嵌套 for 循环以在两个字符串之间迭代

Nested for loops to iterate between two strings

我想使用 for 循环遍历每个字符串并依次输出每个字符。

String a = "apple";
String b = "class";

for (int i = 0;  i < a.length() ; i++) { // - 1 because 0 = 1
    System.out.print(a.charAt(i));
    for (int j = 0; j < b.length(); j ++) {
        System.out.print(b.charAt(j));
    }
}

我正在为内部循环而苦苦挣扎。

目前我的输出如下:

AClasspClasspClasslClasseClass

但是,我想实现以下目标:

acplpalses

扩展问题:

一个字符串反向输出,另一个正常输出怎么样?

当前尝试:

for (int i = a.length() - 1; i >= 0; i--) {
    System.out.println(a.charAt(i));
    for (int j = 0; j < b.length(); j ++) {
        System.out.println(b.charAt(j));
    }
}

然而,这只是简单地输出如上,只是 "Apple" 以与之前相同的格式相反的顺序:

eclasslclasspclasspclassaclass

您不需要 2 个循环,因为您对两者采用相同的索引 Strings


相同顺序:

  1. 简单的同尺寸案例:

    for (int i = 0; i < a.length(); i++) {
        System.out.print(a.charAt(i));
        System.out.print(b.charAt(i));
    }
    
  2. 复杂不同大小的案例:

    int minLength = Math.min(a.length(), b.length());
    for (int i = 0; i < minLength; i++) {
        System.out.print(a.charAt(i));
        System.out.print(b.charAt(i));
    }
    System.out.print(a.substring(minLength)); // prints the remaining if 'a' is longer
    System.out.print(b.substring(minLength)); // prints the remaining if 'b' is longer
    

顺序不同:

  1. 简单的同尺寸案例:

    for (int i = 0; i < a.length(); i++) {
        System.out.print(a.charAt(i));
        System.out.print(b.charAt(b.length() - i - 1));
    }
    
  2. 复杂不同大小的案例:

    int minLength = Math.min(a.length(), b.length());
    for (int i = 0; i < minLength; i++) {
        System.out.print(a.charAt(i));
        System.out.print(b.charAt(b.length() - i - 1));
    }
    System.out.print(a.substring(minLength));
    System.out.print(new StringBuilder(b).reverse().substring(minLength));
    

另一个使用 Java 8 个流的解决方案:

System.out.println(
    IntStream.range(0, Math.min(a.length(), b.length()))
        .mapToObj(i -> "" + a.charAt(i) + b.charAt(i))
        .collect(Collectors.joining(""))
);

对于扩展问题- 假设两个字符串的大小相同

for (int i = 0; i < a.length(); i++) {
    System.out.print(a.charAt(a.length()-1-i));
    System.out.print(b.charAt(i));
}