如何从日期列中删除时间并在每个日期拥有唯一的用户数

Question

我遇到了一个事件 table，其中包含太多列。我想查询 3 个列，DateTimeResolved、Team 和 Individual。首先，我想放弃 DateTimeResolved 列中的时间，只留下一个日期。然后我想知道自 2017 年 4 月以来每个团队有多少人（唯一计数）解决了事件。

这可以做到吗？

我有以下查询，但它们显然需要调整，因为它们没有给我想要的最终结果。

select stat_datetimeresolved, resolvedbyteam, resolvedby 
from [dbo].[Incident]
where Stat_DateTimeResolved is not null
and Stat_DateTimeResolved >= '2017-04-01 00:00:00'
order by Stat_DateTimeResolved asc


select CAST(stat_datetimeresolved as date),
COUNT(resolvedby)
from [dbo].[Incident]
group by CAST(Stat_DateTimeResolved as DATE)
order by CAST(stat_datetimeresolved as DATE) asc

Answer 1

您在此处的问题中有多个不兼容的请求。我想你追求的其实是：

自 2017 年 4 月以来，每个团队每天有多少人下定决心？

为此，您只需要 return 一个包含解决日期、个人所属团队以及实际做出解决方案的人的唯一列表，然后汇总：

with r as
(
    select distinct cast(stat_datetimeresolved as date) as DateResolved
                   ,ResolvedByTeam
                   ,ResolvedBy
    from [dbo].[Incident]
    where Stat_DateTimeResolved >= '20170401'  -- NULL check is redundant if you are filtering for a value
)
select DateResolved
      ,ResolvedByTeam
      ,count(ResolvedBy) as NumIndividualsMakingResolutions
from r
group by DateResolved
        ,ResolvedByTeam
order by DateResolved
        ,ResolvedByTeam;

Answer 2

你很亲密；您可以将 DISTINCT 关键字添加到 COUNT 以按天获取唯一团队成员的数量。

SELECT CAST(stat_datetimeresolved as date) as DateResolved
, ResolvedByTeam
, COUNT(DISTINCT resolvedby) as ResolvedByCnt
FROM [dbo].[Incident]
 WHERE Stat_DateTimeResolved >= '20170401'
GROUP BY CAST(Stat_DateTimeResolved as DATE), ResolvedByTeam
ORDER BY CAST(stat_datetimeresolved as DATE) asc, ResolvedByTeam

如何从日期列中删除时间并在每个日期拥有唯一的用户数

how to strip the time from a date column and have a unique count of users per date

datetime

sql-server-2014

自 2017 年 4 月以来，每个团队每天有多少人下定决心？