如何在 R 中一遍又一遍地 运行 欧氏距离

How to run euclidean distance over and over in R

如果我在 R 中有这样的文件

dput(filename)
structure(list(word = structure(c(2L, 1L), .Label = c("frq", 
"ocr_avg"), class = "factor"), abeja = c(98, 24), abeja.1 = c(26.666, 
3), abrigo = c(53.333, 6), abrigo.1 = c(50, 1), abrigo.2 = c(83.809, 
21), abrigo.3 = c(31.666, 6)), .Names = c("word", "abeja", "abeja.1", 
"abrigo", "abrigo.1", "abrigo.2", "abrigo.3"), row.names = c(NA, 
-2L), class = "data.frame")

#      word abeja abeja.1 abrigo abrigo.1 abrigo.2 abrigo.3
# 1 ocr_avg    98  26.666 53.333       50   83.809   31.666
# 2     frq    24   3.000  6.000        1   21.000    6.000

我想计算同名对之间的欧氏距离,例如在 (abeja & abeja.1) 之间,然后在 (abrigo & abrigo.1) 和 (abrigo & abrigo.2) 之间,以及(abrigo & abrigo.3)。但也在 (abrigo.1 & abrigo.2) 和 (abrigo.2 & abrigo.3) 之间。

有没有一种方法可以自动执行此操作,这样我就不必遍历每一对并在 R 中自己完成(这是一个相当大的文件)?

我自己的做法是这样的:

x <- filename$abeja
y <- filename$abeja.1 
dist(rbind(x,y))
mystring <- names(filename)

library(stringr)

# take the common patterns
strUniq <- unique(ifelse(str_detect(mystring, '\.'), 
                         str_sub(mystring, 1, str_locate(mystring, '\.')[,1] -1), 
                         mystring))
strUniq

# [1] "word"   "abeja"  "abrigo"

library(dplyr)
outp <- lapply(strUniq, function(x) select(filename, starts_with(x)))
outp

# [[1]]
#      word
# 1 ocr_avg
# 2     frq
#
# [[2]]
#   abeja abeja.1
# 1    98  26.666
# 2    24   3.000
#
# [[3]]
#   abrigo abrigo.1 abrigo.2 abrigo.3
# 1 53.333       50   83.809   31.666
# 2  6.000        1   21.000    6.000

lapply(outp, function(x) dist(t(x)))

# [[1]]
# dist(0)
#
# [[2]]
#            abeja
# abeja.1 74.36087
#
# [[3]]
#             abrigo  abrigo.1  abrigo.2
# abrigo.1  6.009067                    
# abrigo.2 33.967434 39.281656          
# abrigo.3 21.667000 19.003567 54.257649
#
# Warning message:
# In dist(t(x)) : NAs introduced by coercion

警告是由于 "word" 不包含数字。您可以先将其删除以避免警告。