合并匹配元素并迭代并分离出集合中的非匹配元素

Question

我是 Node\JS 的新手，一直在研究如何合并匹配元素并迭代集合中的非匹配元素以创建新集合。到目前为止，我已经使用 lodash 对下面粘贴的数据（分组输入）进行了分组，但无法弄清楚如何获得所需的输出。

我愿意使用 lodash\underscore\javascript 或任何其他与 Node 兼容的库。

感谢您的帮助和建议。

Grouped Input:

[ { mod_AccountNumber: '0001',
    mod_Id: '123456',
    mod_LastName: 'SMITH',
    mod_FirstName: 'NANCY',
    mod_AppointmentLocation: 'ROOM10',
    mod_AppointmentDate: '10/26/18',
    mod_AppointmentTime: '0900' },
  { mod_AccountNumber: '0001',
    mod_Id: '123456',
    mod_LastName: 'SMITH',
    mod_FirstName: 'NANCY',
    mod_AppointmentLocation: 'ROOM11',
    mod_AppointmentDate: '10/26/18',
    mod_AppointmentTime: '0930' },
  { mod_AccountNumber: '0001',
    mod_Id: '654321',
    mod_LastName: 'JONES',
    mod_FirstName: 'NATASHA',
    mod_AppointmentLocation: 'ROOM11',
    mod_AppointmentDate: '10/26/18',
    mod_AppointmentTime: '0930' },
  { mod_AccountNumber: '0001',
    mod_Id: '654321',
    mod_LastName: 'JONES',
    mod_FirstName: 'NATASHA',
    mod_AppointmentLocation: 'ROOM12',
    mod_AppointmentDate: '10/26/18',
    mod_AppointmentTime: '1015' }
]

Desired Output:

[ { mod_AccountNumber: '0001',
    mod_Id: '123456',
    mod_LastName: 'SMITH',
    mod_FirstName: 'NANCY',
    mod_AppointmentLocation_1: 'ROOM10',
    mod_AppointmentTime_1:'0900',
    mod_AppointmentLocation_2: 'ROOM11',
    mod_AppointmentTime_2:'0930' },
  { mod_AccountNumber: '0001',
    mod_Id: '654321',
    mod_LastName: 'JONES',
    mod_FirstName: 'NATASHA',
    mod_AppointmentLocation_1: 'ROOM11',
    mod_AppointmentTime_1:'0930',
    mod_AppointmentLocation_2: 'ROOM12',
    mod_AppointmentTime_2:'1015' }
]

Answer 1

const {groupBy, values, merge} = require('lodash');
// input...
const output = values(
    groupBy(input, 'id')
).map(chunks => merge(...chunks));

Answer 2

总体上更好的方法是 将那些 date/time/locations 转换为数组 。但是考虑到当前的问题可以做这样的事情：

const data = [{ mod_AccountNumber: '0001', mod_Id: '123456', mod_LastName: 'SMITH', mod_FirstName: 'NANCY', mod_AppointmentLocation: 'ROOM10', mod_AppointmentDate: '10/26/18', mod_AppointmentTime: '0900' }, { mod_AccountNumber: '0001', mod_Id: '123456', mod_LastName: 'SMITH', mod_FirstName: 'NANCY', mod_AppointmentLocation: 'ROOM11', mod_AppointmentDate: '10/26/18', mod_AppointmentTime: '0930' }, { mod_AccountNumber: '0001', mod_Id: '654321', mod_LastName: 'JONES', mod_FirstName: 'NATASHA', mod_AppointmentLocation: 'ROOM11', mod_AppointmentDate: '10/26/18', mod_AppointmentTime: '0930' }, { mod_AccountNumber: '0001', mod_Id: '654321', mod_LastName: 'JONES', mod_FirstName: 'NATASHA', mod_AppointmentLocation: 'ROOM12', mod_AppointmentDate: '10/26/18', mod_AppointmentTime: '1015' } ]

const result = _(data)
 .groupBy('mod_Id')
 .values()
 .map(x => _.values(_.transform(x, (r,c,i) => {
   r[c.mod_Id] = _.extend(r[c.mod_Id], {
   mod_Id: c.mod_Id,
   mod_AccountNumber: c.mod_AccountNumber,
   mod_LastName: c.mod_LastName,
   mod_FirstName: c.mod_FirstName,
   [`mod_AppointmentLocation${i+1}`]: c.mod_AppointmentLocation,
   [`mod_AppointmentDate${i+1}`]: c.mod_AppointmentDate,
   [`mod_AppointmentTime${i+1}`]: c.mod_AppointmentTime,
 })}, {})))
 .flatten()
 .value()

console.log(result)

