在 FabricJS 中,如何通过鼠标点击坐标处重叠的一组对象来识别?
In FabricJS, how can I identify through a set of objects that overlap at the coordinates where the mouse is clicked?
我需要能够遍历一组对象,这些对象在单击鼠标的坐标处相互重叠。作为后续,我会使用 bringToFront,然后根据该对象显示一个漂亮的菜单,但我不确定如何识别和迭代对象集。
我的具体需要是通过按 Tab 键设置活动 object/group 来迭代一组重叠对象。以下是我所做的:
var stackArray = new Array();
canvas.on('mouse:down', function(e){
var subobj = canvas.getObjects();
stackArray = [];
for (var i=0;i<subobj.length;i++) {
if (subobj[i].id != '' && typeof(subobj[i].id) != 'undefined' && subobj[i].id != 'navpanel' && subobj[i].id != 'header') {
if (e.target!=null && typeof(e.target.id) != 'undefined') {
if (subobj[i].intersectsWithObject(canvas.getActiveObject()) && subobj[i].id != e.target.id) {
stackArray.push(subobj[i]);
} else if (subobj[i].id == e.target.id) {
stackArray.push(subobj[i]);
}
}
}
}
});
...
e.preventDefault();
switch(e.keyCode){
case 9: // tab
if (stackArray.length > 1) {
fillObj(canvas.getActiveObject(),'inactive');
canvas.getActiveObject().sendToBack();
canvas.setActiveObject(stackArray[stackArray.length-1]);
fillObj(canvas.getActiveObject(),'active');
stackArray.splice(0, 0, stackArray.splice(stackArray.length-1,1)[0]);
}
break;
}
function fillObj(obj,mode) {
if (obj.type == 'group') {
obj = obj.item(0);
}
if (mode == 'active') {
obj.set('fill', 'red');
obj.set('strokeWidth', 1);
obj.set('shadow','rgba(0,0,0,0.5) 5px 5px 15px');
} else if (mode == 'inactive') {
obj.set('fill', '#333');
obj.set('strokeWidth', 0);
obj.set('shadow','');
}
}
我需要能够遍历一组对象,这些对象在单击鼠标的坐标处相互重叠。作为后续,我会使用 bringToFront,然后根据该对象显示一个漂亮的菜单,但我不确定如何识别和迭代对象集。
我的具体需要是通过按 Tab 键设置活动 object/group 来迭代一组重叠对象。以下是我所做的:
var stackArray = new Array();
canvas.on('mouse:down', function(e){
var subobj = canvas.getObjects();
stackArray = [];
for (var i=0;i<subobj.length;i++) {
if (subobj[i].id != '' && typeof(subobj[i].id) != 'undefined' && subobj[i].id != 'navpanel' && subobj[i].id != 'header') {
if (e.target!=null && typeof(e.target.id) != 'undefined') {
if (subobj[i].intersectsWithObject(canvas.getActiveObject()) && subobj[i].id != e.target.id) {
stackArray.push(subobj[i]);
} else if (subobj[i].id == e.target.id) {
stackArray.push(subobj[i]);
}
}
}
}
});
...
e.preventDefault();
switch(e.keyCode){
case 9: // tab
if (stackArray.length > 1) {
fillObj(canvas.getActiveObject(),'inactive');
canvas.getActiveObject().sendToBack();
canvas.setActiveObject(stackArray[stackArray.length-1]);
fillObj(canvas.getActiveObject(),'active');
stackArray.splice(0, 0, stackArray.splice(stackArray.length-1,1)[0]);
}
break;
}
function fillObj(obj,mode) {
if (obj.type == 'group') {
obj = obj.item(0);
}
if (mode == 'active') {
obj.set('fill', 'red');
obj.set('strokeWidth', 1);
obj.set('shadow','rgba(0,0,0,0.5) 5px 5px 15px');
} else if (mode == 'inactive') {
obj.set('fill', '#333');
obj.set('strokeWidth', 0);
obj.set('shadow','');
}
}