PHP 更改密码脚本总是从数据库中检测到错误的密码

PHP Change password script always detect wrong password from database

所以我有一个带有 phpmyadmin 的数据库,那里有密码列。我想制作一个可以更改密码的脚本,如果当前密码与数据库中的密码相同,则更改成功。但如果当前密码与数据库中的密码不匹配,则更改密码失败。

当我尝试时,我总是出错 password/failed 即使当前密码与数据库中的密码相同。我使用 Postman

检查它

这是邮递员的输出postman

这是我的数据库 database

这是我的 PHP 脚本

<?php

if ($_SERVER['REQUEST_METHOD']=='POST'){

    $id = $_POST['id'];
    $currentpassword = $_POST['currentpassword'];
    $newpassword = $_POST['newpassword'];

    require_once 'connect.php';

    $sql = "SELECT * FROM user_account WHERE id='$id' ";

    $response = mysqli_query($conn, $sql);

    //echo mysqli_num_rows($response);


    if(mysqli_num_rows($response) > 0){

        $row = mysqli_fetch_assoc($response);

        if (password_verify($currentpassword, $row['password']) ){

            $updatepass = "UPDATE user_account SET password='$newpassword' WHERE id='$id' ";

                if(mysqli_query($conn, $updatepass)) {

                    $result["success"] = "1";
                    $result["message"] = "success";

                    echo json_encode($result);
                    mysqli_close($conn);
                }
                else{

                    $result["success"] = "0";
                    $result["message"] = "error!";
                    echo json_encode($result);

                mysqli_close($conn);
                }

        }else{
            $result['success'] = "0";
            $result['message'] = "Wrong password.";
            echo json_encode($result);

            mysqli_close($conn);
        }

    }

}


?>

来自manual

password_verify — Verifies that a password matches a hash

然后您将密码存储为原始密码。您需要将密码存储在数据库中作为 散列 密码 password_hash() function 因此 password_verify 函数 returns 为真。

//for example replace this
$query = "insert into user_account(name, email, password) values ('testing','testing@gmail.com','1234567')";
//with this
$query = "insert into user_account(name, email, password) values ('testing','testing@gmail.com','" . password_hash('1234567') . "')";