Swagger 不为 IActionResult 包装的对象生成模型
Swagger not generating model for object wrapped by IActionResult
使用以下代码,Swaggger UI 显示 RegistrationInfo 模型但不显示 UserInfo 模型。
我如何生成它?
[Produces("application/json")]
[Authorize(AuthenticationSchemes = JwtBearerDefaults.AuthenticationScheme)]
[Route("api")]
public class UserController : Controller
{
[HttpPost("RegisterUser")]
public IActionResult RegisterUser([FromBody] RegistrationInfo info)
{
UserInfo data = UserData.RegisterUser(info);
if (data != null)
{
return Ok(data);
}
return NoContent();
}
}
您需要使用 ProducesResponseType
属性。将您的控制器更改为:
[Produces("application/json")]
[Authorize(AuthenticationSchemes = JwtBearerDefaults.AuthenticationScheme)]
[Route("api")]
public class UserController : Controller
{
[ProducesResponseType(typeof(UserInfo), StatusCodes.Status200OK)]
[HttpPost("RegisterUser")]
public IActionResult RegisterUser([FromBody] RegistrationInfo info)
{
UserInfo data = UserData.RegisterUser(info);
if (data != null)
{
return Ok(data);
}
return NoContent();
}
}
查看更多here.
使用以下代码,Swaggger UI 显示 RegistrationInfo 模型但不显示 UserInfo 模型。
我如何生成它?
[Produces("application/json")]
[Authorize(AuthenticationSchemes = JwtBearerDefaults.AuthenticationScheme)]
[Route("api")]
public class UserController : Controller
{
[HttpPost("RegisterUser")]
public IActionResult RegisterUser([FromBody] RegistrationInfo info)
{
UserInfo data = UserData.RegisterUser(info);
if (data != null)
{
return Ok(data);
}
return NoContent();
}
}
您需要使用 ProducesResponseType
属性。将您的控制器更改为:
[Produces("application/json")]
[Authorize(AuthenticationSchemes = JwtBearerDefaults.AuthenticationScheme)]
[Route("api")]
public class UserController : Controller
{
[ProducesResponseType(typeof(UserInfo), StatusCodes.Status200OK)]
[HttpPost("RegisterUser")]
public IActionResult RegisterUser([FromBody] RegistrationInfo info)
{
UserInfo data = UserData.RegisterUser(info);
if (data != null)
{
return Ok(data);
}
return NoContent();
}
}
查看更多here.