Order MySQL 查询结果根据另一个 table 列以 DESC 顺序排列

Question

您好！

我的数据库中有两个 table

table（订单）

+--------+----+---------+
|  name  | id | user_id |
+--------+----+---------+
| order1 | 1  | 3       |
| order2 | 2  | 5       |
| order3 | 3  | 5       |
| order4 | 4  | 1       |
| order5 | 5  | 5       |
+--------+----+---------+

table (reported_orders)

+----------+---------+------------+
| order_id | user_id | time       |
+----------+---------+------------+
| 2        | 5       | 1535110516 |
+----------+---------+------------+
| 3        | 5       | 1535166516 |
+----------+---------+------------+
| 5        | 5       | 1535168651 |
+----------+---------+------------+

当我执行这个查询时

SELECT name,id FROM orders 
WHERE 
user_id=5
AND 
id IN (SELECT order_id FROM reported_orders WHERE user_id=5 ORDER BY time DESC )
LIMIT 0, 12

我得到结果

+--------+----+
|  name  | id |
+--------+----+
| order2 | 2  |
+--------+----+
| order3 | 3  |
+--------+----+
| order5 | 5  |
+--------+----+

但我想得到这样的结果

+--------+----+
|  name  | id |
+--------+----+
| order5 | 5  |
+--------+----+
| order3 | 3  |
+--------+----+
| order2 | 2  |
+--------+----+

我在查询中使用 ORDER BY time DESC 根据 reported_orders table 中的 time 降序获取结果，但事实并非如此工作

Answer 1

试试这个查询

SELECT a.name,a.id FROM orders a join reported_orders b on a.id=b.id where a.user_id=5 and b.user_id=5 order by a.id desc

Answer 2

这个查询对我有用。

SELECT orders.name,orders.id, reported_orders.time
FROM orders
INNER JOIN reported_orders
ON (orders.id=reported_orders.order_id) 
WHERE 
(orders.user_id=5 AND reported_orders.user_id=5) 
ORDER BY time DESC

Answer 3

这对我有用。

select o.name, o.id from orders o natural join reported_orders ro order by ro.time desc;

Order MySQL 查询结果根据另一个 table 列以 DESC 顺序排列

Order MySQL query results in DESC order according to another table column

mysql

sql

sql-order-by