通过列表过滤一列字符串而不做完全匹配

Question

我有一个如下所示的 pandas 数据框：-

    Tweets
0   RT @cizzorz: THE CHILLER TRAP *TEMPLE RUN* OBS...
1   Disco Domination receives a change in order to...
2   It's time for the Week 3 #FallSkirmish Trials!...
3   Dance your way to victory in the new Disco Dom...
4   Patch v6.02 is available now with a return fro...
5   Downtime for patch v6.02 has begun. Find out a...
6   ⛏️... soon
7   Launch into patch v6.02 Wednesday, October 10!...
8   Righteous Fury.\n\nThe Wukong and Dark Vanguar...
9   RT @wbgames: WB Games is happy to bring @Fortn...

我还有一个列表假设如下：-

my_list = ['Launch', 'Dance', 'Issue']

使用下面的命令过滤掉数据框：-

 ndata = data[data['Tweets'].str.contains( "|".join(my_list), regex=True)].reset_index(drop=True)

如果我有

，过滤器将无法正常工作

    Working        Not Working
    Launch        'launch' , 'launch,' , 'Launch,' ,'LAUNCH','@launch'

预期的输出应该是下面任何一个词的句子

'launch' , 'launch,' , 'Launch,' ,'LAUNCH','@launch'

Answer 1

您需要确保 contains 忽略大小写：

import re

.
.
.

ndata = data[data['Tweets'].str.contains("|".join(my_list), regex=True,                          
                                         flags=re.IGNORECASE)].reset_index(drop=True)
#                                        ^^^^^^^^^^^^^^^^^^^

通过列表过滤一列字符串而不做完全匹配

filtering a column of string by list without doing exact match

python

dataframe

python-3.x

pandas

data-cleaning