当列类型为 nvarchar 时,旋转 table 以及列值的总和
Pivoting a table along with sum of column value when column type is nvarchar
我有一个具有以下结构的 table。我想转置它。
BookId Status
----------------------
123A Perfect
123B Restore
123C Lost
123D Perfect
123A Perfect
123B Restore
123A Lost
123B Restore
我需要转置 table 看起来像这样。
输出
BookId Total Perfect Restore Lost
-----------------------------------------
123A 3 2 0 1
123B 3 0 3 0
123C 1 0 0 1
123D 1 1 0 0
我试过了
select
BookId,
sum('Perfect') as Perfect,
sum('Restore') as Restore
from
[dbo].[Orders]
group by
BookId
但由于这些是 nvarchar
值,因此 sum
无效。我收到这个错误
我对 Pivot 的了解不多。但尝试关注
select *
from
(select SellerAddress, ApplicationStatus
from [Farm_For_Books].[dbo].[Orders]) src
pivot
(sum(ApplicationStatus)
for SellerAddress in ([1], [2], [3])
) piv;
conditional aggregation
可能会被使用
with Orders( BookId, Status ) as
(
select '123A','Perfect' union all
select '123B','Restore' union all
select '123C','Lost' union all
select '123D','Perfect' union all
select '123A','Perfect' union all
select '123B','Restore' union all
select '123A','Lost' union all
select '123B','Restore'
)
select
BookId,
sum(1) as [Total],
sum(case when Status='Perfect' then 1 else 0 end ) as [Perfect],
sum(case when Status='Restore' then 1 else 0 end ) as [Restore],
sum(case when Status='Lost' then 1 else 0 end ) as [Lost]
from
[Orders]
group by BookId;
BookId Total Perfect Restore Lost
123A 3 2 0 1
123B 3 0 3 0
123C 1 0 0 1
123D 1 1 0 0
我有一个具有以下结构的 table。我想转置它。
BookId Status
----------------------
123A Perfect
123B Restore
123C Lost
123D Perfect
123A Perfect
123B Restore
123A Lost
123B Restore
我需要转置 table 看起来像这样。
输出
BookId Total Perfect Restore Lost
-----------------------------------------
123A 3 2 0 1
123B 3 0 3 0
123C 1 0 0 1
123D 1 1 0 0
我试过了
select
BookId,
sum('Perfect') as Perfect,
sum('Restore') as Restore
from
[dbo].[Orders]
group by
BookId
但由于这些是 nvarchar
值,因此 sum
无效。我收到这个错误
我对 Pivot 的了解不多。但尝试关注
select *
from
(select SellerAddress, ApplicationStatus
from [Farm_For_Books].[dbo].[Orders]) src
pivot
(sum(ApplicationStatus)
for SellerAddress in ([1], [2], [3])
) piv;
conditional aggregation
可能会被使用
with Orders( BookId, Status ) as
(
select '123A','Perfect' union all
select '123B','Restore' union all
select '123C','Lost' union all
select '123D','Perfect' union all
select '123A','Perfect' union all
select '123B','Restore' union all
select '123A','Lost' union all
select '123B','Restore'
)
select
BookId,
sum(1) as [Total],
sum(case when Status='Perfect' then 1 else 0 end ) as [Perfect],
sum(case when Status='Restore' then 1 else 0 end ) as [Restore],
sum(case when Status='Lost' then 1 else 0 end ) as [Lost]
from
[Orders]
group by BookId;
BookId Total Perfect Restore Lost
123A 3 2 0 1
123B 3 0 3 0
123C 1 0 0 1
123D 1 1 0 0