按组从递归事件中获取第一个日期

Question

我有以下table

ID  Date    Event
1   1990-01-01  1
1   1990-01-02  0
1   1990-01-03  1
2   1990-02-01  0
2   1990-02-02  1
2   1990-02-03  1

我想创建一个新列，它指示事件列为 1 的日期，例如：

ID  Date    Event   Fist Event date
1   1990-01-01  1   1990-01-01
1   1990-01-02  0   1990-01-01
1   1990-01-03  1   1990-01-01
2   1990-02-01  0   1990-02-02
2   1990-02-02  1   1990-02-02
2   1990-02-03  1   1990-02-02

Answer 1

我们可以尝试在这里使用MIN作为解析函数：

SELECT
    ID,
    Date,
    Event,
    MIN(CASE WHEN Event = 1 THEN Date END) OVER (PARTITION BY ID) AS First_Event_Date
FROM yourTable
ORDER BY
    ID,
    Date;

Demo

Answer 2

我会使用 outer apply :

select t.*, t1.Date as Fist_Event_date
from table t outer apply
     ( select top (1) t1.*
       from table t1 
       where t1.id = t.id and t1.event = 1
       order by t1.date 
     ) t1;

按组从递归事件中获取第一个日期

Taking the first date from a recursive event by group

sql

sql-server

partitioning

date

Demo