比较文件名并重新创建源目录后移动文件
Moving files after comparing filenames and recreating source directories
我正在学习 shell 脚本，并努力保持尽可能 POSIX 兼容，同时保持代码库的可读性。目标是从目录 A 中读取文件列表，从目录 B 中找到它们的匹配项，并在目录 C 中重新创建目录父 B 的一部分，其中目录 A 中的文件应该被移动，然后删除 matched/moved目录 B 中的文件，如果从目录 B 文件中找到的目录为空，则删除它们。目录 A 中的所有文件将始终彼此唯一，目录 B 中始终存在一个或多个匹配项，而目录 C 中永远不会匹配，但目录 C 中的子目录可能已经存在以匹配目录 B . 在将匹配项从目录 A 移动到目录 C 后，应删除目录 B 中匹配的所有文件。扩展名会随着文件的单独处理而变化，但文件名将完全匹配。文件名可以包含空格和句点。文件名不会总是相同的长度。输出目录和存档目录中有两级子目录。
这是我目前所知道的。我被困在编写 for 循环来做脏活。尽量不要在 find、printf、awk、grep、for 和 if 之外走得太远。
#!/bin/sh
execHome="intendedMachine"
baseDir="/home/library/projects"
folderNew="output"
folderOld="working"
folderArchive="archive"
workingTypes=("jpg", "svg", "bmp", "tiff", "psd")
$folderNew="$baseDir/$folderNew"
$folderOld="$baseDir/$folderOld"
folderArchive="$baseDir/$folderArchive"
if [ "$(uname -n)" = "$execHome" ]
then
count=$(find $folderNew -type f |grep -v "DS_Store" |awk -F "/" '{print $NF}'|wc -l)
printf "\nFound/processing %s files in the %s folder\n\n" "$count" "$folderNew"
find $folderNew -type f |grep -v "DS_Store" |awk -F "/" '{print $NF}'
else
printf "Executed from %s; Run from %s for proper execution.\n" "$(uname -n)" "$execHome"
fi
示例：
目录A
/home/library/projects/output/projectOne 1.a.png
/home/library/projects/output/projectOne 1.b.png
/home/library/projects/output/projectOne 1.c.png
/home/library/projects/output/projectThree 3.m.png
/home/library/projects/output/projectThree 3.o.png
/home/library/projects/output/projectFour 4.t.png
/home/library/projects/output/projectFour 4.u.png
目录 B
/home/library/projects/working/House/2018 01/projectOne 1.a.jpg
/home/library/projects/working/House/2018 01/projectOne 1.a.svg
/home/library/projects/working/House/2018 01/projectOne 1.b.jpg
/home/library/projects/working/House/2018 01/projectOne 1.b.svg
/home/library/projects/working/House/2018 01/projectOne 1.c.jpg
/home/library/projects/working/House/2018 02/projectTwo 2.g.jpg
/home/library/projects/working/House/2018 02/projectTwo 2.g.svg
/home/library/projects/working/House/2018 02/projectTwo 2.h.jpg
/home/library/projects/working/House/2018 02/projectTwo 2.h.svg
/home/library/projects/working/House/2018 02/projectTwo 2.i.jpg
/home/library/projects/working/Car/2018 03/projectThree 3.m.jpg
/home/library/projects/working/Car/2018 03/projectThree 3.n.jpg
/home/library/projects/working/Car/2018 03/projectThree 3.o.jpg
/home/library/projects/working/Car/2018 03/projectThree 3.o.svg
/home/library/projects/working/Car/2018 04/projectFour 4.s.jpg
/home/library/projects/working/Car/2018 04/projectFour 4.t.jpg
/home/library/projects/working/Car/2018 04/projectFour 4.u.jpg
C目录
/home/library/projects/archive/House/2018 01/projectOne 1.d.png
/home/library/projects/archive/House/2018 01/projectOne 1.e.png
/home/library/projects/archive/House/2018 01/projectOne 1.f.png
/home/library/projects/archive/Car/2018 03/projectThree 3.p.png
/home/library/projects/archive/Car/2018 03/projectThree 3.q.png
/home/library/projects/archive/Car/2018 03/projectThree 3.r.png
期望的结果：
目录 A 的文件已移至目录 C
/home/library/projects/output/
目录 B 应删除目录 A 的文件并删除空文件夹
/home/library/projects/working/House/2018 02/projectTwo 2.g.jpg
/home/library/projects/working/House/2018 02/projectTwo 2.g.svg
/home/library/projects/working/House/2018 02/projectTwo 2.h.jpg
/home/library/projects/working/House/2018 02/projectTwo 2.h.svg
