Python: 子 class 属性未粘附

Question

我正在尝试与 classes 一起工作，但对他们来说还是新手。我对如何从父 class 继承属性以及为子 class 初始化新属性感到困惑。我发现父属性是可调用的，但我定义的子属性不是。请在下面查看我的代码：

import random
import hashlib
import base64
import requests
import json
import urllib3
import getpass

# Disable warning re: server certificate checking turned off
urllib3.disable_warnings(urllib3.exceptions.InsecureRequestWarning)

class vsa:
    def __init__(self):
        self.vsa_token = self.api_authentication()
        self.headers = {'Authorization': "Bearer " + self.vsa_token}
        self.url = "example.com"

    def api_authentication(self):
        while True: 
            username = input("Enter your username: ")
            password = getpass.getpass("Enter your password: ")

            vsa = "example.com/api/auth"
            random_integer = random.randint(5000, 50000)
            CoveredSHA256HashTemp_object = hashlib.sha256()
            CoveredSHA256HashTemp_object.update(('%s%s' % (password, username)).encode('utf-8'))
            CoveredSHA256HashTemp = CoveredSHA256HashTemp_object.hexdigest()
            CoveredSHA256Hash_object = hashlib.sha256()
            CoveredSHA256Hash_object.update(('%s%d' % (CoveredSHA256HashTemp, random_integer)).encode('utf-8'))
            CoveredSHA256Hash = CoveredSHA256Hash_object.hexdigest()
            CoveredSHA1HashTemp_object = hashlib.sha1()
            CoveredSHA1HashTemp_object.update(('%s%s' % (password, username)).encode('utf-8'))
            CoveredSHA1HashTemp = CoveredSHA1HashTemp_object.hexdigest()
            CoveredSHA1Hash_object = hashlib.sha1()
            CoveredSHA1Hash_object.update(('%s%d' % (CoveredSHA1HashTemp, random_integer)).encode('utf-8'))
            CoveredSHA1Hash = CoveredSHA1Hash_object.hexdigest()
            auth = "user=%s, pass2=%s, pass1=%s, rpass2=%s, rpass1=%s, rand2=%d, twofapass=:undefined" % (username, CoveredSHA256Hash, CoveredSHA1Hash, CoveredSHA1Hash, CoveredSHA256Hash, random_integer)
            encode = base64.urlsafe_b64encode(('%s' % auth).encode('UTF-8')).decode('ascii')
            headers = { 'Authorization' : 'Basic %s' %  encode }
            r = requests.get(vsa, headers=headers, verify=False)

            data = r.text

            parsed_data = json.loads(data)
            if parsed_data['ResponseCode'] == 0:
                print("\nVSA token successfully retrieved\n")
                vsa_token = parsed_data['Result']['Token']
                return vsa_token
            else:
                print("Unauthorized")


    def get_vsa_token(self):
        return self.vsa_token

class agents(vsa):

    def __init___(self):
        vsa.__init__(self)
        self.call = "/asetmgmt/agents"

    def get_agents(self):
        list_agents = []
        r = requests.get(self.url + self.call, headers=self.headers, verify=False)
        data = r.text
        parsed_data = json.loads(data)
        all_agents = parsed_data
        for agents in all_agents['Result']:
                    list_agents.append((agents['AgentName']))
        return list_agents

session = agents()
print(session.call)

最终命令 - print(session.call) 给出以下输出：

AttributeError: 'agents' object has no attribute 'call'

但是，我已经（我认为是）这段代码的相关部分和运行它通过 PythonTutor，看到 call 属性正在被初始化？

PythonTutor Link to Code

我对自己做错了什么感到茫然。我发现我可以在 agents.__init__(self) 块之外初始化变量，这工作正常：

class agents(vsa):

    call = "/assetmgmt/agents"

    def __init___(self):
        vsa.__init__(self)

但现在困扰我的是一些概念性的东西。我构建这个的方式很愚蠢吗？你会如何更好地构建？

感谢您提供的任何见解。

Answer 1

感谢@Blckknght 为我提供了解决方案，修复了我的错别字...

__init___ != __init__

被忽视的总是简单的事情。我很高兴我在这里发布了一个问题，而不是不断地调试和尝试其他解决方案（我做了大概 30 分钟）。

谢谢！

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