C# xls 和 xlsx 查询从 sheet 中选择而不考虑 sheet 名称

Question

这是我的GetData方法：

    private DataTable GetData(string userFileName)
    {
        string dirName = Path.GetDirectoryName(userFileName);
        string fileName = Path.GetFileName(userFileName);
        string fileExtension = Path.GetExtension(userFileName);
        string connection = string.Empty;
        string query = string.Empty;

        switch (fileExtension)
        {
            case ".xls":
                connection = $@"Provider=Microsoft.Jet.OLEDB.4.0;Data Source={userFileName};" +
                               "Extended Properties=\"Excel 8.0; HDR=Yes; IMEX=1\"";
                query = "SELECT * FROM [Sheet1$]";
                break;

            case ".xlsx":
                connection = $@"Provider=Microsoft.ACE.OLEDB.12.0;Data Source={userFileName};" +
                               "Extended Properties=\"Excel 12.0; HDR=Yes; IMEX=1\"";
                query = "SELECT * FROM [Sheet1$]";
                break;

            case ".csv":
                connection = $@"Provider=Microsoft.ACE.OLEDB.12.0;Data Source={dirName};" +
                               "Extended Properties=\"text; HDR=Yes; IMEX=1; FMT=Delimited\"";
                query = $"SELECT * FROM [{fileName}]";
                break;
        }

        return FillData(connection, query);
    }

它适用于 .csv 个文件，因为它使用文件名而不是 sheet 名称。

它适用于 .xls 和 .xlsx 文件，这些文件的作品sheet 名为 Sheet1。

当我尝试使用具有不同 sheet 名称的 .xls/.xlsx 文件时，出现以下错误：

System.Data.OleDb.OleDbException: ''Sheet1$' is not a valid name. Make sure that it does not include invalid characters or punctuation and that it is not too long.'

另一个问题的答案：

using (OleDbConnection conn = new OleDbConnection(connString))
{
    conn.Open();
    dtSchema = conn.GetOleDbSchemaTable(OleDbSchemaGuid.Tables, new object[] { null, null, null, "TABLE" });
    Sheet1= dtSchema.Rows[0].Field<string>("TABLE_NAME");
}

没有帮助，因为我不知道它应该放在我的代码中的什么位置，答案中也没有任何关于它应该放在什么位置的指示。

我这样加吗？

string Sheet1 = dataGridView1.Rows[0].Field<string>("TABLE_NAME");

这给了我一个错误：

Error CS1929 'DataGridViewRow' does not contain a definition for 'Field' and the best extension method overload 'DataRowExtensions.Field(DataRow, string)' requires a receiver of type 'DataRow'

Answer 1

尝试在 GetData 方法的末尾调用此方法而不是 FillData 方法，如您所见，不需要传递 query，因为此方法获取 sheetname self来自文档架构。

    private DataTable GetDataFromFirstSheet(string connection)
    {
        using (OleDbConnection conn = new OleDbConnection(connection))
        {
            using (DataTable dtSchema = conn.GetOleDbSchemaTable(OleDbSchemaGuid.Tables, new object[] { null, null, null, "TABLE" }))
            {
                string firstSheet = dtSchema.Rows[0].Field<string>("TABLE_NAME");

                //try to remove $ from sheetname if it will be not working
                using (OleDbCommand cmd = new OleDbCommand($"SELECT * FROM [{firstSheet}$]", conn))
                {
                    using (OleDbDataAdapter adp = new OleDbDataAdapter(cmd))
                    {
                        conn.Open();

                        DataTable dt = new DataTable();
                        adp.Fill(dt);

                        return dt;
                    }                            
                }
            }
        }
    }

Answer 2

我很快为您的代码添加了一些修复程序，但这个解决方案远非干净。您应该考虑@woldemar 的解决方案，并更深入地了解代码。一些优秀的资源可以在这里找到：https://github.com/EbookFoundation/free-programming-books

回到你的代码。要找出第一个 sheet 的名称，您必须首先打开到 xlsx 文件的连接。然后使用示例中的一些代码查询元数据：

using (OleDbConnection conn = new OleDbConnection(connString))
{
    conn.Open();
    dtSchema = conn.GetOleDbSchemaTable(OleDbSchemaGuid.Tables, new object[] { null, null, null, "TABLE" });
    Sheet1= dtSchema.Rows[0].Field<string>("TABLE_NAME");
}

之后，您可以将收到的 sheet 名称插入到您的查询中。

快速而肮脏，你的代码应该看起来像这样才能让它与 xlsx 文件一起工作：

private static DataTable GetData(string userFileName)
    {
        string dirName = Path.GetDirectoryName(userFileName);
        string fileName = Path.GetFileName(userFileName);
        string fileExtension = Path.GetExtension(userFileName);
        string connection = string.Empty;
        string query = string.Empty;

        switch (fileExtension)
        {
            case ".xls":
                connection = $@"Provider=Microsoft.Jet.OLEDB.4.0;Data Source={userFileName};" +
                             "Extended Properties=\"Excel 8.0; HDR=Yes; IMEX=1\"";
                query = "SELECT * FROM [Sheet1$]";
                break;

            case ".xlsx":
                connection = $@"Provider=Microsoft.ACE.OLEDB.12.0;Data Source={userFileName};" +
                             "Extended Properties=\"Excel 12.0; HDR=Yes; IMEX=1\"";
                string sheetName;
                using (OleDbConnection con = new OleDbConnection(connection))
                {
                    con.Open();
                    var dtSchema = con.GetOleDbSchemaTable(OleDbSchemaGuid.Tables, new object[] { null, null, null, "TABLE" });
                    sheetName = dtSchema.Rows[0].Field<string>("TABLE_NAME");
                }

                if (sheetName.Length <= 0) throw new InvalidDataException("No sheet found."); // abort if no sheet name was returned

                query = $"SELECT * FROM [{sheetName}]";
                break;

            case ".csv":
                connection = $@"Provider=Microsoft.ACE.OLEDB.12.0;Data Source={dirName};" +
                             "Extended Properties=\"text; HDR=Yes; IMEX=1; FMT=Delimited\"";
                query = $"SELECT * FROM [{fileName}]";
                break;
        }

        return FillData(connection, query);
    }

C# xls 和 xlsx 查询从 sheet 中选择而不考虑 sheet 名称

C# xls & xlsx query selecting from a sheet regardless of sheet name

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