/home/library/projects/working/House/2018 02/projectTwo 2.i.jpg
/home/library/projects/working/Car/2018 03/projectThree 3.n.jpg
/home/library/projects/working/Car/2018 04/projectFour 4.s.jpg
目录 C 应包含旧存档和新输出文件作为存档
/home/library/projects/archive/House/2018 01/projectOne 1.a.png
/home/library/projects/archive/House/2018 01/projectOne 1.b.png
/home/library/projects/archive/House/2018 01/projectOne 1.c.png
/home/library/projects/archive/House/2018 01/projectOne 1.d.png
/home/library/projects/archive/House/2018 01/projectOne 1.e.png
/home/library/projects/archive/House/2018 01/projectOne 1.f.png
/home/library/projects/archive/Car/2018 03/projectThree 3.m.png
/home/library/projects/archive/Car/2018 03/projectThree 3.o.png
/home/library/projects/archive/Car/2018 03/projectThree 3.p.png
/home/library/projects/archive/Car/2018 03/projectThree 3.q.png
/home/library/projects/archive/Car/2018 03/projectThree 3.r.png
/home/library/projects/archive/Car/2018 04/projectFour 4.t.png
/home/library/projects/archive/Car/2018 04/projectFour 4.u.png
运行 无论如何从 bash 4.4.19 机器上查看它是如何工作的代码，但它并没有像我预期的那样工作。这是结果输出：
Found/processing 4 files in the /home/library/projects/output folder
./auto-archive.sh: line 34: hash["$proj"]: bad array subscript
parent of /home/library/projects/output/.temp/projectThree 3.m.png not found
parent of /home/library/projects/output/projectOne 1.a.png not found
parent of /home/library/projects/output/.temp/projectThree 3.0.png not found
parent of /home/library/projects/output/projectFour 4.t.png not found
抱歉。我之前也没有提到不应该递归扫描目录 B，这在用例中会产生其他正在写入但可能尚未准备好移动的临时文件。另外，出于测试的目的，只有上面列出的四个文件实际上在目录 A 中；并非所有最初列出的文件。此外，在重新创建建议的测试结构后，您的代码似乎可以完美执行；与我实际文件结构的结果不匹配。我担心我在描述我的实际文件 structure/naming 约定时可能错过了一些关键要素。现在审查描述符差异。很抱歉占用您的时间，但您的准确性肯定给我留下了深刻的印象。感觉我们越来越接近了，但肯定需要 运行 在 bash.
的早期版本上
任务将分为三个步骤：
创建一个映射，将每个文件名（项目名称）与其在 C 中的父目录名称相关联。这是通过分析 B 中的路径名作为准备阶段执行的。我们将使用关联array 和 bash 版本必须是 4.2 或更高版本。
循环A中的文件，利用第一步创建的map，在C中构造一个存放路径名，删除B中的文件
作为清理阶段，我们删除 B 中的空目录（如果有）。
那么：
#!/bin/bash
execHome="intendedMachine"
baseDir="/home/library/projects"
folderNew="output"
folderOld="working"
folderArchive="archive"
workingTypes=("jpg" "svg" "bmp" "tiff" "psd")
declare -A hash
folderNew="$baseDir/$folderNew"
folderOld="$baseDir/$folderOld"
folderArchive="$baseDir/$folderArchive"
if [ "$(uname -n)" != "$execHome" ]; then
printf "Executed from %s; Run from %s for proper execution.\n" "$(uname -n)" "$execHome"
exit
fi
count=$(find "$folderNew" -type f |grep -v "DS_Store" |awk -F "/" '{print $NF}'|wc -l)
printf "\nFound/processing %s files in the %s folder\n\n" "$count" "$folderNew"
# determine parent directory name for each project name and create a map for them
while IFS= read -r -d $'[=10=]' f; do
proj="${f##*/}" # remove dirname
proj="${proj%.*}" # remove extention
parent="${f##*$baseDir/}" # remove pathname until $baseDir
parent="${parent#*/}" # strip pathname one-level deeper
parent="${parent%/*}" # remove filename
# now we're mapping "projectOne 1.a" => "House/2018 01" e.g.
# echo "$proj" "=>" "$parent" # just for debugging
hash["$proj"]="$parent"
done < <(find "$folderOld" -type f -print0) # directory B
# iterate over files in A; move to archive directory C and remove files in B
while IFS= read -r -d $'[=10=]' f; do
proj="${f##*/}"
proj="${proj%.*}"
parent="${hash[$proj]}"
if [[ "$parent" = "" ]]; then
echo "parent of $f not found" # may not occur but just in case ..
