如何检查子视图控制器是否存在

How can I check if a child view controller exists

我正在实现样式菜单中的幻灯片。

菜单被添加为显示的子视图控制器,然后以动画形式进入视图。然后我在它关闭后将其从视图中删除。

我想介绍一个 UIPanGestureRecognizer 以便用户可以将其滑动到视图中,但是添加视图的逻辑仅在按下打开时触发。

我想避免在每个手势上多次添加它,所以我在考虑检查它是否存在,如果不添加,则设置动画。

惰性 var menuController = MenuController()

private var menuWidth: CGFloat = 300
private let keyWindow = UIApplication.shared.keyWindow

override func viewDidLoad() {
    super.viewDidLoad()

    setupNavigationItems()
    setupTableView()

    menuController.view.frame = CGRect(x: -menuWidth, y: 0, width: menuWidth, height: view.frame.height)

    let panGesture = UIPanGestureRecognizer(target: self, action: #selector(handlePan))
    view.addGestureRecognizer(panGesture)

}

@objc func handlePan(gesture: UIPanGestureRecognizer) {


    let translation = gesture.translation(in: view)
    let transform = CGAffineTransform(translationX: translation.x, y: 0)
    menuController.view.transform = transform
    navigationController?.view.transform = transform

}

@objc func handleOpen() {
    keyWindow?.addSubview(menuController.view)
    animateMenuController(transform: CGAffineTransform(translationX: self.menuWidth, y: 0)) { }

    addChild(menuController)

}

@objc func handleHide() {
    animateMenuController(transform: .identity) { [weak self] in
        self?.menuController.view.removeFromSuperview()
        self?.menuController.removeFromParent()
    }
}

我希望做这样的事情

    @objc func handlePan(gesture: UIPanGestureRecognizer) {

        if view.subviews.contains(MenuController) {
            print("yes")
        }


        let translation = gesture.translation(in: view)
        let transform = CGAffineTransform(translationX: translation.x, y: 0)
        menuController.view.transform = transform
        navigationController?.view.transform = transform

    }

但这是不正确的。

你可以尝试使用childrens属性的vc

if !children.isEmpty { // this assumes 1 vc tell if you have more
   print("YES")  
}

if let _ = children.first(where:{ [=11=] is menuController})  {  // this assumes 1 vc tell if you have more
   print("YES")  
}

您可能还需要将其添加到

 view.addSubview(menuController.view)

不会keyWindow

您可以根据您的 class 姓名检查 classForCoder

if children.first(where: { String(describing: [=10=].classForCoder) == "MenuController" }) != nil {
    print("we have one")
}

这确实引入了 "magic string",但是因为简单地更改您的 class 名称会破坏此逻辑。