mysql 使用日期和状态字段的订购问题

mysql ordering question using date and status field

需要关于根据日期和状态订购一些 items/events 的最有效方式的想法。

目前我有以下查询。

select tevent.ID, tevent.ename, e_dates.edate, tevent.status, tevent.eactive  from tevent 
LEFT JOIN e_dates on tevent.ID=e_dates.EID) Where tevent.status <> 'delete' and tevent.eactive ='Y'  group by tevent.id order 
by (case when tevent.status = 'closed' and e_dates.edate >= curdate() then 0 
else 1 end), edates.edate desc

我用了一个案例,但它按状态排序,然后按日期排序,这让人很困惑。

下面是输出

+----+--------------+-----+-----------+
| ID |Edate           | Ename   | Status  | 
+----+--------------+-----+-----------+
|  2  | 2018-09-21    | Event2  | Closed  |
|  5  | 2018-09-15    | Event5  | Closed  | 
|  3  | 2018-12-12    | Event3  | Open    |
|  6  | 2018-10-25    | Event6  | Approved|
|  4  | 2018-10-25    | Event4  | Open    |
|  7  | 2018-10-15    | Event7  | Pending |
|  10 | 2018-10-01    | Event10 | Open    |
|  1  | 2018-09-30    | Event1  | Open    |
|  4  | 2018-09-30    | Event4  | Open    |
|  8  | 2018-09-01    | Event8  | Closed  |
|  11 | 2018-08-25    | Event11 | Closed  |
+----+--------------+-----+-----------+

已编辑: 我想要完成的是列出事件日期早于事件日期的已关闭事件。 IE(ID 2 和 ID 5)

但是想要按ASC的时间顺序列出OPEN、APPROVED、PENDING的事件状态。

以及事件日期 (edate) 晚于底部列出的当前日期 (now()) 的已结束事件

例如:

   +----+--------------+-----+-----------+
    | ID |Edate           | Ename   | Status  | 
    +----+--------------+-----+-----------+
    |  2  | 2018-09-21    | Event2  | Closed  |
    |  5  | 2018-09-15    | Event5  | Closed  | 
    |  1  | 2018-09-30    | Event1  | Open    |*
    |  4  | 2018-09-30    | Event4  | Open    |*
    |  10 | 2018-10-01    | Event10 | Open    |*
    |  7  | 2018-10-15    | Event7  | Pending |*
    |  4  | 2018-10-25    | Event4  | Open    |*
    |  6  | 2018-10-25    | Event6  | Approved|*
    |  3  | 2018-12-12    | Event3  | Open    |*
    |  11 | 2018-08-25    | Event11 | Closed  |    
    |  8  | 2018-09-01    | Event8  | Closed  |
    +----+--------------+-----+-----------+

我认为你几乎是对的。您的案例陈述中需要三个选项 - 0 表示顶部的所有封闭项,2 表示底部的所有封闭项,1 表示中间的所有其他项。然后删除日期上的 desc 以获得每个部分内升序的日期,因此您的 order by 子句应该看起来像

order by (
    case when tevent.status = 'closed' and e_dates.edate >= curdate() then 0 
    when tevent.status = 'closed' and e_dates.edate < curdate() then 2
    else 1 end
), edates.edate

或者你也可以这样写

order by (
    case when tevent.status = 'closed' 
        then case when e_dates.edate >= curdate() then 0 else 2 end
    else 1 end
), edates.edate