SQL 服务器 (2008) UNION with ROLL UP
SQL Server (2008) UNION with ROLL UP
我有一个费用报告应用程序,可以将费用费用和帐号合二为一 table,但是给定的费用可以拆分为一部分记入一个 GL 帐户,其余部分记入另一个帐户。为了适应成本拆分,费用 table 有两对金额和帐号列,供数据输入过程使用。像这样:
create table Expenses (expheaderid int, explineid int, amount_split1 decimal(5,2),
account int, amount_split2 decimal(5,2), account2 int);
insert Expenses values (57, 11, 47.35, 80400, 0, 0);
insert Expenses values (57, 12, 163.31, 80440, 0, 0);
insert Expenses values (57, 13, 30, 80401, 5.90, 70410);
insert Expenses values (57, 14, 35, 80440, 0, 0);
insert Expenses values (57, 15, 45.15, 80440, 0, 0);
insert Expenses values (57, 16, 145.87, 80400, 68.14, 80400);
insert Expenses values (57, 17, 67.35, 80870, 0, 0);
insert Expenses values (57, 18, 105, 80402, 34.50, 80440);
我需要汇总(GROUP BY)来自相同帐户代码的金额,但汇总必须发生在两对金额和帐号列之间 - (amount_split1 & 帐户)第一对或 (amount_split2 & account 2) 第二列对。所以我的 table 看起来像这样:
expheaderid explineid amount_split1 account amount_split2 account2
----------- --------- ------------- ------- ------------- --------
57 11 47.35 80400 0.00 0
57 12 163.31 80440 0.00 0
57 13 30.00 80401 5.90 70410
57 14 35.00 80440 0.00 0
57 15 45.15 80440 0.00 0
57 16 145.87 80400 68.14 80400
57 17 67.35 80870 0 0
57 18 105.00 80402 34.50 80440
我想将 amount_split1 成本与 amount_split2 成本联合起来按帐号对它们进行分组。
结果应该是这样的,从 account 列和 account2 列中的 GL accounts 收集
AggTotal GLAccount
-------- ---------
261.36 80400
30.00 80401
105.00 80402
277.96 80440
67.35 80470
and probably...
0.00 0 -which I don't care about.
我根本不擅长复合查询。我试图在这样的一个语句中使用 UNION 和 GROUP:
select sum(AggTotal), GLAccount from
((select amount_split1 as AggTotal, account as GLAccount from Expenses)
union all
(select amount_split2 as AggTotal, account2 as GLAccount from Expenses))as t
where Expenses.expheaderid=57 group by GLAccount;
但是expheaderid列不会绑定。此数据是更大数据集的一部分,因此 expheaderid 上的 WHERE 子句必须起作用。
感谢您的帮助。
你试过分块做吗?
试试这样的 CTE
WITH C AS(
(select amount_split1 as AggTotal, account as GLAccount,expheaderid from Expenses)
union all
(select amount_split2 as AggTotal, account2 as GLAccount,expheaderid from Expenses)
)SELECT sum(AggTotal) AS SUMAVGTOTAL, GLAccount
FROM C
WHERE expheaderid=57
GROUP BY GLAccount
或者这个
select sum(AggTotal), GLAccount from
((select amount_split1 as AggTotal, account as GLAccount from Expenses where expheaderid=57)
union all
(select amount_split2 as AggTotal, account2 as GLAccount from Expenses where expheaderid=57))as t
group by GLAccount;
将你的 expheaderid=57 添加到 union 的每个部分
您也可以使用诱人的## 来做同样的事情。
如果它不起作用告诉我
您可以尝试在子查询中 UNION ALL
,然后添加 expheaderid
列,因为您需要在子查询中的 where
上使用它,最终执行 SUM
.
