如何在 python 中使我的合并输出水平而不是垂直

Question

我有这个 python3 代码可以将我的子列表合并到一个列表中：

l=[[4, 5, 6], [10], [1, 2, 3], [10], [1, 2, 3], [10], [4, 5, 6], [1, 2, 3], [4, 5, 6], [4, 5, 6], [7, 8, 9], [1, 2, 3], [7, 8, 9], [1, 2, 3], [4, 5, 6], [7, 8, 9], [4, 5, 6], [10], [7, 8, 9], [7, 8, 9]]

import itertools
merged = list(itertools.chain(*l))

from collections import Iterable

def flatten(items):
    """Yield items from any nested iterable; see Reference."""
    for x in items:
        if isinstance(x, Iterable) and not 
isinstance(x, (str, bytes)):
            for sub_x in flatten(x):
                yield sub_x
        else:
            yield x

merged = list(itertools.chain(*l))
merged

输出的不良形状

虽然输出结果是我想要的，但是输出的形状不是我想要的输出以垂直形状出现，如下所示：

[4,
5,
6,
10,
1,
2,
3,
10,
1,
2,
3,
10,
4,
5,
6,
1,
2,
3,
4,
5,
6,
4,
5,
6,
7,
8,
9,
1,
2,
3,
7,
8,
9,
1,
2,
3,
4,
5,
6,
7,
8,
9,
4,
5,
6,
10,
7,
8,
9,
7,
8,
9]

我想要的理想输出形状

我希望输出水平输出，如下所示：

[4, 5, 6, 10, 1, 2, 3, 10, 1, 2, 3, 10, 4, 5, 6, 1, 2, 3, 4, 5, 6, 4, 5, 6, 7, 8, 9, 1, 2, 3, 7, 8, 9, 1, 2, 3, 4, 5, 6, 7, 8, 9, 4, 5, 6, 10, 7, 8, 9, 7, 8, 9]

请帮帮我，我不介意是否有一种不同于我的代码的方法来实现这一点。

Answer 1

你可以这样做：

In [5]: for x in merged:
   ...:     print(x, end=' ')
   ...:     
4 5 6 10 1 2 3 10 1 2 3 10 4 5 6 1 2 3 4 5 6 4 5 6 7 8 9 1 2 3 7 8 9 1 2 3 4 5 6 7 8 9 4 5 6 10 7 8 9 7 8 9

Answer 2

而是只使用列表理解：

l=[[4, 5, 6], [10], [1, 2, 3], [10], [1, 2, 3], [10], [4, 5, 6], [1, 2, 3], [4, 5, 6], [4, 5, 6], [7, 8, 9], [1, 2, 3], [7, 8, 9], [1, 2, 3], [4, 5, 6], [7, 8, 9], [4, 5, 6], [10], [7, 8, 9], [7, 8, 9]]

new_l=[j for i in l for j in i]
print(new_l)

输出：

C:\Users\Desktop>py x.py
[4, 5, 6, 10, 1, 2, 3, 10, 1, 2, 3, 10, 4, 5, 6, 1, 2, 3, 4, 5, 6, 4, 5, 6, 7, 8, 9, 1, 2, 3, 7, 8, 9, 1, 2, 3, 4, 5, 6, 7, 8, 9, 4, 5, 6, 10, 7, 8, 9, 7, 8, 9]

如何在 python 中使我的合并输出水平而不是垂直

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