为什么在 sub vb6 上传递参数时我检索错误?
why when pass arguments on a sub vb6 i retrieve error?
我写了这段代码:
Sub Insert_Pic_From_File2(PicPath As String, ByVal row As Integer, ByVal col As Integer)
Dim Pic As Picture, Sh As Shape, Rng As Range
Set Rng = Range.Cells(row, col)
Set Rng = Rng.MergeArea
With Rng
Set Sh = ActiveSheet.Shapes.AddPicture(Filename:=PicPath, linkToFile:=msoFalse, SaveWithDocument:=msoTrue, Left:=.Left, Top:=.Top, Width:=.Width, Height:=.Height)
Sh.LockAspectRatio = msoFalse
End With
Set Sh = Nothing
Set Rng = Nothing
End Sub
我从这一行调用它:
Insert_Pic_From_File2 ("D:\Area Open\ok.png", y, col_result)
y 和 col_result 都是整数。
当我按下进入程序时出现此错误(意大利语)
errore di compilazione:
Previsto: =
我认为是英文的:
compilation error:
needed: =
这是为什么?
如果我删除参数 y 和 col_result 似乎没问题,但没有参数。
非常感谢。
参数不要用括号括起来!它们仅在您使用冗余 'Call' 语句或用于返回值的函数时使用。
Insert_Pic_From_File2 "D:\Area Open\ok.png", y, col_result
应该没问题
我写了这段代码:
Sub Insert_Pic_From_File2(PicPath As String, ByVal row As Integer, ByVal col As Integer)
Dim Pic As Picture, Sh As Shape, Rng As Range
Set Rng = Range.Cells(row, col)
Set Rng = Rng.MergeArea
With Rng
Set Sh = ActiveSheet.Shapes.AddPicture(Filename:=PicPath, linkToFile:=msoFalse, SaveWithDocument:=msoTrue, Left:=.Left, Top:=.Top, Width:=.Width, Height:=.Height)
Sh.LockAspectRatio = msoFalse
End With
Set Sh = Nothing
Set Rng = Nothing
End Sub
我从这一行调用它:
Insert_Pic_From_File2 ("D:\Area Open\ok.png", y, col_result)
y 和 col_result 都是整数。
当我按下进入程序时出现此错误(意大利语)
errore di compilazione: Previsto: =
我认为是英文的:
compilation error: needed: =
这是为什么? 如果我删除参数 y 和 col_result 似乎没问题,但没有参数。
非常感谢。
参数不要用括号括起来!它们仅在您使用冗余 'Call' 语句或用于返回值的函数时使用。
Insert_Pic_From_File2 "D:\Area Open\ok.png", y, col_result
应该没问题