else
# move from A to C
destdir="$folderArchive/$parent"
mkdir -p -- "$destdir"
mv -- "$f" "$destdir"
# remove relevant file(s) in B
for ext in "${workingTypes[@]}"; do
oldfile="$folderOld/$parent/$proj.${ext}"
[ -f "$oldfile" ] && rm -f -- "$oldfile"
done
fi
done < <(find "$folderNew" -type f -print0) # directory A
# clean-up: remove empty dirs in B
find "$folderOld" -type d -empty -print0 | xargs -r -0 rmdir --
说明：
- 您不必使用逗号来分隔数组中的元素。
- 你不应该把
$ 放在左边的变量名之前。
while IFS= ... done < <(find ...) 语法是循环遍历 find 输出的惯用法。${parameter#word} 类型的语法是 parameter expansion 从路径中提取子字符串。- 关联数组
hash 将每个项目名称（例如 "projectOne 1.a"）映射到其父目录名称（例如 "House/2018 01". ）
某些命令中的--是为可能以-开头的文件名做准备。 （这种保护可能看起来病态...）
如果您的 bash 早于 4.2，请告诉我。那我们就得想办法了。
编辑
这是 POSIX 兼容版本作为替代：
（显然，如果文件名包含换行符或转义字符 \x1b，脚本将不起作用。）
#!/bin/sh
execHome="intendedMachine"
baseDir="/home/library/projects"
folderNew="output"
folderOld="working"
folderArchive="archive"
workingTypes="jpg
svg
bmp
tiff
psd"
folderNew="$baseDir/$folderNew"
folderOld="$baseDir/$folderOld"
folderArchive="$baseDir/$folderArchive"
nl="
" # set to newline character
esc=$(/bin/echo -ne "3") # set to escape character
#esc=":" # if 3 does not work well, try another character
# substitute of reading a hash
# it relies on the context that IFS is set to $nl
read_lut() {
local i
local key
local val
local ret=""
for i in $lut; do
key="${i%${esc}*}"
val="${i#*${esc}}"
if [ "$key" = "" ]; then
# loop until the end and use the last value
ret="$val"
fi
done
echo "$ret"
}
# substitute of writing to a hash
write_lut() {
lut=$(printf "%s\n%s%c%s" "$lut" "" "$esc" "")
}
if [ "$(uname -n)" != "$execHome" ]; then
printf "Executed from %s; Run from %s for proper execution.\n" "$(uname -n)" "$execHome"
exit
fi
count=$(find "$folderNew" -type f |grep -v "DS_Store" |awk -F "/" '{print $NF}'|wc -l)
printf "\nFound/processing %s files in the %s folder\n\n" "$count" "$folderNew"
# determine parent directory name for each project name and create a map for them
ifs_bak="$IFS"
IFS="$nl"
for f in $(find "$folderOld" -type f); do
proj="${f##*/}" # remove dirname
proj="${proj%.*}" # remove extention
parent="${f##*$baseDir/}" # remove pathname until $baseDir
parent="${parent#*/}" # strip pathname one-level deeper
parent="${parent%/*}" # remove filename
# now we're mapping "projectOne 1.a" => "House/2018 01" e.g.
# echo "$proj" "=>" "$parent" # just for debugging
write_lut "$proj" "$parent"
done
# iterate over files in A; move to archive directory C and remove files in B
for f in $(find "$folderNew" -type f); do
proj="${f##*/}"
proj="${proj%.*}"
parent=$(read_lut "$proj")
if [ "$parent" = "" ]; then
echo "parent of $f not found" # may not occur but just in case ..