查询 1:
SELECT SUM(AggTotal) AggTotal,GLAccount
FROM (
select amount_split1 as AggTotal,
account as GLAccount,
expheaderid -- <-- add this column
from Expenses
union all
select
amount_split2 as AggTotal,
account2 as GLAccount ,
expheaderid
from Expenses
) t1
where expheaderid = 57
GROUP BY GLAccount
| AggTotal | GLAccount |
|----------|-----------|
| 0 | 0 |
| 5.9 | 70410 |
| 261.36 | 80400 |
| 30 | 80401 |
| 105 | 80402 |
| 277.96 | 80440 |
| 67.35 | 80870 |
我有一个费用报告应用程序,可以将费用费用和帐号合二为一 table,但是给定的费用可以拆分为一部分记入一个 GL 帐户,其余部分记入另一个帐户。为了适应成本拆分,费用 table 有两对金额和帐号列,供数据输入过程使用。像这样:
create table Expenses (expheaderid int, explineid int, amount_split1 decimal(5,2),
account int, amount_split2 decimal(5,2), account2 int);
insert Expenses values (57, 11, 47.35, 80400, 0, 0);
insert Expenses values (57, 12, 163.31, 80440, 0, 0);
insert Expenses values (57, 13, 30, 80401, 5.90, 70410);
insert Expenses values (57, 14, 35, 80440, 0, 0);
insert Expenses values (57, 15, 45.15, 80440, 0, 0);
insert Expenses values (57, 16, 145.87, 80400, 68.14, 80400);
insert Expenses values (57, 17, 67.35, 80870, 0, 0);
insert Expenses values (57, 18, 105, 80402, 34.50, 80440);
我需要汇总(GROUP BY)来自相同帐户代码的金额,但汇总必须发生在两对金额和帐号列之间 - (amount_split1 & 帐户)第一对或 (amount_split2 & account 2) 第二列对。所以我的 table 看起来像这样:
expheaderid explineid amount_split1 account amount_split2 account2
----------- --------- ------------- ------- ------------- --------
57 11 47.35 80400 0.00 0
57 12 163.31 80440 0.00 0
57 13 30.00 80401 5.90 70410
57 14 35.00 80440 0.00 0
57 15 45.15 80440 0.00 0
57 16 145.87 80400 68.14 80400
57 17 67.35 80870 0 0
57 18 105.00 80402 34.50 80440
我想将 amount_split1 成本与 amount_split2 成本联合起来按帐号对它们进行分组。
结果应该是这样的,从 account 列和 account2 列中的 GL accounts 收集
AggTotal GLAccount
-------- ---------
261.36 80400
30.00 80401
105.00 80402
277.96 80440
67.35 80470
and probably...
0.00 0 -which I don't care about.
我根本不擅长复合查询。我试图在这样的一个语句中使用 UNION 和 GROUP:
select sum(AggTotal), GLAccount from
((select amount_split1 as AggTotal, account as GLAccount from Expenses)
union all
(select amount_split2 as AggTotal, account2 as GLAccount from Expenses))as t
where Expenses.expheaderid=57 group by GLAccount;
但是expheaderid列不会绑定。此数据是更大数据集的一部分,因此 expheaderid 上的 WHERE 子句必须起作用。
感谢您的帮助。
你试过分块做吗? 试试这样的 CTE
WITH C AS(
(select amount_split1 as AggTotal, account as GLAccount,expheaderid from Expenses)
union all
(select amount_split2 as AggTotal, account2 as GLAccount,expheaderid from Expenses)
)SELECT sum(AggTotal) AS SUMAVGTOTAL, GLAccount
FROM C
WHERE expheaderid=57
GROUP BY GLAccount
或者这个
select sum(AggTotal), GLAccount from
((select amount_split1 as AggTotal, account as GLAccount from Expenses where expheaderid=57)
union all
(select amount_split2 as AggTotal, account2 as GLAccount from Expenses where expheaderid=57))as t
group by GLAccount;
将你的 expheaderid=57 添加到 union 的每个部分
您也可以使用诱人的## 来做同样的事情。 如果它不起作用告诉我
您可以尝试在子查询中 UNION ALL
,然后添加 expheaderid
列,因为您需要在子查询中的 where
上使用它,最终执行 SUM
.
查询 1:
SELECT SUM(AggTotal) AggTotal,GLAccount
FROM (
select amount_split1 as AggTotal,
account as GLAccount,
expheaderid -- <-- add this column
from Expenses
union all
select
amount_split2 as AggTotal,
account2 as GLAccount ,
expheaderid
from Expenses
) t1
where expheaderid = 57
GROUP BY GLAccount
| AggTotal | GLAccount |
|----------|-----------|
| 0 | 0 |
| 5.9 | 70410 |
| 261.36 | 80400 |
| 30 | 80401 |
| 105 | 80402 |
| 277.96 | 80440 |
| 67.35 | 80870 |