为什么我的表达式不能处理多行？
Why doesn't my expression handle multiline?
输入
下面这段代码是c++中对话框的资源声明
LTEXT "Width",IDC_WIDTH_TEXT,203,74,22,10
EDITTEXT IDC_WIDTH_IN,244,73,57,12,ES_AUTOHSCROLL | WS_GROUP
CONTROL "Manually scale instances and paper",IDC_RAD_PSCALE_KEYIN,
"Button",BS_AUTORADIOBUTTON | WS_GROUP | WS_TABSTOP,15,89,132,10
CONTROL "Keep drawing instance scale 1.0",IDC_RAD_PSCALE_AUTO,
"Button",BS_AUTORADIOBUTTON,15,104,123,10
CONTROL "Keep drawing paper scale 1.0",IDC_RAD_ISCALE_AUTO,
"Button",BS_AUTORADIOBUTTON,15,119,118,10
期望的输出
我想使用 Visual Studio 2010 Find/Replace 对话框来处理该信息。
我想从该声明中提取所有 ID 并有一个清除列表，因此使用该输入我想获得以下输出：
IDC_WIDTH_TEXT
IDC_WIDTH_IN
IDC_RAD_PSCALE_KEYIN
IDC_RAD_PSCALE_AUTO
IDC_RAD_ISCALE_AUTO
1°尝试
如果我使用 .*{IDC:i*}.* 那么我可以获得所有这些 ID，但我不会从中获取多行部分，如果我将 </code> 放在替换字段中，这就是输出：</p>
<pre><code>IDC_WIDTH_TEXT
IDC_WIDTH_IN
IDC_RAD_PSCALE_KEYIN
"Button",BS_AUTORADIOBUTTON | WS_GROUP | WS_TABSTOP,15,89,132,10
IDC_RAD_PSCALE_AUTO
"Button",BS_AUTORADIOBUTTON,15,104,123,10
IDC_RAD_ISCALE_AUTO
"Button",BS_AUTORADIOBUTTON,15,119,118,10
2°尝试
如果我改用 .*{IDC:i*}.*\n.*~({IDC:i*})，我会得到以下缺少 IDC_WIDTH_IN
的输出
IDC_WIDTH_TEXT
IDC_RAD_PSCALE_KEYIN
IDC_RAD_PSCALE_AUTO
IDC_RAD_ISCALE_AUTO
如何才能正确获得我想要的输出？
没有 language/program-specific dotall 修饰符，点通常匹配除换行符之外的所有内容。
试试这个 (demo)。请注意，我的演示中的替换将 \n 附加到末尾，否则它也会处理换行符并将所有内容放在一行中。
^.*?(IDC\w*)[\s\S]*?(?:$|(,\n.*$))(\n|$)
解释：
^ # Anchors to the beginning to the string.
.*? # . denotes any single character, except for newline
# * repeats zero or more times
# ? as few times as possible
( # Opens CG1
IDC # Literal IDC
\w* # Token: \w (a-z, A-Z, 0-9, _)
# * repeats zero or more times
) # Closes CG1
[\s\S]*? # Character class (any of the characters within)
# A character class and negated character class, common expression meaning any character.
(?: # Opens NCG
$ # Anchors to the end to the string.
| # Alternation (NCG)
( # Opens CG2
, # Literal ,
\n # Token: \n (newline)
.* # . denotes any single character, except for newline
$ # Anchors to the end to the string.
) # Closes CG2
) # Closes NCG
( # Opens CG3
\n # Token: \n (newline)
| # Alternation (CG3)
$ # Anchors to the end to the string.
) # Closes CG3
输入
下面这段代码是c++中对话框的资源声明
LTEXT "Width",IDC_WIDTH_TEXT,203,74,22,10
EDITTEXT IDC_WIDTH_IN,244,73,57,12,ES_AUTOHSCROLL | WS_GROUP
CONTROL "Manually scale instances and paper",IDC_RAD_PSCALE_KEYIN,
"Button",BS_AUTORADIOBUTTON | WS_GROUP | WS_TABSTOP,15,89,132,10
CONTROL "Keep drawing instance scale 1.0",IDC_RAD_PSCALE_AUTO,
"Button",BS_AUTORADIOBUTTON,15,104,123,10
CONTROL "Keep drawing paper scale 1.0",IDC_RAD_ISCALE_AUTO,
"Button",BS_AUTORADIOBUTTON,15,119,118,10
期望的输出
我想使用 Visual Studio 2010 Find/Replace 对话框来处理该信息。
我想从该声明中提取所有 ID 并有一个清除列表，因此使用该输入我想获得以下输出：
IDC_WIDTH_TEXT
IDC_WIDTH_IN
IDC_RAD_PSCALE_KEYIN
IDC_RAD_PSCALE_AUTO
IDC_RAD_ISCALE_AUTO
1°尝试
如果我使用 .*{IDC:i*}.* 那么我可以获得所有这些 ID，但我不会从中获取多行部分，如果我将 </code> 放在替换字段中，这就是输出：</p>
<pre><code>IDC_WIDTH_TEXT
IDC_WIDTH_IN
IDC_RAD_PSCALE_KEYIN
"Button",BS_AUTORADIOBUTTON | WS_GROUP | WS_TABSTOP,15,89,132,10
IDC_RAD_PSCALE_AUTO
"Button",BS_AUTORADIOBUTTON,15,104,123,10
IDC_RAD_ISCALE_AUTO
"Button",BS_AUTORADIOBUTTON,15,119,118,10
2°尝试
如果我改用 .*{IDC:i*}.*\n.*~({IDC:i*})，我会得到以下缺少 IDC_WIDTH_IN
IDC_WIDTH_TEXT
IDC_RAD_PSCALE_KEYIN
IDC_RAD_PSCALE_AUTO
IDC_RAD_ISCALE_AUTO
如何才能正确获得我想要的输出？
没有 language/program-specific dotall 修饰符，点通常匹配除换行符之外的所有内容。
试试这个 (demo)。请注意，我的演示中的替换将 \n 附加到末尾，否则它也会处理换行符并将所有内容放在一行中。
^.*?(IDC\w*)[\s\S]*?(?:$|(,\n.*$))(\n|$)
解释：
^ # Anchors to the beginning to the string.
.*? # . denotes any single character, except for newline
# * repeats zero or more times
# ? as few times as possible
( # Opens CG1
IDC # Literal IDC
\w* # Token: \w (a-z, A-Z, 0-9, _)
# * repeats zero or more times
) # Closes CG1
[\s\S]*? # Character class (any of the characters within)
# A character class and negated character class, common expression meaning any character.
(?: # Opens NCG
$ # Anchors to the end to the string.
| # Alternation (NCG)
( # Opens CG2
, # Literal ,
\n # Token: \n (newline)
.* # . denotes any single character, except for newline
$ # Anchors to the end to the string.
) # Closes CG2
) # Closes NCG
( # Opens CG3
\n # Token: \n (newline)
| # Alternation (CG3)
$ # Anchors to the end to the string.
) # Closes CG3