检查按下了哪个 gestureRecognizer
Checking which gestureRecognizer was pressed
我使用 gestureRecognizer
和 UIImageView
。我有两个 UIImageView
。我需要在 UIImageView
中上传图片。为了打开 UIImagePickerController()
,我在两个 UIImageView
上都使用 gestureRecognizer
。
所以我需要在 func imagePickerController(_ picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [String : Any])
中以不同的 UIImageView
上传图片
如何从库中上传图片?
这是我的代码:
@IBOutlet weak var mainPhotoImageView: UIImageView!
@IBOutlet weak var addImageView: UIImageView!
override func viewDidLoad() {
super.viewDidLoad()
configureGestureRecognizer()
}
func imagePickerController(_ picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [String : Any]) {
let chosenImage = info[UIImagePickerControllerEditedImage] as? UIImage
if chosenImage != nil {
logoImageView.image = chosenImage
dismiss(animated: true, completion: nil)
}
}
@objc func addLogoHall(_ sender: AnyObject) {
let picker = UIImagePickerController()
picker.delegate = self
picker.allowsEditing = true
picker.sourceType = .photoLibrary
present(picker, animated: true, completion: nil)
}
@objc func addMainPhoto(_ sender: AnyObject) {
let picker = UIImagePickerController()
picker.delegate = self
picker.allowsEditing = true
picker.sourceType = .photoLibrary
present(picker, animated: true, completion: nil)
}
func configureGestureRecognizer() {
let addHallLogo = UITapGestureRecognizer(target: self, action: #selector(AddPhotoAndLogoViewController.addLogoHall(_:)))
logoImageView.isUserInteractionEnabled = true
logoImageView.addGestureRecognizer(addHallLogo)
let addMainPhotoImage = UITapGestureRecognizer(target: self, action: #selector(AddPhotoAndLogoViewController.addMainPhoto(_:)))
mainPhotoImageView.isUserInteractionEnabled = true
mainPhotoImageView.addGestureRecognizer(addMainPhotoImage)
}
所以在 func imagePickerController
中,我需要检测使用了哪个 gestureRecognizer
。或者也许有其他机会去做?
您可以像这样为选择器使用不同的标签:
@objc func addLogoHall(_ sender: AnyObject) {
let picker = UIImagePickerController()
picker.delegate = self
picker.allowsEditing = true
picker.sourceType = .photoLibrary
picker.view.tag = 1
present(picker, animated: true, completion: nil)
}
@objc func addMainPhoto(_ sender: AnyObject) {
let picker = UIImagePickerController()
picker.delegate = self
picker.allowsEditing = true
picker.view.tag = 2
picker.sourceType = .photoLibrary
present(picker, animated: true, completion: nil)
}
然后你可以像这样通过这个标签来识别:
func imagePickerController(_ picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [String : Any]) {
let chosenImage = info[UIImagePickerControllerEditedImage] as? UIImage
if chosenImage != nil {
if(picker.view.tag == 1) {
logoImageView.image = chosenImage
} else {
mainImageView.image = chosenImage
}
dismiss(animated: true, completion: nil)
}
}
虽然 Jogendar 的回答很好,但我看到了一个陷阱。 if-else 将随着视图控制器文件中图像视图实例数量的增加而增长。这可能会很快变得混乱和不必要的大。我可以建议一个替代解决方案:
class ImageSelectionController: NSObject, UIImagePickerControllerDelegate, UINavigationControllerDelegate {
weak var delegate: ImageSelectionControllerDelegate?
private weak var imageView: UIImageView?
private weak var presentingViewController: UIViewController?
// MARK: - Initialization
init(withImageView imageView: UIImageView?, andPresentingViewController viewController: UIViewController?) {
self.imageView = imageView
self.presentingViewController = viewController
}
// MARK: - Public
func presentImagePickerController(withConfigurationHandler handler: ((UIImagePickerController) -> Void)? = nil) -> Void {
let picker = UIImagePickerController()
picker.allowsEditing = true
picker.sourceType = .photoLibrary
handler?(picker)
picker.delegate = self
}
// MARK: - UIImagePickerController
func imagePickerController(_ picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [String : Any]) {
let chosenImage = info[UIImagePickerControllerEditedImage] as? UIImage
self.imageView?.image = chosenImage
self.delegate?.controller(self, didFinishPickingImage: chosenImage, forImageView: self.imageView)
picker.dismiss(animated: true, completion: nil)
}
}
protocol ImageSelectionControllerDelegate: AnyObject {
func controller(_ controller: ImageSelectionController, didFinishPickingImage image: UIImage?, forImageView: UIImageView?) -> Void
}
// ---- 你的视图控制器 ---- //
@IBOutlet weak var logoImageView: UIImageView?
@IBOutlet weak var mainPhotoImageView: UIImageView?
override func viewDidLoad() {
super.viewDidLoad()
configureGestureRecognizer()
}
@objc func addLogoHall(_ sender: AnyObject) {
let controller = ImageSelectionController.init(withImageView: self.logoImageView, andPresentingViewController: self)
controller.delegate = self
controller.presentImagePickerController()
}
@objc func addMainPhoto(_ sender: AnyObject) {
let controller = ImageSelectionController.init(withImageView: self.logoImageView, andPresentingViewController: self)
controller.presentImagePickerController { (picker) in
picker.sourceType = .camera
}
}
// MARK: - ImageSelectionControllerDelegate
func controller(_ controller: ImageSelectionController, didFinishPickingImage image: UIImage?, forImageView: UIImageView?) {
print("image picked!")
}
这样做,您可以将所有 UIImagePickerController
相关代码放在一个地方,并且您不需要任何 if-else 情况。同样,没有正确或错误的答案,有人可能还会在我的解决方案中发现其他缺陷。这只是您想要如何构建代码的问题。
编码愉快!
