Rails 基于关联的顺序无法正常工作

Question

我正在尝试按 release_date 对电影进行排序，但它无法正常工作

@movies = Movie.where(id: movie_ids).recent

如果我使用相反的范围 (:old)，它可以工作，但不能使用 (:recent)

# Movie.rb

# Associations  
has_many :movie_countries, dependent: :destroy
has_many :countries, through: :movie_countries

# Scopes
scope :recent,    -> { includes(:movie_countries).order('movie_countries.release_date DESC') }
scope :old,       -> { includes(:movie_countries).order('movie_countries.release_date ASC') }

示例：

MovieCountry id: 1, movie_id: 1, release_date: '2018-01-01'
MovieCountry id: 2, movie_id: 2, release_date: '2019-01-01'
MovieCountry id: 3, movie_id: 3, release_date: '2020-01-01'

movies = Movie.recent
movies => [movie id: 1, movie id: 3, movie id: 2]

movies = Movie.old
movies => [movie id: 1, movie id: 2, movie id: 3]

如您所见，:old 作用域正常但 :recent

真实数据回溯：

• 最近：

  SELECT "movies"."id" AS t0_r0, "movies"."external_id" AS t0_r1, "movies"."original_title" AS t0_r2, "movies"."original_language" AS t0_r3, "movies"."imdb_id" AS t0_r4, "movies"."tmdb_id" AS t0_r5, "movies"."rentrak_film_id" AS t0_r6, "movies"."running_time" AS t0_r7, "movies"."status" 作为 t0_r8, "movies"."website" 作为 t0_r9, "movies"."backdrop_url" AS t0_r10, "movies"."created_at" AS t0_r11, "movies"."updated_at" AS t0_r12, "movie_countries"."id" AS t1_r0, "movie_countries"."country_id" AS t1_r1, "movie_countries"."movie_id" AS t1_r2 , "movie_countries"."release_date" AS t1_r3, "movie_countries"."iso_code" AS t1_r4, "movie_countries"."created_at" AS t1_r5, "movie_countries"."updated_at" AS t1_r6 FROM "movies" LEFT OUTER JOIN "movie_countries" ON "movie_countries"."movie_id" = "movies"."id" WHERE "movies"."id" IN ($1, $2, $3, $4, $5, $6, $7, $8, $9, $10, $11, $12, $13, $14, $15, $16, $17, $18, $19, $20, $21, $22, $23, $24, $25, $26, $27, $28, $29, $30, $31, $32, $33, $34, $35, $36, $37, $38, $39, $40, $41, $42, $43, $44, $45, $46, $47, $48, $49, $50, $51, $52, $53, $54, $55, $56, $57, $58, $59, $60, $61, $62, $63, $64, $65, $66, $67, $68, $69, $70, $71, $72, $73, $74, $75, $76, $ 77、78 美元、79 美元、80 美元、81 美元、82 美元、83 美元、84 美元、85 美元、86 美元、87 美元、88 美元、89 美元、90 美元、91 美元、92 美元、93 美元、94 美元、95 美元、96 美元、97 美元、98 美元、99 美元、100 美元、101 美元， $102, $103, $104, $105, $106, $107, $108, $109, $110, $111, $112, $113, $114, $115, $116, $117, $118, $119, $120, $121, $122, $123, $124, $125, $126, $127, $128, $129, $130, $131, $132, $133, $134, $135, $136, $137, $138, $139, $140, $141, $142, $143, $144, $145, $146, $147, $148, $149, $150, $151, $152, $153, $154, $155, $156, $157, $158, $159, $160, $161, $162, $163, $164, $165, $166, $167, $168, $169, $170, $171, $172, $173, $174, $175, $176, $177, $178, $179, $180, $181, $182, $183, $184, $185, $186, $187, $188, $189, $190, $191, $192, $193, $194, $195, $196, $197, $198, $199, $200, $201, $202, $203, $204, $205, $206, $207, $208, $209, $210, $211, $212, $213, $214, $215, $216, $217, $218, $219, $220, $221, $222, $223, $224, $225, $226, $227、$228、$229、$230、$231、$232、$233、$234、$235、$236、$237、$238、$239、$240、$241) 按 movie_countries.release_date DESC

