使用 GraphQL + 石墨烯进行删除操作的最佳方式

Question

我正在努力让我的删除操作正常工作。我的创建、读取和更新工作正常，但删除与 return.

无关

class DeleteEmployeeInput(graphene.InputObjectType):
    """Arguments to delete an employee."""
    id = graphene.ID(required=True, description="Global Id of the employee.")


class DeleteEmployee(graphene.Mutation):
    """Delete an employee."""
    employee = graphene.Field(
        lambda: Employee, description="Employee deleted by this mutation.")

    class Arguments:
        input = DeleteEmployeeInput(required=True)

    def mutate(self, info, input):
        data = utils.input_to_dictionary(input)
        #data['edited'] = datetime.utcnow()

        employee = db_session.query(
            EmployeeModel).filter_by(id=data['id'])
        employee.delete(data['id'])
        db_session.commit()
        #employee = db_session.query(
            #EmployeeModel).filter_by(id=data['id']).first()

        #return DeleteEmployee(employee=employee)

删除条目的最佳方法是什么？我假设我必须 return OK 或 Error。

当我运行我的突变：

mutation {
  deleteEmployee (input: {
       id: "RW1wbG95ZWU6MQ=="
  }) 
}

我收到错误 Field \"deleteEmployee\" of type \"DeleteEmployee\" must have a sub selection."

注意注释掉的行

Answer 1

尝试将 employee = graphene.Field... 替换为 ok = graphene.Boolean()，然后将 mutate 方法的最后一行设为 return DeleteEmployee(ok=True)

您的 mutate 方法将类似于：

    def mutate(self, info, input):
        ... skipping deletion code ...
        db_session.commit()
        return DeleteEmployee(ok=True)

使用 GraphQL + 石墨烯进行删除操作的最佳方式

Best way to do a delete operation with GraphQL + graphene

graphql

graphene-python