将数据（标签）从 TableViewCell 传递到另一个 ViewController

Question

我想在单击单元格时将标签从 TableViewCell 传递到 ViewController。最后它应该像 twitter 一样，如果您单击带有标签的单元格，您将获得具有相同标签初始化的 detailViewController。我的代码不起作用，因为我只是从情节提要中获得了毯子标签...

import UIKit
import Firebase

class JobTableViewController: UIViewController, UITableViewDelegate, UITableViewDataSource {

@IBOutlet weak var tableView: UITableView!
var valueToPass:String!


 func tableView(_ tableView: UITableView, canEditRowAt indexPath: IndexPath) -> Bool {
    return true
}

 func numberOfSections(in tableView: UITableView) -> Int {
    return 1
}

 func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int{
    // Arvice return to count jobs
    return jobs.count
}

func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) {
    print("You selected cell #\(indexPath.row)!")

    // Get Cell Label
    let indexPath = tableView.indexPathForSelectedRow!
    let currentCell = tableView.cellForRow(at: indexPath)! as UITableViewCell

    let valueToPass = currentCell.textLabel?.text
    print("value: \(valueToPass)")

    performSegue(withIdentifier: "toDetails", sender: valueToPass)
}

 func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell{
    let cell = tableView.dequeueReusableCell(withIdentifier: "JobCell", for: indexPath) as! JobTableViewCell
    let job = jobs[indexPath.row]
    cell.job = job

    //spacing
    cell.contentView.backgroundColor = UIColor.clear

    let whiteRoundedView : UIView = UIView(frame: CGRect(x: 10, y: 8, width: self.view.frame.size.width - 20, height: 120))

    whiteRoundedView.layer.backgroundColor = CGColor(colorSpace: CGColorSpaceCreateDeviceRGB(), components: [0.36, 0.39, 0.40, 1.0])
    whiteRoundedView.layer.masksToBounds = false
    whiteRoundedView.layer.cornerRadius = 2.0
    whiteRoundedView.layer.shadowOffset = CGSize(width: 0, height: 0)
    whiteRoundedView.layer.shadowOpacity = 0.0

    cell.contentView.addSubview(whiteRoundedView)
    cell.contentView.sendSubview(toBack: whiteRoundedView)

    cell.emojiLabel.text = cell.emojiString

    return cell
}

override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
    if segue.identifier == "toDetails" {
        let destinationViewController = segue.destination as! JobDetailViewController
        destinationViewController.valueToPass = (sender as? String)!
    }
}

我的手机：

import UIKit
import Firebase

class JobTableViewCell: UITableViewCell {

@IBOutlet weak var jobLabel: UILabel!

var job: Job! {
    didSet {
        jobLabel.text = job.text
    }
}
}

Job.Swift:

import Foundation
import Firebase

class Job{

var text: String = ""
let ref: DatabaseReference!

init(text: String) {
    self.text = text
    ref = Database.database().reference().child("jobs").childByAutoId()
}

init(snapshot: DataSnapshot)
{
    ref = snapshot.ref
    if let value = snapshot.value as? [String : Any] {
        text = value["text"] as! String
    }
}

func save() {
    ref.setValue(toDictionary())
}

func toDictionary() -> [String : Any]
{
    return [
        "text" : text,
    ]
}
}

在我的 DestinationController 中：

import UIKit
import Firebase

class JobDetailViewController: UIViewController {

 @IBOutlet weak var jobDetail: RoundText!



var valueToPass: String = ""

override func viewDidAppear(_ animated: Bool) {
    super.viewDidAppear(animated)
    jobDetail.text = valueToPass
}

override func viewDidLoad() {
    super.viewDidLoad()

    title = "Jobinformation"
}
}

Answer 1

您不应该使用单元格来存储数据。您应该有一个数据模型来表示您在单元格中显示的数据，并且您应该使用所选单元格的 indexPath 来查找数据模型中的数据。

Answer 2

我会避免使用全局变量将数据传递到目标视图控制器。推迟查找，直到您准备好传递数据。

并且，避免使用强制展开，它会导致运行时崩溃。

改用这样的东西：

let segueIdentifier = "yourSegueIdentifer"
let labelDataSource: [String] = ["SomeText"]

func label(forIndexPath indexPath: IndexPath) -> String? {
    let index = indexPath.row
    guard labelDataSource.indices.contains(index) else { return nil }

    return labelDataSource[index]
}

func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) {
    performSegue(withIdentifier: segueIdentifier, sender: indexPath)
}

func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
    guard segue.identifier == segueIdentifier,
        let indexPath = sender as? IndexPath,
        let destinationViewController = segue.destination as? AnotherViewController else { return }

    destinationViewController.valuePassed = label(forIndexPath: indexPath)
}

Answer 3

快速解决方案：

改变 performSegue(withIdentifier: "yourSegueIdentifer", sender: self) 到 performSegue(withIdentifier: "yourSegueIdentifer", sender: valueToPass)

