MessagingStyle 未正确显示 "You"

MessagingStyle Not Displaying "You" Properly

Android 开发新手,使用最新的 MessagingStyle 代码。来自你的消息显示正确的图标,但是,对于名字,我期待你而不是收件人的名字,就像内置的消息应用程序一样。不确定这是否与 Kotlin 相关。

任何想法表示赞赏 - compileSdkVersiontargetSdkVersion 都是 28。

我看到的例子是:

通知方法及相关(删除不太重要的代码):

fun notifyTest(context: Context, upcoming: UpcomingDetail, top3Sent: List<String>?) {
    //...

    @TargetApi(Build.VERSION_CODES.P)
    when (Build.VERSION.SDK_INT) {
        in 1..27 -> {
            with(NotificationManagerCompat.from(context)) {
                notify(upcoming.id.toInt(), legacyNotificationBuilder(
                        context,
                        upcoming,
                        noteIntent,
                        contentPending,
                        disablePending,
                        deletePending,
                        postponePending,
                        top3Sent
                ).build())
            }
        }
        else -> context.getSystemService(NotificationManager::class.java)
                .notify(upcoming.id.toInt(), notificationBuilder(
                        context,
                        upcoming,
                        noteIntent,
                        contentPending,
                        disablePending,
                        deletePending,
                        postponePending,
                        top3Sent
                ).build())
    }
}

@RequiresApi(Build.VERSION_CODES.P)
private fun notificationBuilder(
        context: Context,
        upcoming: UpcomingDetail,
        noteIntent: Intent,
        contentPending: PendingIntent,
        deletePending: PendingIntent,
        disablePending: PendingIntent,
        postponePending: PendingIntent,
        top3Sent: List<String>?
): Notification.Builder {
    val recipient: android.app.Person = android.app.Person.Builder().setName("Darren").setImportant(true).build()
    val you: android.app.Person? = null

    val messageStyle = Notification.MessagingStyle(recipient)
    messageStyle.addMessage(Notification.MessagingStyle.Message("What's up?", Instant.now().minusSeconds(5 * 60).toEpochMilli(), recipient))
    messageStyle.addMessage(Notification.MessagingStyle.Message("Doing great!", Instant.now().toEpochMilli(), you))

    //...

    return Notification.Builder(context, "Input").apply {
        setSmallIcon(R.drawable.ic_stat)
        style = messageStyle
        setAutoCancel(true)
        setCategory(Notification.CATEGORY_REMINDER)
        setColor(ContextCompat.getColor(context, R.color.secondaryDarkColor))
        setContentIntent(contentPending)
        setDeleteIntent(deletePending)
        setGroup("notifications")
        setOnlyAlertOnce(true)
        setVisibility(Notification.VISIBILITY_PRIVATE)
        addAction(inputAction)
    }
}

你必须做两件事:

  1. 将 You-person 传递给 Notification.MessagingStyle 构造函数,而不是接收者。
  2. 将 null 传递给来自 You-person 的每个 Notification.MessagingStyle.Message。由于新的 API,Kotlin 中存在一个小问题,因为它的类型是 Person,而不是 Person?.

我刚刚检查了这段代码,它像你想要的那样工作:

val recipient: Person = Person.Builder().setName("Darren").build()
val you: Person = Person.Builder().setName("You").build()
val nullPerson: Person? = null

val messageStyle = Notification.MessagingStyle(you) // pass you-person here
messageStyle.addMessage(Notification.MessagingStyle.Message("What's up?", timestamp1, recipient))
messageStyle.addMessage(Notification.MessagingStyle.Message("Doing great!", timestamp2, nullPerson)) // pass to null for a message to display `You`