如何在 preg_replace 中保留数字和特殊字符
How to keep digit and special character in preg_replace
我想用 45 美元等价格更换 {goal} 牙套。例如
$pattern = /\{goal\}/
$replacement = .00
$subject = Final price is {goal}
所以函数看起来像
preg_replace('/\{goal\}/', '.00', 'Free shipping for all orders over {goal}');
实际输出应该是
Final price is .00
但我得到的输出是
Final price is .00
所以看起来 preg_replace 用空白字符串替换了整个数字和特殊字符。有什么办法可以保留吗
The $n will be replaced by the text captured by the n'th parenthesized pattern. manual
当您使用 '.00' php 时，将其视为第 45 个捕获组。所以你应该通过 \ 逃避 $ 来解决问题
preg_replace('/\{goal\}/', '$45.00', 'Free shipping for all orders over {goal}');
我想用 45 美元等价格更换 {goal} 牙套。例如
$pattern = /\{goal\}/
$replacement = .00
$subject = Final price is {goal}
所以函数看起来像
preg_replace('/\{goal\}/', '.00', 'Free shipping for all orders over {goal}');
实际输出应该是
Final price is .00
但我得到的输出是
Final price is .00
所以看起来 preg_replace 用空白字符串替换了整个数字和特殊字符。有什么办法可以保留吗
The
$nwill be replaced by the text captured by then'thparenthesized pattern. manual
当您使用 '.00' php 时，将其视为第 45 个捕获组。所以你应该通过 \ 逃避 $ 来解决问题
preg_replace('/\{goal\}/', '$45.00', 'Free shipping for all orders over {goal}');