2.Your 准备 Segue 方法应该如下所示：

override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
     if segue.identifier == "yourSegueIdentifer" {
         let destinationViewController = segue.destination as!   AnotherViewController
             destinationViewController.valueToPass = sender as? String
    }
}

在 AnotherViewController 上创建 var valuteToPass: String = "" 并设置你的 label.text = valueToPass

但我认为你不应该使用 currentCell.textLabel.text 值，而是使用原始值。（比如如果您将 currentCell 设置为 cell.textLabel.cell = array[indexPath.row]，您的 valueToPass 应该是 valueToPass = array[indexPath.row]）

编辑：

您使用了 didDeselectRowAt 方法，而不是 didSelectRowAt。

将func tableView(_ tableView: UITableView, didDeselectRowAt indexPath: IndexPath)改为 func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath)

不要使用全局变量，在didSelectRowAt中创建。

    func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) {
    print("You selected cell #\(indexPath.row)!")

    // Get Cell Label
    let indexPath = tableView.indexPathForSelectedRow!
    let currentCell = tableView.cellForRow(at: indexPath)! as UITableViewCell

    let valueToPass = currentCell.textLabel?.text
    print("value: \(valuteToPass)")

    performSegue(withIdentifier: "toDetails", sender: valueToPass)
}

On DestinationController:

class DestinationController: UIViewController {

var valuteToPass: String = ""

  override func viewDidLoad() {
    super.viewDidLoad()
   jobLabel.text = valueToPass
   }

}

EDIT2

JobTableViewController

删除var valueToPass:String!

将let valueToPass = currentCell.textLabel?.text改为let valueToPass = jobs[indexPath.row].text 我检查了您代码中的此更改，这将起作用。

Answer 4

嗨，我不能发表评论，但我正在使用@Dris 回答，我一直收到这个错误，上面写着

Could not cast value of type 'UITableViewCell' (0x115464e18) to 'NSString' (0x10fa594c8).

SIGABRT 目标行 destinationViewController.valueToPass = (sender as? String)!

这是为什么？

这基本上是我的代码

 func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) {
        //  Determine what to do when a cell in a particular section is selected.
        print("did select:      \(indexPath.row)  ")

        // Get Cell Label
        let indexPath = tableView.indexPathForSelectedRow!
        let currentCell = tableView.cellForRow(at: indexPath)! as UITableViewCell

        valueToPass = currentCell.textLabel?.text
        print("valueToPass: \(String(describing: valueToPass))")
        performSegue(withIdentifier: "cellToView", sender: self)

    }

    func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {

        var cell:UITableViewCell?

        if tableView == self.tableView {

            let currentNotif = notificationList[indexPath.row]
            cell = tableView.dequeueReusableCell(withIdentifier: "cell", for: indexPath) as UITableViewCell
            cell?.textLabel?.text = currentNotif.notifType
            cell?.detailTextLabel?.text = "\(currentNotif.notifTime) \n\(currentNotif.notifContent)"
        }

        if tableView == self.tableViewAnnounce {

            let currentAnnounce = announcementList[indexPath.row]
            cell = tableView.dequeueReusableCell(withIdentifier: "cellAnn", for: indexPath) as UITableViewCell
            cell?.textLabel?.text = currentAnnounce.annouceType
            cell?.detailTextLabel?.text = "\(currentAnnounce.annouceTime) \n\(currentAnnounce.annouceContent)"
        }

        return cell!

    }

    override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
        if segue.identifier == "cellToView" {
            // perform custom segue operation.

            let destinationViewController = segue.destination as! ExtendedAnnouncementViewController
            destinationViewController.valueToPass = (sender as? String)!
        }
    }

将数据（标签）从 TableViewCell 传递到另一个 ViewController

Pass Data (Label) from TableViewCell to another ViewController

uilabel

ios

segue

swift