字节缓冲区解码为字符串时丢失数据
ByteBuffer Missing Data When decoded As string
我正在读取和写入 ByteBuffer
import org.assertj.core.api.Assertions;
import java.io.IOException;
import java.net.InetSocketAddress;
import java.nio.ByteBuffer;
import java.nio.ByteOrder;
import java.nio.charset.Charset;
import java.nio.charset.CharsetDecoder;
import java.nio.charset.CharsetEncoder;
public class Solution{
public static void main(String[] args) throws Exception{
final CharsetEncoder messageEncoder = Charset.forName("ISO-8859-1").newEncoder();
String message = "TRANSACTION IGNORED";
String carrierName= "CARR00AB";
int messageLength = message.length()+carrierName.length()+8;
System.out.println(" --------Fill data---------");
ByteBuffer messageBuffer = ByteBuffer.allocate(4096);
messageBuffer.order(ByteOrder.BIG_ENDIAN);
messageBuffer.putInt(messageLength);
messageBuffer.put(messageEncoder.encode(CharBuffer.wrap(carrierName)));
messageBuffer.put(messageEncoder.encode(CharBuffer.wrap(message)));
messageBuffer.put((byte) 0x2b);
messageBuffer.flip();
System.out.println("------------Extract Data Approach 1--------");
CharsetDecoder messageDecoder = Charset.forName("ISO-8859-1").newDecoder();
int lengthField = messageBuffer.getInt();
System.out.println("lengthField="+lengthField);
int responseLength = lengthField - 12;
System.out.println("responseLength="+responseLength);
String messageDecoded= messageDecoder.decode(messageBuffer).toString();
System.out.println("messageDecoded="+messageDecoded);
String decodedCarrier = messageDecoded.substring(0, carrierName.length());
System.out.println("decodedCarrier="+ decodedCarrier);
String decodedBody = messageDecoded.substring(carrierName.length(), messageDecoded.length() - 1);
System.out.println("decodedBody="+decodedBody);
Assertions.assertThat(messageLength).isEqualTo(lengthField);
Assertions.assertThat(decodedBody).isEqualTo(message);
Assertions.assertThat(decodedBody).isEqualTo(message);
ByteBuffer messageBuffer2 = ByteBuffer.allocate(4096);
messageBuffer2.order(ByteOrder.BIG_ENDIAN);
messageBuffer2.putInt(messageLength);
messageBuffer2.put(messageEncoder.encode(CharBuffer.wrap(carrierName)));
messageBuffer2.put(messageEncoder.encode(CharBuffer.wrap(message)));
messageBuffer2.put((byte) 0x2b);
messageBuffer2.flip();
System.out.println("---------Extract Data Approach 2--------");
byte [] data = new byte[messageBuffer2.limit()];
messageBuffer2.get(data);
String dataString =new String(data, "ISO-8859-1");
System.out.println(dataString);
}
}
它工作正常但后来我想重构它,请参阅上面代码中的方法 2
byte [] data = new byte[messageBuffer.limit()];
messageBuffer.get(data);
String dataString =new String(data, "ISO-8859-1");
System.out.println(dataString);
Output= #CARR00ABTRANSACTION IGNORED+
大家能帮我解释一下吗
为什么第二种方法解码时整数丢失了???
有没有办法在第二种方法中提取整数??
