浏览列表并删除文件。示例:
# spam.py
import pathlib
import numpy
def plain_write():
with open('spam.1', 'w') as f:
f.write('eggs')
def pathlib_write():
with pathlib.Path('spam.2').open('w') as f:
f.write('eggs')
def pathlib_write_text():
pathlib.Path('spam.3').write_text('eggs')
def pathlib_write_bytes():
pathlib.Path('spam.3').write_bytes(b'eggs')
def numpy_save():
numpy.save('spam.4', numpy.zeros([10, 10]))
def numpy_savetxt():
numpy.savetxt('spam.5', numpy.zeros([10, 10]))
测试
根据您测试的功能,monkeypatching builtins.open
可能还不够:例如,要清理使用 pathlib
编写的文件,您还需要 monkeypatch io.open
.
import builtins
import io
import os
import pytest
import spam
def patch_open(open_func, files):
def open_patched(path, mode='r', buffering=-1, encoding=None,
errors=None, newline=None, closefd=True,
opener=None):
if 'w' in mode and not os.path.isfile(path):
files.append(path)
return open_func(path, mode=mode, buffering=buffering,
encoding=encoding, errors=errors,
newline=newline, closefd=closefd,
opener=opener)
return open_patched
@pytest.fixture(autouse=True)
def cleanup_files(monkeypatch):
files = []
monkeypatch.setattr(builtins, 'open', patch_open(builtins.open, files))
monkeypatch.setattr(io, 'open', patch_open(io.open, files))
yield
for file in files:
os.remove(file)
def test_plain_write():
assert spam.plain_write() is None
def test_pathlib_write():
assert spam.pathlib_write() is None
def test_pathlib_write_text():
assert spam.pathlib_write_text() is None
def test_pathlib_write_bytes():
assert spam.pathlib_write_bytes() is None
def test_numpy_save():
assert spam.numpy_save() is None
def test_numpy_savetxt():
assert spam.numpy_savetxt() is None