Collectors.groupby 地图<String,List<String>

Question

如果解决方案非常明显但我似乎不知道该怎么做，请原谅我

public static void main(String[] args) {
    Map<String, String> map = new HashMap<>();
    map.put("b1", "a1");
    map.put("b2", "a2");
    map.put("b3", "a1");
    Map<String, List<String>> mm = map.values().stream().collect(Collectors.groupingBy(m -> m));
    System.out.println(mm);
}

我想根据哈希图中的值进行分组。我希望输出为 {a1=[b1, b3], a2=[b2]}，但目前为 {a1=[a1, a1], a2=[a2]}

Answer 1

目前，您正在对地图值进行流式传输（我认为这是一个拼写错误），根据您需要的输出，您应该对地图进行流式传输 entrySet 并使用 groupingBy 基于映射值和 mapping 作为基于映射键的下游收集器：

 Map<String, List<String>> result = map.entrySet()
            .stream()
            .collect(Collectors.groupingBy(Map.Entry::getValue,
                          Collectors.mapping(Map.Entry::getKey, 
                                        Collectors.toList())));

您也可以通过 forEach + computeIfAbsent:

在没有流的情况下执行此逻辑

Map<String, List<String>> result = new HashMap<>();
map.forEach((k, v) -> result.computeIfAbsent(v, x -> new ArrayList<>()).add(k));

Answer 2

您可以在地图 entrySet 上使用 Collectors.mapping with Collectors.groupingBy 作为 :

Map<String, List<String>> mm = map.entrySet()
        .stream()
        .collect(Collectors.groupingBy(Map.Entry::getValue, 
                Collectors.mapping(Map.Entry::getKey, Collectors.toList())));

but it is currently coming as {a1=[a1, a1], a2=[a2]}

那是因为您目前正在对仅 {a1, a2, a1} 的值集合进行分组。

Answer 3

public class Test5 {

    public static void main(String[] args) {

        List<String> list1 = List.of("Tabu", "Gina", "protijayi", "Gini", "Gini","North Calcutta");
        List<String> list2 = List.of("Soudipta", "Gina", "Gina", "upto");
        List<String> list3 = List.of("Soudipta", "Gina", "protijayi", "Tabu","South Calcutta");
        List<List<String>> listres = List.of(list1, list2, list3);
        System.out.println(listres);
/*
 [[Tabu, Gina, protijayi, Gini, Gini, North Calcutta], 
[Soudipta, Gina, Gina, upto],
 [Soudipta, Gina, protijayi, Tabu, South Calcutta]]

 */



        Map<String, List<Long>> FirstKeyThenValue1 = listres.stream().flatMap(
                // mapper

                list -> list.stream().collect(Collectors.groupingBy(Function.identity(), Collectors.counting()))
                        .entrySet().parallelStream()

        ).collect(Collectors.groupingBy(Entry::getKey, Collectors.mapping(
                // mapper, downstream

                Entry::getValue, Collectors.toList())));
        System.out.println("FirstKeyThenValue1  -> " + FirstKeyThenValue1);
        /*
         {
  upto=[1],
   Soudipta=[1, 1],
    Gina=[1, 2, 1], 
    Tabu=[1, 1],
     North Calcutta=[1], 
     South Calcutta=[1], 
     protijayi=[1, 1], 
     Gini=[2]}
         */

        Map<Long, List<String>> FirstValueThenkey1 = listres.stream().flatMap(
                // mapper

                list -> list.stream().collect(Collectors.groupingBy(Function.identity(), Collectors.counting()))
                        .entrySet().stream()

        ).collect(

                Collectors.groupingBy(Entry::getValue, Collectors.mapping(


                        Entry::getKey, Collectors.toList()

                ))

        );

        System.out.println(" FirstValueThenkey1 => " + FirstValueThenkey1);

        /*


  {
  1=[Gina, Tabu, North Calcutta, protijayi, upto, Soudipta,
   Soudipta, Gina, Tabu, South Calcutta, protijayi],

 2=[Gini, Gina]
 }
         */





    }// main
}

Collectors.groupby 地图<String,List<String>

Collectors.groupby for Map<String,List<String>

java

java-8

java-stream

collectors