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.10/lodash.min.js"></script>

想法是先按 mod_Id 进行分组，然后将 values map 通过它们，然后 transform 它们成为一个对象。因为你回到了对象形式，你得到了 values 最后你 flatten 数组。

更简单的方法是使用 ES6 和这样的东西：

const data = [{ mod_AccountNumber: '0001', mod_Id: '123456', mod_LastName: 'SMITH', mod_FirstName: 'NANCY', mod_AppointmentLocation: 'ROOM10', mod_AppointmentDate: '10/26/18', mod_AppointmentTime: '0900' }, { mod_AccountNumber: '0001', mod_Id: '123456', mod_LastName: 'SMITH', mod_FirstName: 'NANCY', mod_AppointmentLocation: 'ROOM11', mod_AppointmentDate: '10/26/18', mod_AppointmentTime: '0930' }, { mod_AccountNumber: '0001', mod_Id: '654321', mod_LastName: 'JONES', mod_FirstName: 'NATASHA', mod_AppointmentLocation: 'ROOM11', mod_AppointmentDate: '10/26/18', mod_AppointmentTime: '0930' }, { mod_AccountNumber: '0001', mod_Id: '654321', mod_LastName: 'JONES', mod_FirstName: 'NATASHA', mod_AppointmentLocation: 'ROOM12', mod_AppointmentDate: '10/26/18', mod_AppointmentTime: '1015' } ]

const result = Object.values(data.reduce((r, c, i) => {
  let _x = r[c.mod_Id] ? r[c.mod_Id]._x : 0
  _x++
  r[c.mod_Id] = Object.assign(r[c.mod_Id] || {}, {
    mod_Id: c.mod_Id,
    mod_AccountNumber: c.mod_AccountNumber,
    mod_LastName: c.mod_LastName,
    mod_FirstName: c.mod_FirstName,
    [`mod_AppointmentLocation${_x}`]: c.mod_AppointmentLocation,
    [`mod_AppointmentDate${_x}`]: c.mod_AppointmentDate,
    [`mod_AppointmentTime${_x}`]: c.mod_AppointmentTime,
    _x
  })
  return r
}, {})).map(({_x, ...rest}) => rest)
console.log(result)

唯一需要注意的是，这种方法并不纯粹，因为它通过使用 _x 属性改变对象来跟踪当前项目编号，最后通过 map

如果您想考虑采用数组的想法，那么事情会变得简单得多：

const data = [{ mod_AccountNumber: '0001', mod_Id: '123456', mod_LastName: 'SMITH', mod_FirstName: 'NANCY', mod_AppointmentLocation: 'ROOM10', mod_AppointmentDate: '10/26/18', mod_AppointmentTime: '0900' }, { mod_AccountNumber: '0001', mod_Id: '123456', mod_LastName: 'SMITH', mod_FirstName: 'NANCY', mod_AppointmentLocation: 'ROOM11', mod_AppointmentDate: '10/26/18', mod_AppointmentTime: '0930' }, { mod_AccountNumber: '0001', mod_Id: '654321', mod_LastName: 'JONES', mod_FirstName: 'NATASHA', mod_AppointmentLocation: 'ROOM11', mod_AppointmentDate: '10/26/18', mod_AppointmentTime: '0930' }, { mod_AccountNumber: '0001', mod_Id: '654321', mod_LastName: 'JONES', mod_FirstName: 'NATASHA', mod_AppointmentLocation: 'ROOM12', mod_AppointmentDate: '10/26/18', mod_AppointmentTime: '1015' } ]

const result = _.chain(data)
  .reduce((r,c,i) => {
  r[c.mod_Id] = r[c.mod_Id] ? r[c.mod_Id] : {
    mod_Id: c.mod_Id,
    mod_AccountNumber: c.mod_AccountNumber,
    mod_LastName: c.mod_LastName,
    mod_FirstName: c.mod_FirstName,
    schedule: []
  }
  r[c.mod_Id].schedule.push({
    mod_AppointmentLocation: c.mod_AppointmentLocation,
    mod_AppointmentDate: c.mod_AppointmentDate,
    mod_AppointmentTime: c.mod_AppointmentTime
  })
  return r
 }, {})
 .values()
 .value()
 
console.log(result)

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.10/lodash.min.js"></script>

合并匹配元素并迭代并分离出集合中的非匹配元素

Consolidate matching elements and iterate and separate out elements non matching elements in a collection

javascript

node.js

underscore.js

lodash