else
# move from A to C
destdir="$folderArchive/$parent"
mkdir -p -- "$destdir"
mv -- "$f" "$destdir"
# remove relevant file(s) in B
for ext in $workingTypes; do
oldfile="$folderOld/$parent/$proj.${ext}"
[ -f "$oldfile" ] && rm -f -- "$oldfile"
done
fi
done
# clean-up: remove empty dirs in B
find "$folderOld" -type d -empty -print0 | xargs -r -0 rmdir --
# restore IFS
IFS="$ifs_bak"
我正在学习 shell 脚本，并努力保持尽可能 POSIX 兼容，同时保持代码库的可读性。目标是从目录 A 中读取文件列表，从目录 B 中找到它们的匹配项，并在目录 C 中重新创建目录父 B 的一部分，其中目录 A 中的文件应该被移动，然后删除 matched/moved目录 B 中的文件，如果从目录 B 文件中找到的目录为空，则删除它们。目录 A 中的所有文件将始终彼此唯一，目录 B 中始终存在一个或多个匹配项，而目录 C 中永远不会匹配，但目录 C 中的子目录可能已经存在以匹配目录 B . 在将匹配项从目录 A 移动到目录 C 后，应删除目录 B 中匹配的所有文件。扩展名会随着文件的单独处理而变化，但文件名将完全匹配。文件名可以包含空格和句点。文件名不会总是相同的长度。输出目录和存档目录中有两级子目录。
这是我目前所知道的。我被困在编写 for 循环来做脏活。尽量不要在 find、printf、awk、grep、for 和 if 之外走得太远。
#!/bin/sh
execHome="intendedMachine"
baseDir="/home/library/projects"
folderNew="output"
folderOld="working"
folderArchive="archive"
workingTypes=("jpg", "svg", "bmp", "tiff", "psd")
$folderNew="$baseDir/$folderNew"
$folderOld="$baseDir/$folderOld"
folderArchive="$baseDir/$folderArchive"
if [ "$(uname -n)" = "$execHome" ]
then
count=$(find $folderNew -type f |grep -v "DS_Store" |awk -F "/" '{print $NF}'|wc -l)
printf "\nFound/processing %s files in the %s folder\n\n" "$count" "$folderNew"
find $folderNew -type f |grep -v "DS_Store" |awk -F "/" '{print $NF}'
else
printf "Executed from %s; Run from %s for proper execution.\n" "$(uname -n)" "$execHome"
fi
示例：
目录A
/home/library/projects/output/projectOne 1.a.png
/home/library/projects/output/projectOne 1.b.png
/home/library/projects/output/projectOne 1.c.png
/home/library/projects/output/projectThree 3.m.png
/home/library/projects/output/projectThree 3.o.png
/home/library/projects/output/projectFour 4.t.png
/home/library/projects/output/projectFour 4.u.png
目录 B
/home/library/projects/working/House/2018 01/projectOne 1.a.jpg
/home/library/projects/working/House/2018 01/projectOne 1.a.svg
/home/library/projects/working/House/2018 01/projectOne 1.b.jpg
/home/library/projects/working/House/2018 01/projectOne 1.b.svg
/home/library/projects/working/House/2018 01/projectOne 1.c.jpg
/home/library/projects/working/House/2018 02/projectTwo 2.g.jpg
/home/library/projects/working/House/2018 02/projectTwo 2.g.svg
/home/library/projects/working/House/2018 02/projectTwo 2.h.jpg
/home/library/projects/working/House/2018 02/projectTwo 2.h.svg
/home/library/projects/working/House/2018 02/projectTwo 2.i.jpg
/home/library/projects/working/Car/2018 03/projectThree 3.m.jpg
/home/library/projects/working/Car/2018 03/projectThree 3.n.jpg
/home/library/projects/working/Car/2018 03/projectThree 3.o.jpg
/home/library/projects/working/Car/2018 03/projectThree 3.o.svg
/home/library/projects/working/Car/2018 04/projectFour 4.s.jpg
/home/library/projects/working/Car/2018 04/projectFour 4.t.jpg
/home/library/projects/working/Car/2018 04/projectFour 4.u.jpg
C目录
/home/library/projects/archive/House/2018 01/projectOne 1.d.png
/home/library/projects/archive/House/2018 01/projectOne 1.e.png
/home/library/projects/archive/House/2018 01/projectOne 1.f.png
/home/library/projects/archive/Car/2018 03/projectThree 3.p.png
/home/library/projects/archive/Car/2018 03/projectThree 3.q.png
/home/library/projects/archive/Car/2018 03/projectThree 3.r.png
期望的结果：
目录 A 的文件已移至目录 C
/home/library/projects/output/
目录 B 应删除目录 A 的文件并删除空文件夹
/home/library/projects/working/House/2018 02/projectTwo 2.g.jpg
/home/library/projects/working/House/2018 02/projectTwo 2.g.svg
