如何将地图的地图列表合并为地图的地图?

How to merge List of Maps of Maps into a Map of Maps?

你能帮我 Java Streams 吗?

如标题所示,我需要将 List<Map<String, Map<String, Genuineness>>> 合并到 Map<String, Map<String, Genuineness>>

列表表示为 List<Map<String, Map<String, Genuineness>>>,看起来像:

[  
   {  
      "USER_1":{  
         "APP_1":{  
            "total":1,
            "totalGenuine":1,
            "totalDevelopment":1
         }
      },
      "USER_2":{  
         "APP_1":{  
            "total":1,
            "totalGenuine":1,
            "totalDevelopment":1
         },
         "APP_2":{  
            "total":2,
            "totalGenuine":2,
            "totalDevelopment":2
         }
      }
   },
   {  
      "USER_1":{  
         "APP_1":{  
            "total":1,
            "totalGenuine":1,
            "totalDevelopment":1
         }
      },
      "USER_2":{  
         "APP_1":{  
            "total":1,
            "totalGenuine":1,
            "totalDevelopment":1
         },
         "APP_2":{  
            "total":2,
            "totalGenuine":2,
            "totalDevelopment":2
         }
      }
   }
]

因此,如您所见,重复键可能无处不在。 我的目标是通过合并 Genuineness 将它们组合成 Map<String, Map<String, Genuineness>>。合并 Genuineness 只是意味着 return 一个新的 object 具有汇总值 totaltotalGenuinetotalDevelopment.

这是我失败的实现:

final Map<String, Map<String, Genuineness>> map = taskHandles.stream().map(this::mapTaskHandle)
                .flatMap(m -> m.entrySet().stream()).collect(
                        Collectors.toMap(Map.Entry::getKey, e -> e.getValue().entrySet().stream()
                                .collect(
                                        Collectors.toMap(Map.Entry::getKey,
                                                g -> new Genuineness(g.getValue().getTotal(), g.getValue().getTotalGenuine(), g.getValue().getTotalDevelopment()),
                                                (g1, g2) -> new Genuineness(g1.getTotal() + g2.getTotal(),
                                                        g1.getTotalGenuine() + g2.getTotalGenuine(),
                                                        g1.getTotalDevelopment() + g2.getTotalGenuine()
                                                )
                                        )
                                )
                        )
                );

失败并显示消息:

java.lang.IllegalStateException: Duplicate key {TEST_33_33_APP_1=live.attach.billing.domain.model.billing.Genuineness@951b6fe}

所以,在我的实现中,我似乎指出了如何合并内部地图,但没有合并外部地图的值,我不知道该怎么做。

非常感谢你的帮助。提前致谢!

更新: 预期输出:

   {  
      "USER_1":{  
         "APP_1":{  
            "total":2,
            "totalGenuine":2,
            "totalDevelopment":2
         }
      },
      "USER_2":{  
         "APP_1":{  
            "total":2,
            "totalGenuine":2,
            "totalDevelopment":2
         },
         "APP_2":{  
            "total":4,
            "totalGenuine":4,
            "totalDevelopment":4
         }
      }
   }

老实说,这是一个糟糕的数据结构,代码的维护者将很难发现出现的问题。

你应该退一步考虑重构代码,任何你可以通过在最外层使用以下合并功能来解决缺失部分的方法toMap:

(l, r) -> {
      r.forEach((k, v) -> l.merge(k, v,
                    (bi, bii) -> new Genuineness(bi.getTotal() + bii.getTotal(),
                               bi.getTotalGenuine() + bii.getTotalGenuine(),
                               bi.getTotalDevelopment() + bii.getTotalGenuine())));
       return l;
}

完整代码:

taskHandles.stream().map(this::mapTaskHandle)
                .flatMap(m -> m.entrySet().stream()).collect(
                        Collectors.toMap(Map.Entry::getKey, e -> e.getValue().entrySet().stream()
                                .collect(
                                        Collectors.toMap(Map.Entry::getKey,
                                                g -> new Genuineness(g.getValue().getTotal(), g.getValue().getTotalGenuine(), g.getValue().getTotalDevelopment()),
                                                (g1, g2) -> new Genuineness(g1.getTotal() + g2.getTotal(),
                                                        g1.getTotalGenuine() + g2.getTotalGenuine(),
                                                        g1.getTotalDevelopment() + g2.getTotalGenuine()
                                                )
                                        )
                                ),(l, r) -> {
                                  r.forEach((k, v) -> l.merge(k, v,
                                          (bi, bii) -> new Genuineness(bi.getTotal() + bii.getTotal(),
                                                  bi.getTotalGenuine() + bii.getTotalGenuine(),
                                                  bi.getTotalDevelopment() + bii.getTotalGenuine())));
                                  return l;
                                }

                        )
                );

Ideone

尽管 seems to be correct, you can alternatively improve your code readability and simplify it defining a BinaryOperator<Genuineness> 作为 :

BinaryOperator<Genuineness> remappingGenuineness = (g1, g2) -> new Genuineness(g1.getTotal() + g2.getTotal(),
        g1.getTotalGenuine() + g2.getTotalGenuine(),
        g1.getTotalDevelopment() + g2.getTotalGenuine()
);

然后进一步将其用作:

final Map<String, Map<String, Genuineness>> map = taskHandles.stream()
        .flatMap(m -> m.entrySet().stream())
        .collect(Collectors.toMap(Map.Entry::getKey,
                e -> e.getValue().entrySet().stream().collect(
                        Collectors.toMap(Map.Entry::getKey, Map.Entry::getValue, remappingGenuineness)),
                (a, b) -> {
                    a.forEach((k, v) -> b.merge(k, v, remappingGenuineness));
                    return b;
                }));