Jenkins 共享库:是否可以将参数传递给作为 'libraryResource' 导入的 shell 脚本?
Jenkins Shared Libraries: is it possible to pass arguments to shell scripts imported as 'libraryResource'?
我有以下设置:
(剥离)Jenkinsfile:
@Library('my-custom-library') _
pipeline {
agent any
stages {
stage('Example') {
steps {
printHello name: 'Jenkins'
}
}
}
}
my-custom-library/resources/com/org/scripts/print-hello.sh:
#!/bin/bash
echo "Hello, "
my-custom-library/vars/printHello.groovy:
def call(Map parameters = [:]) {
def printHelloScript = libraryResource 'com/org/scripts/print-hello.sh'
def name = parameters.name
//the following line gives me headaches
sh(printHelloScript(name))
}
我期望 Hello, Jenkins
,但它抛出以下异常:
groovy.lang.MissingMethodException: No signature of method:
java.lang.String.call() is applicable for argument types:
(java.lang.String) values: [Jenkins]
Possible solutions: wait(), any(), wait(long),
split(java.lang.String), take(int), each(groovy.lang.Closure)
那么,是否可以在不混合 Groovy 和 Bash 代码的情况下执行上述操作?
是的,查看 withEnv
他们给出的例子看起来像;
node {
withEnv(['MYTOOL_HOME=/usr/local/mytool']) {
sh '$MYTOOL_HOME/bin/start'
}
}
更适合你:
// resources/test.sh
echo "HI here we are - $PUPPY_DOH --"
// vars/test.groovy
def call() {
withEnv(['PUPPY_DOH=bobby']) {
sh(libraryResource('test.sh'))
}
}
打印:
[Pipeline] {
[Pipeline] withEnv
[Pipeline] {
[Pipeline] libraryResource
[Pipeline] sh
+ echo HI here we are - bobby --
HI here we are - bobby --
[Pipeline] }
[Pipeline] // withEnv
[Pipeline] }
使用它,您可以使用范围命名变量传递它,例如
def call(Map parameters = [:]) {
def printHelloScript = libraryResource 'com/org/scripts/print-hello.sh'
def name = parameters.name
withEnv(['NAME=' + name]) { // This may not be 100% syntax here ;)
sh(printHelloScript)
}
// print-hello.sh
echo "Hello, $name"
我有以下设置:
(剥离)Jenkinsfile:
@Library('my-custom-library') _
pipeline {
agent any
stages {
stage('Example') {
steps {
printHello name: 'Jenkins'
}
}
}
}
my-custom-library/resources/com/org/scripts/print-hello.sh:
#!/bin/bash
echo "Hello, "
my-custom-library/vars/printHello.groovy:
def call(Map parameters = [:]) {
def printHelloScript = libraryResource 'com/org/scripts/print-hello.sh'
def name = parameters.name
//the following line gives me headaches
sh(printHelloScript(name))
}
我期望 Hello, Jenkins
,但它抛出以下异常:
groovy.lang.MissingMethodException: No signature of method: java.lang.String.call() is applicable for argument types: (java.lang.String) values: [Jenkins]
Possible solutions: wait(), any(), wait(long), split(java.lang.String), take(int), each(groovy.lang.Closure)
那么,是否可以在不混合 Groovy 和 Bash 代码的情况下执行上述操作?
是的,查看 withEnv
他们给出的例子看起来像;
node {
withEnv(['MYTOOL_HOME=/usr/local/mytool']) {
sh '$MYTOOL_HOME/bin/start'
}
}
更适合你:
// resources/test.sh
echo "HI here we are - $PUPPY_DOH --"
// vars/test.groovy
def call() {
withEnv(['PUPPY_DOH=bobby']) {
sh(libraryResource('test.sh'))
}
}
打印:
[Pipeline] {
[Pipeline] withEnv
[Pipeline] {
[Pipeline] libraryResource
[Pipeline] sh
+ echo HI here we are - bobby --
HI here we are - bobby --
[Pipeline] }
[Pipeline] // withEnv
[Pipeline] }
使用它,您可以使用范围命名变量传递它,例如
def call(Map parameters = [:]) {
def printHelloScript = libraryResource 'com/org/scripts/print-hello.sh'
def name = parameters.name
withEnv(['NAME=' + name]) { // This may not be 100% syntax here ;)
sh(printHelloScript)
}
// print-hello.sh
echo "Hello, $name"