/home/library/projects/working/House/2018 02/projectTwo 2.h.jpg
/home/library/projects/working/House/2018 02/projectTwo 2.h.svg
/home/library/projects/working/House/2018 02/projectTwo 2.i.jpg
/home/library/projects/working/Car/2018 03/projectThree 3.n.jpg
/home/library/projects/working/Car/2018 04/projectFour 4.s.jpg
目录 C 应包含旧存档和新输出文件作为存档
/home/library/projects/archive/House/2018 01/projectOne 1.a.png
/home/library/projects/archive/House/2018 01/projectOne 1.b.png
/home/library/projects/archive/House/2018 01/projectOne 1.c.png
/home/library/projects/archive/House/2018 01/projectOne 1.d.png
/home/library/projects/archive/House/2018 01/projectOne 1.e.png
/home/library/projects/archive/House/2018 01/projectOne 1.f.png
/home/library/projects/archive/Car/2018 03/projectThree 3.m.png
/home/library/projects/archive/Car/2018 03/projectThree 3.o.png
/home/library/projects/archive/Car/2018 03/projectThree 3.p.png
/home/library/projects/archive/Car/2018 03/projectThree 3.q.png
/home/library/projects/archive/Car/2018 03/projectThree 3.r.png
/home/library/projects/archive/Car/2018 04/projectFour 4.t.png
/home/library/projects/archive/Car/2018 04/projectFour 4.u.png
运行 无论如何从 bash 4.4.19 机器上查看它是如何工作的代码，但它并没有像我预期的那样工作。这是结果输出：
Found/processing 4 files in the /home/library/projects/output folder
./auto-archive.sh: line 34: hash["$proj"]: bad array subscript
parent of /home/library/projects/output/.temp/projectThree 3.m.png not found
parent of /home/library/projects/output/projectOne 1.a.png not found
parent of /home/library/projects/output/.temp/projectThree 3.0.png not found
parent of /home/library/projects/output/projectFour 4.t.png not found
抱歉。我之前也没有提到不应该递归扫描目录 B，这在用例中会产生其他正在写入但可能尚未准备好移动的临时文件。另外，出于测试的目的，只有上面列出的四个文件实际上在目录 A 中；并非所有最初列出的文件。此外，在重新创建建议的测试结构后，您的代码似乎可以完美执行；与我实际文件结构的结果不匹配。我担心我在描述我的实际文件 structure/naming 约定时可能错过了一些关键要素。现在审查描述符差异。很抱歉占用您的时间，但您的准确性肯定给我留下了深刻的印象。感觉我们越来越接近了，但肯定需要 运行 在 bash.
的早期版本上任务将分为三个步骤：
创建一个映射，将每个文件名（项目名称）与其在 C 中的父目录名称相关联。这是通过分析 B 中的路径名作为准备阶段执行的。我们将使用关联array 和 bash 版本必须是 4.2 或更高版本。
循环A中的文件，利用第一步创建的map，在C中构造一个存放路径名，删除B中的文件
作为清理阶段，我们删除 B 中的空目录（如果有）。
那么：
#!/bin/bash
execHome="intendedMachine"
baseDir="/home/library/projects"
folderNew="output"
folderOld="working"
folderArchive="archive"
workingTypes=("jpg" "svg" "bmp" "tiff" "psd")
declare -A hash
folderNew="$baseDir/$folderNew"
folderOld="$baseDir/$folderOld"
folderArchive="$baseDir/$folderArchive"
if [ "$(uname -n)" != "$execHome" ]; then
printf "Executed from %s; Run from %s for proper execution.\n" "$(uname -n)" "$execHome"
exit
fi
count=$(find "$folderNew" -type f |grep -v "DS_Store" |awk -F "/" '{print $NF}'|wc -l)
printf "\nFound/processing %s files in the %s folder\n\n" "$count" "$folderNew"
# determine parent directory name for each project name and create a map for them
while IFS= read -r -d $'[=10=]' f; do
proj="${f##*/}" # remove dirname
proj="${proj%.*}" # remove extention
parent="${f##*$baseDir/}" # remove pathname until $baseDir
parent="${parent#*/}" # strip pathname one-level deeper
parent="${parent%/*}" # remove filename
# now we're mapping "projectOne 1.a" => "House/2018 01" e.g.
# echo "$proj" "=>" "$parent" # just for debugging
hash["$proj"]="$parent"
done < <(find "$folderOld" -type f -print0) # directory B
# iterate over files in A; move to archive directory C and remove files in B
while IFS= read -r -d $'[=10=]' f; do
proj="${f##*/}"
proj="${proj%.*}"
parent="${hash[$proj]}"
if [[ "$parent" = "" ]]; then
echo "parent of $f not found" # may not occur but just in case ..
