获取方法 JSON 键的响应（字符串）编码投诉

Question

我的ResponseString如下，

SUCCESS: 
{"code":200,"shop_detail":{"name":"dad","address":"556666"},
"shop_types : [{"name":"IT\/SOFTWARE","merchant_type":"office"}]}

我的带headers的Get请求代码如下，

func getProfileAPI() {
        let headers: HTTPHeaders = [
            "Authorisation": AuthService.instance.tokenId ?? "",
            "Content-Type": "application/json",
            "Accept": "application/json"
        ]
        print(headers)
        let scriptUrl = "http://haitch.igenuz.com/api/merchant/profile"

        if let url = URL(string: scriptUrl) {
            var urlRequest = URLRequest(url: url)
            urlRequest.httpMethod = HTTPMethod.get.rawValue

            urlRequest.addValue(AuthService.instance.tokenId ?? "", forHTTPHeaderField: "Authorization")
            urlRequest.addValue("application/json", forHTTPHeaderField: "Content-Type")
            urlRequest.addValue("application/json", forHTTPHeaderField: "Accept")

            Alamofire.request(urlRequest)
                .responseString { response in
                    debugPrint(response)
                    print(response)
                    if let result = response.result.value //    getting the json value from the server
                    {
                        print(result)

                        let jsonData1 = result as NSString
                        print(jsonData1)
                        let name = jsonData1.object(forKey: "code") as! [AnyHashable: Any]
                        print(name)
                       // var data = jsonData1!["shop_detail"]?["name"] as? String

      } }
}

当我尝试获取 "name" 的值时，它得到'[<__NSCFString 0x7b40f400> valueForUndefinedKey:]：此 class 不符合密钥的键值编码代码。请指导我获取姓名、地址的值..??????

Answer 1

您可以尝试将 json 字符串转换为数据然后对其进行解码

struct Root: Codable {
    let code: Int
    let shopDetail: ShopDetail
    let shopTypes: [ShopType] 
}

struct ShopDetail: Codable {
    let name, address: String
}

struct ShopType: Codable {
    let name, merchantType: String 
}

然后

let jsonStr = result as! String
let dec = JSONDecoder()
dec.keyDecodingStrategy = .convertFromSnakeCase
let res = try? dec.decode(Root.self,from:jsonStr.data(using:.utf8)!)

请注意，您的 str json 可能无效，因为您在 shop_types 之后错过了 "，因此请确保它看起来像这样

{"code":200,"shop_detail":{"name":"dad","address":"556666"}, "shop_types" : [{"name":"IT/SOFTWARE","merchant_type":"office"}]}

Answer 2

您可以使用 Response Handler 而不是 Response String Handler:

Response Handler

The response handler does NOT evaluate any of the response data. It merely forwards on all information directly from the URL session delegate. It is the Alamofire equivalent of using cURL to execute a Request.

struct Root: Codable {
    let code: Int
    let shopDetail: ShopDetail
    let shopTypes: [ShopType]
}

struct ShopDetail: Codable {
    let name, address: String
}

struct ShopType: Codable {
    let name, merchantType: String
}

如果您将解码器 keyDecodingStrategy（检查 this）设置为 .convertFromSnakeCase，您也可以省略结构声明中的编码键，正如@vadian 的评论中已经提到的那样：

Alamofire.request(urlRequest).response { response in
    guard 
       let data = response.data, 
       let json = String(data: data, encoding: .utf8) 
    else { return }
    print("json:", json)
    do {
        let decoder = JSONDecoder()
        decoder.keyDecodingStrategy = .convertFromSnakeCase
        let root = try decoder.decode(Root.self, from: data)
        print(root.shopDetail.name)
        print(root.shopDetail.address)
        for shop in root.shopTypes {
            print(shop.name)
            print(shop.merchantType)
        }
    } catch { 
        print(error) 
    }            
}

有关编码和解码自定义类型的更多信息，您可以阅读这篇文章 post。

获取方法 JSON 键的响应（字符串）编码投诉

Get Method JSON Response(String) Coding Complaint for key

string

xcode

json

ios

swift4