排序

• 旧：

  SELECT "movies"."id" AS t0_r0, "movies"."external_id" AS t0_r1, "movies"."original_title" AS t0_r2, "movies"."original_language" AS t0_r3, "movies"."imdb_id" AS t0_r4, "movies"."tmdb_id" AS t0_r5, "movies"."rentrak_film_id" AS t0_r6, "movies"."running_time" AS t0_r7, "movies"."status" 作为 t0_r8, "movies"."website" 作为 t0_r9, "movies"."backdrop_url" AS t0_r10, "movies"."created_at" AS t0_r11, "movies"."updated_at" AS t0_r12, "movie_countries"."id" AS t1_r0, "movie_countries"."country_id" AS t1_r1, "movie_countries"."movie_id" AS t1_r2 , "movie_countries"."release_date" AS t1_r3, "movie_countries"."iso_code" AS t1_r4, "movie_countries"."created_at" AS t1_r5, "movie_countries"."updated_at" AS t1_r6 FROM "movies" LEFT OUTER JOIN "movie_countries" ON "movie_countries"."movie_id" = "movies"."id" WHERE "movies"."id" IN ($1, $2, $3, $4, $5, $6, $7, $8, $9, $10, $11, $12, $13, $14, $15, $16, $17, $18, $19, $20, $21, $22, $23, $24, $25, $26, $27, $28, $29, $30, $31, $32, $33, $34, $35, $36, $37, $38, $39, $40, $41, $42, $43, $44, $45, $46, $47, $48, $49, $50, $51, $52, $53, $54, $55, $56, $57, $58, $59, $60, $61, $62, $63, $64, $65, $66, $67, $68, $69, $70, $71, $72, $73, $74, $75, $76, $ 77、78 美元、79 美元、80 美元、81 美元、82 美元、83 美元、84 美元、85 美元、86 美元、87 美元、88 美元、89 美元、90 美元、91 美元、92 美元、93 美元、94 美元、95 美元、96 美元、97 美元、98 美元、99 美元、100 美元、101 美元， $102, $103, $104, $105, $106, $107, $108, $109, $110, $111, $112, $113, $114, $115, $116, $117, $118, $119, $120, $121, $122, $123, $124, $125, $126, $127, $128, $129, $130, $131, $132, $133, $134, $135, $136, $137, $138, $139, $140, $141, $142, $143, $144, $145, $146, $147, $148, $149, $150, $151, $152, $153, $154, $155, $156, $157, $158, $159, $160, $161, $162, $163, $164, $165, $166, $167, $168, $169, $170, $171, $172, $173, $174, $175, $176, $177, $178, $179, $180, $181, $182, $183, $184, $185, $186, $187, $188, $189, $190, $191, $192, $193, $194, $195, $196, $197, $198, $199, $200, $201, $202, $203, $204, $205, $206, $207, $208, $209, $210, $211, $212, $213, $214, $215, $216, $217, $218, $219, $220, $221, $222, $223, $224, $225, $226, $227, $228, $229, $230, $231, $232, $233, $234, $235, $236, $237, $238, $239, $240, $241) 按 movie_countries.release_date ASC

排序

Answer 1

我找到了解决此问题的替代方法：

# Movie.rb
scope :old,       -> {includes(:movie_countries).order('movie_countries.release_date ASC') }
scope :recent,    -> { old.reverse }

解决方案

感谢 我找到了解决方案

# Movie.rb
scope :recent,    -> (iso_code = 'FR') { includes(:movie_countries).where(movie_countries: {iso_code: iso_code}).order('movie_countries.release_date DESC') }

问题是我的电影有 2 个 movie_countries。

[#<MovieCountry id: 8, country_id: 2, movie_id: 5, release_date: "2018-12-10", iso_code: "GB", created_at: "2018-10-23 15:23:09", updated_at: "2018-10-23 15:23:09">, 
 #<MovieCountry id: 7, country_id: 1, movie_id: 5, release_date: "2018-10-24", iso_code: "FR", created_at: "2018-10-23 15:23:09", updated_at: "2018-10-23 15:23:09">]

我必须在 movie_countries 中搜索特定国家/地区，然后对它们进行排序。