Java 中的 RallyApi - 尝试 return 项目层次结构的功能
RallyApi in Java - Trying to return project hierarchy for a feature
鉴于传递到此函数的功能结果集,我试图向上遍历项目层次结构直至订阅。我无法在 projResponse 上获得空指针 =...甚至不确定该方法。
private static void getProjHierarchyForFeature(RallyRestApi restApi, QueryResponse featureSet,
Time2Market time2market, Integer featureInSet) {
String tempHierarchy = "";
JsonArray tempFeatures = featureSet.getResults();
//time2market.setProjectName(projectName);
try {
JsonObject obj1 = tempFeatures.get(featureInSet).getAsJsonObject();
JsonObject proj = obj1.get("Project").getAsJsonObject();
String url = proj.get("_ref").getAsString();
QueryRequest projQuery = new QueryRequest(url);
projQuery.setFetch(new Fetch("_ref", "_refObjectUUID", "_refObjectName"));
QueryResponse projResponse = restApi.query(projQuery);
if (projResponse.wasSuccessful()) {
JsonArray tempProj = projResponse.getResults();
// Here we have the project object, now process Parents...
Boolean moreParents = true;
while (moreParents) {
QueryRequest parentQuery = new QueryRequest(url);
//projQuery.setFetch(new Fetch("_ref", "_refObjectUUID", "_refObjectName"));
QueryResponse parentResponse = restApi.query(parentQuery);
if (parentResponse.wasSuccessful()) {
System.out.println ("proj Response... " + parentResponse.toString());
JsonArray projParent = parentResponse.getResults();
tempHierarchy.concat(projParent.get(0).getAsString());
JsonArray tempParent = parentResponse.getResults();
proj = tempParent.getAsJsonObject();
} else {
moreParents = false;
}
}
} else {
System.err.println("The following errors occurred: ");
for (String err : projResponse.getErrors()) {
System.err.println("\t" + err);
}
throw new java.lang.Error("Rally API Call Error Occurred");
}
} catch (Exception e) {
e.printStackTrace();
}
}
您可能想使用 GetRequest 而不是 QueryRequest,因为您只是在读取单个对象。此外,在您的提取中包含 Parent。然后你应该有数据来确定是否有父级并继续循环。
鉴于传递到此函数的功能结果集,我试图向上遍历项目层次结构直至订阅。我无法在 projResponse 上获得空指针 =...甚至不确定该方法。
private static void getProjHierarchyForFeature(RallyRestApi restApi, QueryResponse featureSet,
Time2Market time2market, Integer featureInSet) {
String tempHierarchy = "";
JsonArray tempFeatures = featureSet.getResults();
//time2market.setProjectName(projectName);
try {
JsonObject obj1 = tempFeatures.get(featureInSet).getAsJsonObject();
JsonObject proj = obj1.get("Project").getAsJsonObject();
String url = proj.get("_ref").getAsString();
QueryRequest projQuery = new QueryRequest(url);
projQuery.setFetch(new Fetch("_ref", "_refObjectUUID", "_refObjectName"));
QueryResponse projResponse = restApi.query(projQuery);
if (projResponse.wasSuccessful()) {
JsonArray tempProj = projResponse.getResults();
// Here we have the project object, now process Parents...
Boolean moreParents = true;
while (moreParents) {
QueryRequest parentQuery = new QueryRequest(url);
//projQuery.setFetch(new Fetch("_ref", "_refObjectUUID", "_refObjectName"));
QueryResponse parentResponse = restApi.query(parentQuery);
if (parentResponse.wasSuccessful()) {
System.out.println ("proj Response... " + parentResponse.toString());
JsonArray projParent = parentResponse.getResults();
tempHierarchy.concat(projParent.get(0).getAsString());
JsonArray tempParent = parentResponse.getResults();
proj = tempParent.getAsJsonObject();
} else {
moreParents = false;
}
}
} else {
System.err.println("The following errors occurred: ");
for (String err : projResponse.getErrors()) {
System.err.println("\t" + err);
}
throw new java.lang.Error("Rally API Call Error Occurred");
}
} catch (Exception e) {
e.printStackTrace();
}
}
您可能想使用 GetRequest 而不是 QueryRequest,因为您只是在读取单个对象。此外,在您的提取中包含 Parent。然后你应该有数据来确定是否有父级并继续循环。