set 不包含等于其成员之一的项目？

Question

所以根据the Java API,Set::contains

returns true if and only if this set contains an element e such that (o==null ? e==null : o.equals(e))

所以...为什么即使集合只包含一个等于 creds 的元素，这种方法 returns 还是 false？

private boolean validate(Credentials creds){
    Set<Credentials> acceptedUsers = getAcceptedUsers();
    return acceptedUsers.contains(creds);
}

更具体地说，我插入了一些 printlns

private boolean validate(Credentials creds){
    Set<Credentials> acceptedUsers = getAcceptedUsers();

    System.out.print("accepted users: ");
    System.out.println(acceptedUsers);
    System.out.print("accessing user: ");
    System.out.println(creds);
    System.out.println("items are equal: " + acceptedUsers.stream().map(c -> c.equals(creds)).collect(Collectors.toSet()));
    System.out.println("access ok: " + (acceptedUsers.contains(creds) ? "YES" : "NO"));

    return acceptedUsers.contains(creds);
}

这就是它所说的：

accepted users: [[
    foo
    FCDE2B2EDBA56BF408601FB721FE9B5C338D10EE429EA04FAE5511B68FBF8FB9
]]
accessing user: [
    foo
    FCDE2B2EDBA56BF408601FB721FE9B5C338D10EE429EA04FAE5511B68FBF8FB9
]
items are equal: [true]
access ok: NO

getAcceptedUsers目前returns一个虚拟集

private Set<Credentials> getAcceptedUsers(){
    return new HashSet<Credentials>(){{add(new Credentials("foo","bar", false));}};
}

和Credentials实现为

class Credentials{
    final String username;
    final String password;

    public Credentials(String username, String password, boolean isPasswordHashed) {
        this.username = username;

        if(isPasswordHashed) this.password = password;
        else {
            MessageDigest md;
            try {
                md = MessageDigest.getInstance("SHA-256");
            } catch (NoSuchAlgorithmException e) {
                throw new IllegalStateException(e);
            }

            md.update(password.getBytes());
            byte[] hash = md.digest();

            this.password = (new HexBinaryAdapter()).marshal(hash);
        }
    }

    @Override
    public boolean equals(Object obj) {
        if(obj == null) return false;
        if(!(obj instanceof Credentials)) return false;
        Credentials other = (Credentials)obj;
        return this.username.equals(other.username) && this.password.equals(other.password);
    }

    @Override
    public String toString() {
        return String.format("[\n\t%s\n\t%s\n]", username,password);
    }
}

Answer 1

实施 equals 方法还不够，您还必须实施 hashCode。

喜欢你可以阅读here:

Returns the hash code value for this set. The hash code of a set is defined to be the sum of the hash codes of the elements in the set, where the hash code of a null element is defined to be zero. This ensures that s1.equals(s2) implies that s1.hashCode()==s2.hashCode() for any two sets s1 and s2, as required by the general contract of Object.hashCode().

Answer 2

如果您想使用 HashMap 或 HashSet，您需要重写 hashCode() 方法，以便相等的对象具有相同的哈希码。例如：

@Override
public int hashCode() {
    return Objects.hash(username, password);
}

set 不包含等于其成员之一的项目？

set does not contain an item that equals one of its members?

java

contains

equals

set