我使用 gestureRecognizer
和 UIImageView
。我有两个 UIImageView
。我需要在 UIImageView
中上传图片。为了打开 UIImagePickerController()
,我在两个 UIImageView
上都使用 gestureRecognizer
。
所以我需要在 func imagePickerController(_ picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [String : Any])
UIImageView
上传图片
如何从库中上传图片?
这是我的代码:
@IBOutlet weak var mainPhotoImageView: UIImageView!
@IBOutlet weak var addImageView: UIImageView!
override func viewDidLoad() {
super.viewDidLoad()
configureGestureRecognizer()
}
func imagePickerController(_ picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [String : Any]) {
let chosenImage = info[UIImagePickerControllerEditedImage] as? UIImage
if chosenImage != nil {
logoImageView.image = chosenImage
dismiss(animated: true, completion: nil)
}
}
@objc func addLogoHall(_ sender: AnyObject) {
let picker = UIImagePickerController()
picker.delegate = self
picker.allowsEditing = true
picker.sourceType = .photoLibrary
present(picker, animated: true, completion: nil)
}
@objc func addMainPhoto(_ sender: AnyObject) {
let picker = UIImagePickerController()
picker.delegate = self
picker.allowsEditing = true
picker.sourceType = .photoLibrary
present(picker, animated: true, completion: nil)
}
func configureGestureRecognizer() {
let addHallLogo = UITapGestureRecognizer(target: self, action: #selector(AddPhotoAndLogoViewController.addLogoHall(_:)))
logoImageView.isUserInteractionEnabled = true
logoImageView.addGestureRecognizer(addHallLogo)
let addMainPhotoImage = UITapGestureRecognizer(target: self, action: #selector(AddPhotoAndLogoViewController.addMainPhoto(_:)))
mainPhotoImageView.isUserInteractionEnabled = true
mainPhotoImageView.addGestureRecognizer(addMainPhotoImage)
}
所以在 func imagePickerController
中,我需要检测使用了哪个 gestureRecognizer
。或者也许有其他机会去做?
您可以像这样为选择器使用不同的标签:
@objc func addLogoHall(_ sender: AnyObject) {
let picker = UIImagePickerController()
picker.delegate = self
picker.allowsEditing = true
picker.sourceType = .photoLibrary
picker.view.tag = 1
present(picker, animated: true, completion: nil)
}
@objc func addMainPhoto(_ sender: AnyObject) {
let picker = UIImagePickerController()
picker.delegate = self
picker.allowsEditing = true
picker.view.tag = 2
picker.sourceType = .photoLibrary
present(picker, animated: true, completion: nil)
}
然后你可以像这样通过这个标签来识别:
func imagePickerController(_ picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [String : Any]) {
let chosenImage = info[UIImagePickerControllerEditedImage] as? UIImage
if chosenImage != nil {
if(picker.view.tag == 1) {
logoImageView.image = chosenImage
} else {
mainImageView.image = chosenImage
}
dismiss(animated: true, completion: nil)
}
}
虽然 Jogendar 的回答很好,但我看到了一个陷阱。 if-else 将随着视图控制器文件中图像视图实例数量的增加而增长。这可能会很快变得混乱和不必要的大。我可以建议一个替代解决方案:
class ImageSelectionController: NSObject, UIImagePickerControllerDelegate, UINavigationControllerDelegate {
weak var delegate: ImageSelectionControllerDelegate?
private weak var imageView: UIImageView?
private weak var presentingViewController: UIViewController?
// MARK: - Initialization
init(withImageView imageView: UIImageView?, andPresentingViewController viewController: UIViewController?) {
self.imageView = imageView
self.presentingViewController = viewController
}
// MARK: - Public
func presentImagePickerController(withConfigurationHandler handler: ((UIImagePickerController) -> Void)? = nil) -> Void {
let picker = UIImagePickerController()
picker.allowsEditing = true
picker.sourceType = .photoLibrary
handler?(picker)
picker.delegate = self
}
// MARK: - UIImagePickerController
func imagePickerController(_ picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [String : Any]) {
let chosenImage = info[UIImagePickerControllerEditedImage] as? UIImage
self.imageView?.image = chosenImage
self.delegate?.controller(self, didFinishPickingImage: chosenImage, forImageView: self.imageView)
picker.dismiss(animated: true, completion: nil)
}
}
protocol ImageSelectionControllerDelegate: AnyObject {
func controller(_ controller: ImageSelectionController, didFinishPickingImage image: UIImage?, forImageView: UIImageView?) -> Void
}
// ---- 你的视图控制器 ---- //
@IBOutlet weak var logoImageView: UIImageView?
@IBOutlet weak var mainPhotoImageView: UIImageView?
override func viewDidLoad() {
super.viewDidLoad()
configureGestureRecognizer()
}
@objc func addLogoHall(_ sender: AnyObject) {
let controller = ImageSelectionController.init(withImageView: self.logoImageView, andPresentingViewController: self)
controller.delegate = self
controller.presentImagePickerController()
}
@objc func addMainPhoto(_ sender: AnyObject) {
let controller = ImageSelectionController.init(withImageView: self.logoImageView, andPresentingViewController: self)
controller.presentImagePickerController { (picker) in
picker.sourceType = .camera
}
}
// MARK: - ImageSelectionControllerDelegate
func controller(_ controller: ImageSelectionController, didFinishPickingImage image: UIImage?, forImageView: UIImageView?) {
print("image picked!")
}
这样做,您可以将所有 UIImagePickerController
相关代码放在一个地方,并且您不需要任何 if-else 情况。同样,没有正确或错误的答案,有人可能还会在我的解决方案中发现其他缺陷。这只是您想要如何构建代码的问题。
编码愉快!