将不同的列表值添加到 python 中的字典

Question

我有三个列表，其中包含不同的值模式。如果condition.I尝试了以下方法，这应该仅在单个字典内附加特定值，但我从列表中获得了所有值。

class_list = [1,2,3,4,5,6]

boxes = [[0.1,0.2,0.3,0.4],[0.5,0.7,0.8,0.9],[0.7,0.9,0.4,0.2],[0.9,0.7,0.6,0.3],[0.9,0.14,0.6,0.3],[0.9,0.7,0.6,0.13]]

scores = [0.98,0.87,0.97,0.96,0.94,0.92]

k=1;

data = {}

for a in scores:
    for b in boxes:
        for c in list:
            if a >= 0.98:
                data[k+1] = {"score":a,"box":b, "class": c } ;
                k=k+1;
print("Final_result",data)

Answer 1

也许使用 zip:

for a,b,c in zip(scores,boxes,class_list):
   if a >= 0.98:
       data[k+1] = {"score":a,"box":b, "class": c } ;
       k=k+1;
print("Final_result",data)

输出：

Final_result {2: {'score': 0.98, 'box': [0.1, 0.2, 0.3, 0.4], 'class': 1}}

编辑：

for a,b,c in zip(scores,boxes,class_list):
   if a >= 0.98:
       data[k+1] = {"score":a,"box":b, "class": int(c) } ;
       k=k+1;
print("Final_result",data)

Answer 2

您正在获取所有值，因为您正在使用所有其他值遍历所有值，即 6x6x6 次。我明白你的问题，你需要使用的是 Zip 功能。

llist = [1,2,3,4,5,6]

boxes = [[0.1,0.2,0.3,0.4],[0.5,0.7,0.8,0.9],[0.7,0.9,0.4,0.2],[0.9,0.7,0.6,0.3],[0.9,0.14,0.6,0.3],[0.9,0.7,0.6,0.13]]

scores = [0.98,0.87,0.97,0.96,0.94,0.92]

k=1;

data = {}



for a,b,c in zip(scores, boxes, llist):
    if a >= 0.98:
        data[k] = {"score":a,"box":b, "class": c } ;
        k = k + 1

for k in data.keys():
    print(k , data[k])

ps: 避免使用关键字命名变量，list 是一个关键字。可能会遇到问题，您甚至可以找到原因。

将不同的列表值添加到 python 中的字典

Appeding different list values to dictionary in python

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