Google 使用 getLinkUrl(offset) 的 Apps 脚本问题

Question

我正在尝试了解如何在 Google Apps 脚本中使用 getLinkUrl(offset)。

我在此处找到了参考资料 - http://googlescriptreference.com/Document/Text/getlinkurloffset/，但我在网上找不到任何示例。

这个 GAS returns Paragraph在日志中

var paragraph = tableCell.getChild(0);

这个 GAS returns the text string in the paragraph 在日志中

var paragraphText = paragraph.getText();

这个 GAS returns NULL 在日志中

var paragraphText = paragraph.getLinkUrl();

这个 GAS returns 一个错误（找不到方法 getLinkUrl(number)。）并且日志中没有任何内容

var paragraphText = paragraph.getLinkUrl(2);

有人可以帮我了解如何使用 getLinkUrl(offset) 吗？

感谢您的帮助！

Answer 1

我试图直接在段落元素上使用 getLinkUrl(offset)（无效示例），但我需要在 getLinkUrl(offset) 之前使用 asText() 方法。

不工作

var paragraphText = paragraph.getLinkUrl(2);

工作

var paragraphText = paragraph.asText().getLinkUrl(2);

Google 文件 https://docs.google.com/document/d/136G549zIYPYBndXs70ZnR_wEFg5fPST9ZGsOlTgmDyM/edit

//Works if link is on a word or words instead of entire paragraph

function myFunctionP1() {
  //Find out how many Children there are
  var body = DocumentApp.getActiveDocument().getBody();
  Logger.log(body.getNumChildren());

  //Find out which child is table
  var table = body.getChild(2); //table is child#2
  Logger.log(table);

  //Find tableCell inside of table
  var tableCell = table.getChild(0).getChild(0); //tableCell
  Logger.log(tableCell)

  //Find paragraph inside of tableCell 
  //I think, but I'm not sure, the HYPERLINK will be found somewhere within the PARAGRAPH element. But I can't figure out how to get to it.
  var paragraph = tableCell.getChild(0); //paragraph element
  Logger.log(paragraph)

  //Get paragraph text 
  var paragraphText = paragraph.asText().getLinkUrl(2); //paragraph text
  Logger.log(paragraphText)


}



//Works if link is on entire paragraph
//Works if link is on entire paragraph
//Works if link is on entire paragraph
function myFunctionP2() {
  //Find out how many Children there are
  var body = DocumentApp.getActiveDocument().getBody();
  Logger.log(body.getNumChildren());

  //Find out which child is table
  var table = body.getChild(4); //table is child#2
  Logger.log(table);

  //Find tableCell inside of table
  var tableCell = table.getChild(0).getChild(0); //tableCell
  Logger.log(tableCell)

  //Find paragraph inside of tableCell 
  //I think, but I'm not sure, the HYPERLINK will be found somewhere within the PARAGRAPH element. But I can't figure out how to get to it.
  var paragraph = tableCell.getChild(0); //paragraph element
  Logger.log(paragraph)

  //Get paragraph text 
  var paragraphText = paragraph.getText(); //paragraph text
  Logger.log(paragraphText)

  //Get HYPERLIINK from paragraph text 
  var paragraphHYPERLINK = paragraph.getLinkUrl(); //paragraph text
  Logger.log(paragraphHYPERLINK)  

}

@Tanaike 帮助我找到了这个解决方案。 https://whosebug.com/users/7108653/tanaike

Google 使用 getLinkUrl(offset) 的 Apps 脚本问题

Google Apps Script problem using getLinkUrl(offset)

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