Python 如何在 1 到 6 之间随机抽取 2 个随机数

Question

我正在尝试制作这段代码然后我以随机顺序打印出 3 行数字 1 - 6，这很好。但是有没有办法让它打印 1 到 6 之间的数字对，而不是随机打印 6 个数字？示例：它当前打印：

 [1, 6, 5, 3, 4, 2]

需要打印：

[1, 6]
[5, 3]
[4, 2]

代码：

@bot.command()
async def teams(ctx, players):
    await ctx.send("Ido - 1: Yona - 2: Noam - 3: Gil - 4: Liel - 5: Yuval - 6:")
    await ctx.send('Calculating...')
    from random import shuffle
    sequence1 = [i for i in range(1, int(players)+1)]
    shuffle(sequence1)
    await ctx.send(sequence1)

    sequence2 = [i for i in range(1, int(players)+1)]
    shuffle(sequence2)
    await ctx.send(sequence2)

    sequence3 = [i for i in range(1, int(players) + 1)]
    shuffle(sequence3)
    await ctx.send(sequence3)

Answer 1

使用列表理解，这也将通过在末尾创建一个单一的组来处理不均匀的列表。

l = [1, 6, 5, 3, 4, 2]
n = 2
lst = [l[i:i + n] for i in range(0, len(l), n)]
for i in lst:
    print(i)

[1, 6]
[5, 3]
[4, 2]

Python 如何在 1 到 6 之间随机抽取 2 个随机数

Python how to randomly pick 2 randoms between 1 and 6

python

python-3.x

discord.py

discord.py-rewrite