好的,所以您正在尝试从占用 4 bits
的缓冲区中读取 int
,然后在读取 4 bits
后尝试获取整个数据
我所做的是在读取 int 后调用 messageBuffer2.clear();
来解决这个问题。这是完整的代码
System.out.println(messageBuffer2.getInt());
byte[] data = new byte[messageBuffer2.limit()];
messageBuffer2.clear();
messageBuffer2.get(data);
String dataString = new String(data, StandardCharsets.ISO_8859_1);
System.out.println(dataString);
输出为:
35
#CARR0033TRANSACTION IGNORED+
编辑:所以基本上当您调用 clear
时,它会重置各种变量,还会重置它的位置,这就是它修复它的方式。
我正在读取和写入 ByteBuffer
import org.assertj.core.api.Assertions;
import java.io.IOException;
import java.net.InetSocketAddress;
import java.nio.ByteBuffer;
import java.nio.ByteOrder;
import java.nio.charset.Charset;
import java.nio.charset.CharsetDecoder;
import java.nio.charset.CharsetEncoder;
public class Solution{
public static void main(String[] args) throws Exception{
final CharsetEncoder messageEncoder = Charset.forName("ISO-8859-1").newEncoder();
String message = "TRANSACTION IGNORED";
String carrierName= "CARR00AB";
int messageLength = message.length()+carrierName.length()+8;
System.out.println(" --------Fill data---------");
ByteBuffer messageBuffer = ByteBuffer.allocate(4096);
messageBuffer.order(ByteOrder.BIG_ENDIAN);
messageBuffer.putInt(messageLength);
messageBuffer.put(messageEncoder.encode(CharBuffer.wrap(carrierName)));
messageBuffer.put(messageEncoder.encode(CharBuffer.wrap(message)));
messageBuffer.put((byte) 0x2b);
messageBuffer.flip();
System.out.println("------------Extract Data Approach 1--------");
CharsetDecoder messageDecoder = Charset.forName("ISO-8859-1").newDecoder();
int lengthField = messageBuffer.getInt();
System.out.println("lengthField="+lengthField);
int responseLength = lengthField - 12;
System.out.println("responseLength="+responseLength);
String messageDecoded= messageDecoder.decode(messageBuffer).toString();
System.out.println("messageDecoded="+messageDecoded);
String decodedCarrier = messageDecoded.substring(0, carrierName.length());
System.out.println("decodedCarrier="+ decodedCarrier);
String decodedBody = messageDecoded.substring(carrierName.length(), messageDecoded.length() - 1);
System.out.println("decodedBody="+decodedBody);
Assertions.assertThat(messageLength).isEqualTo(lengthField);
Assertions.assertThat(decodedBody).isEqualTo(message);
Assertions.assertThat(decodedBody).isEqualTo(message);
ByteBuffer messageBuffer2 = ByteBuffer.allocate(4096);
messageBuffer2.order(ByteOrder.BIG_ENDIAN);
messageBuffer2.putInt(messageLength);
messageBuffer2.put(messageEncoder.encode(CharBuffer.wrap(carrierName)));
messageBuffer2.put(messageEncoder.encode(CharBuffer.wrap(message)));
messageBuffer2.put((byte) 0x2b);
messageBuffer2.flip();
System.out.println("---------Extract Data Approach 2--------");
byte [] data = new byte[messageBuffer2.limit()];
messageBuffer2.get(data);
String dataString =new String(data, "ISO-8859-1");
System.out.println(dataString);
}
}
它工作正常但后来我想重构它,请参阅上面代码中的方法 2
byte [] data = new byte[messageBuffer.limit()];
messageBuffer.get(data);
String dataString =new String(data, "ISO-8859-1");
System.out.println(dataString);
Output= #CARR00ABTRANSACTION IGNORED+
大家能帮我解释一下吗
为什么第二种方法解码时整数丢失了???
有没有办法在第二种方法中提取整数??
好的,所以您正在尝试从占用 4 bits
的缓冲区中读取 int
,然后在读取 4 bits
我所做的是在读取 int 后调用 messageBuffer2.clear();
来解决这个问题。这是完整的代码
System.out.println(messageBuffer2.getInt());
byte[] data = new byte[messageBuffer2.limit()];
messageBuffer2.clear();
messageBuffer2.get(data);
String dataString = new String(data, StandardCharsets.ISO_8859_1);
System.out.println(dataString);
输出为:
35
#CARR0033TRANSACTION IGNORED+
编辑:所以基本上当您调用 clear
时,它会重置各种变量,还会重置它的位置,这就是它修复它的方式。