通过 Beautifulsoup 在 python 中提取对象的描述

Question

我想提取图附近的描述（从"Figurine model"到"Stay Tuned :)"的那个）并将其存储到变量information到BeautifulSoup中。我该怎么做？这是我的代码，但我不知道如何继续：

from bs4 import BeautifulSoup
response = requests.get('https://www.myminifactory.com/object/3d-print-the-little-prince-4707')
soup = BeautifulSoup(response.text, "lxml")
information =

我在页面下方向您展示了我要从中提取对象描述的位置。先感谢您！

Answer 1

这对我有用，因为我使用 break 语句的方式而不是脚本。但是脚本有效。

from urllib.request import urlopen
from bs4 import BeautifulSoup as BS

url = r'https://www.myminifactory.com/object/3d-print-the-little-prince-4707'

html = urlopen(url).read()
Soup = BS(html,"lxml")
Desc = Soup.find('div',{'class':'short-text text-auto-link'}).text
description = ''
for line in Desc.split('\n'):
    if line.strip() == '_________________________________________________________________________':
        break
    if line.strip():
        description += line.strip()
print(description)

Answer 2

找到父标签然后寻找<p>，过滤空格和____

parent = soup.find("div",class_="row container-info-obj margin-t-10")
result = [" ".join(p.text.split()) for p in parent.find_all("p") if p.text.strip() and not "_"*8  in p.text]
#youtube_v = parent.find("iframe")["src"]
print(result)

通过 Beautifulsoup 在 python 中提取对象的描述

Extract an object's description through Beautifulsoup in python

html

python

extract

beautifulsoup

web-scraping