从 curl 到 pycurl - 如何制作 mutli-part post - 使用 curl，使用 pycurl 时出现 422 失败

Question

我有一个 cURL post 可以正常工作：

curl -X POST http://some-server.com/working_endpoint-F "package[distro_version_id]=1" -F "package[package_file]=@/tmp/myfile.bin"

当我尝试将其转换为 pycurl 时，请求失败并显示 422 Unprocessable Entity，服务器显示 package[package_file] "must be multipart form-data"

import pycurl
c = pycurl.Curl()
c.setopt(pycurl.VERBOSE, 1)
c.setopt(c.URL, 'http://some-server.com/working_endpoint')
c.setopt(c.POST, 1)
c.setopt(c.HTTPPOST, [('package[package_file]', (c.FORM_FILE, '/tmp/myfile.bin'))])
c.setopt(c.HTTPPOST, [('package[distro_version_id]',  '1')])
c.perform()

确实 headers 看起来只有一个参数进入了多部分形式

Content-Length: 165 Content-Type: multipart/form-data; boundary=------------------------dee07c93fad525aa

我做错了什么？

Answer 1

想通了。

而不是单独的 setopt 调用表单数据，像这样

c.setopt(c.HTTPPOST, [('package[package_file]', (c.FORM_FILE, '/tmp/myfile.bin'))])
c.setopt(c.HTTPPOST, [('package[distro_version_id]',  '1')])

它需要在一个单一的结构中，像这样

data = [
    ('package[distro_version_id]', '1'),
    ('package[package_file]', (
        c.FORM_FILE, '/tmp/myfile.bin,
        c.FORM_CONTENTTYPE, 'application/octet-stream'
    ))]
c.setopt(c.HTTPPOST, data)

从 curl 到 pycurl - 如何制作 mutli-part post - 使用 curl，使用 pycurl 时出现 422 失败

from curl to pycurl - how to make a mutli-part post - works with curl, fails with 422 with pycurl

python

curl

http-post

pycurl