else
# move from A to C
destdir="$folderArchive/$parent"
mkdir -p -- "$destdir"
mv -- "$f" "$destdir"
# remove relevant file(s) in B
for ext in "${workingTypes[@]}"; do
oldfile="$folderOld/$parent/$proj.${ext}"
[ -f "$oldfile" ] && rm -f -- "$oldfile"
done
fi
done < <(find "$folderNew" -type f -print0) # directory A
# clean-up: remove empty dirs in B
find "$folderOld" -type d -empty -print0 | xargs -r -0 rmdir --
说明：
- 您不必使用逗号来分隔数组中的元素。
- 你不应该把
$放在左边的变量名之前。 while IFS= ... done < <(find ...)语法是循环遍历find输出的惯用法。${parameter#word}类型的语法是parameter expansion从路径中提取子字符串。- 关联数组
hash将每个项目名称（例如 "projectOne 1.a"）映射到其父目录名称（例如 "House/2018 01". ）
某些命令中的 --是为可能以-开头的文件名做准备。 （这种保护可能看起来病态...）
如果您的 bash 早于 4.2，请告诉我。那我们就得想办法了。
编辑
这是 POSIX 兼容版本作为替代：
（显然，如果文件名包含换行符或转义字符 \x1b，脚本将不起作用。）
#!/bin/sh
execHome="intendedMachine"
baseDir="/home/library/projects"
folderNew="output"
folderOld="working"
folderArchive="archive"
workingTypes="jpg
svg
bmp
tiff
psd"
folderNew="$baseDir/$folderNew"
folderOld="$baseDir/$folderOld"
folderArchive="$baseDir/$folderArchive"
nl="
" # set to newline character
esc=$(/bin/echo -ne "3") # set to escape character
#esc=":" # if 3 does not work well, try another character
# substitute of reading a hash
# it relies on the context that IFS is set to $nl
read_lut() {
local i
local key
local val
local ret=""
for i in $lut; do
key="${i%${esc}*}"
val="${i#*${esc}}"
if [ "$key" = "" ]; then
# loop until the end and use the last value
ret="$val"
fi
done
echo "$ret"
}
# substitute of writing to a hash
write_lut() {
lut=$(printf "%s\n%s%c%s" "$lut" "" "$esc" "")
}
if [ "$(uname -n)" != "$execHome" ]; then
printf "Executed from %s; Run from %s for proper execution.\n" "$(uname -n)" "$execHome"
exit
fi
count=$(find "$folderNew" -type f |grep -v "DS_Store" |awk -F "/" '{print $NF}'|wc -l)
printf "\nFound/processing %s files in the %s folder\n\n" "$count" "$folderNew"
# determine parent directory name for each project name and create a map for them
ifs_bak="$IFS"
IFS="$nl"
for f in $(find "$folderOld" -type f); do
proj="${f##*/}" # remove dirname
proj="${proj%.*}" # remove extention
parent="${f##*$baseDir/}" # remove pathname until $baseDir
parent="${parent#*/}" # strip pathname one-level deeper
parent="${parent%/*}" # remove filename
# now we're mapping "projectOne 1.a" => "House/2018 01" e.g.
# echo "$proj" "=>" "$parent" # just for debugging
write_lut "$proj" "$parent"
done
# iterate over files in A; move to archive directory C and remove files in B
for f in $(find "$folderNew" -type f); do
proj="${f##*/}"
proj="${proj%.*}"
parent=$(read_lut "$proj")
if [ "$parent" = "" ]; then
echo "parent of $f not found" # may not occur but just in case ..
else
# move from A to C
destdir="$folderArchive/$parent"
mkdir -p -- "$destdir"
mv -- "$f" "$destdir"
# remove relevant file(s) in B
for ext in $workingTypes; do
oldfile="$folderOld/$parent/$proj.${ext}"
[ -f "$oldfile" ] && rm -f -- "$oldfile"
done
fi
done
# clean-up: remove empty dirs in B
find "$folderOld" -type d -empty -print0 | xargs -r -0 rmdir --
# restore IFS
IFS="$ifs_bak"