我可以找到每月唯一的事件解决者吗？

Question

我创建了一个脚本，使用以下脚本显示团队中每个月有多少独特的人解决了呼叫。

有没有办法找出个人是谁，但仍然根据我已经在使用的脚本显示每个团队的月度数字？

SELECT CAST(DATEPART(year, stat_datetimeresolved) as varchar(4)) + '-' + RIGHT('0' + CAST(DATEPART(month, stat_datetimeresolved) as varchar(2)), 2) as MonthResolved, ResolvedByTeam, COUNT(DISTINCT resolvedby) as ResolvedByCnt
FROM [dbo].[Incident]
WHERE stat_datetimeresolved >= '20170401'
GROUP BY CAST(DATEPART(year, stat_datetimeresolved) as varchar(4)) + '-' + RIGHT('0' + CAST(DATEPART(month, stat_datetimeresolved) as varchar(2)), 2), ResolvedByTeam
ORDER BY MonthResolved asc, ResolvedByTeam

Answer 1

你有两个选择

为了扩展您的结果，return 为 MonthResolved、ResolvedByTeam 和 resolvedby 的每个唯一组合单独一行。这将比原始查询多 return 行，因为在一个 month/team 组合中，您将获得与解析器一样多的行。
向您的查询添加一列，其中 return 包含解析器名称的列表（例如逗号分隔）。这可以通过 STRING_AGG function, but it is available in SQL Server 2017 and newer only. For 2008 your option is to perform some ugly conversions using FOR XML 子句轻松完成。

这里有两个查询，用于实现选项 1 和 2：

;with cte1 as (
SELECT
    CAST(DATEPART(year, stat_datetimeresolved) as varchar(4)) + '-' + RIGHT('0' + CAST(DATEPART(month, stat_datetimeresolved) as varchar(2)), 2) as MonthResolved
    , ResolvedByTeam
    , resolvedby
FROM [dbo].[Incident]
WHERE stat_datetimeresolved >= '20170401'
GROUP BY CAST(DATEPART(year, stat_datetimeresolved) as varchar(4)) + '-' + RIGHT('0' + CAST(DATEPART(month, stat_datetimeresolved) as varchar(2)), 2), ResolvedByTeam, resolvedby
)
select
    MonthResolved
    , ResolvedByTeam
    , (select count(distinct resolvedby) as Name
       from [dbo].[Incident] i 
       where CAST(DATEPART(year, stat_datetimeresolved) as varchar(4)) + '-' + RIGHT('0' + CAST(DATEPART(month, stat_datetimeresolved) as varchar(2)), 2) = cte1.MonthResolved
         and i.ResolvedByTeam = cte1.ResolvedByTeam)
    , resolvedby
from cte1
ORDER BY MonthResolved asc, ResolvedByTeam, resolvedby

;with cte2 as (
SELECT
    CAST(DATEPART(year, stat_datetimeresolved) as varchar(4)) + '-' + RIGHT('0' + CAST(DATEPART(month, stat_datetimeresolved) as varchar(2)), 2) as MonthResolved
    , ResolvedByTeam
    , COUNT(DISTINCT resolvedby) as ResolvedByCnt
FROM [dbo].[Incident]
WHERE stat_datetimeresolved >= '20170401'
GROUP BY CAST(DATEPART(year, stat_datetimeresolved) as varchar(4)) + '-' + RIGHT('0' + CAST(DATEPART(month, stat_datetimeresolved) as varchar(2)), 2), ResolvedByTeam
)

select *
from cte2
cross apply (select (
    select distinct resolvedby + ', ' as [text()]
    from [dbo].[Incident] 
    where ResolvedByTeam = cte2.ResolvedByTeam
        and CAST(DATEPART(year, stat_datetimeresolved) as varchar(4)) + '-' + RIGHT('0' + CAST(DATEPART(month, stat_datetimeresolved) as varchar(2)), 2) = cte2.MonthResolved
    for xml path ('')) as Names) t
ORDER BY MonthResolved asc, ResolvedByTeam

我可以找到每月唯一的事件解决者吗？

can I find out unique resolvers of incidents per month?

casting

sql-server-2008

datepart