JHipster 中的复选框

Question

我在 html

中有一个复选框

<input type="checkbox" class="form-control" name="myflag" [(ngModel)]="myEntity.myflag" id="field_myflag">

DB 上的字段 (myflag) 有 2 个可能的值 [OK, KO]，这 2 个值在枚举中定义：

@Enumerated(EnumType.STRING)
@Column(name = "MYFLAG")
private MYFLAGENUM myflag;

所以：

public enum MYFLAGENUM {
   OK, KO
}

每次尝试保存时，我都会遇到异常：

WARN 888 --- [ XNIO-7 task-5] .m.m.a.ExceptionHandlerExceptionResolver : Resolved exception caused by handler execution: org.springframework.http.converter.HttpMessageNotReadableException: JSON parse error: Cannot deserialize instance of myproject.hipster.testing.domain.enumeration.MYFLAGENUM out of VALUE_FALSE token; nested exception is com.fasterxml.jackson.databind.exc.MismatchedInputException: Cannot deserialize instance of myproject.hipster.testing.domain.enumeration.MYFLAGENUM out of VALUE_FALSE token at [Source: (PushbackInputStream); line: 1, column: 37] (through reference chain: myproject.hipster.testing.domain.MYENTITY["myflag"])

似乎VALUE_FALSE（或VALUE_TRUE）无法转换为'KO'（或'OK'）。所以我创建了一个转换器，但我看到它没有被调用。如何使用 JHipster 复选框管理我自己的 "boolean" 值？

Answer 1

尝试

...
@JsonDeserialize(using = OkKoDeserializer.class)
private MYFLAGENUM myflag;

和：

public class OkKoDeserializer extends StdScalarDeserializer<MYFLAGENUM> {
public OkKoDeserializer() {
    super(MYFLAGENUM.class);
}

@Override
public MYFLAGENUM deserialize(JsonParser p, DeserializationContext ctxt) throws IOException, JsonProcessingException {
    String value = p.getValueAsString();
    if ("VALUE_FALSE".equalsIgnoreCase(value)) {
        return MYFLAGENUM.KO;
    }
    if ("VALUE_TRUE".equalsIgnoreCase(value)) {
        return MYFLAGENUM.OK;
    }

    throw new IllegalArgumentException("value " + value + " is not parseable to a MYFLAGENUM");
}
}

通过这种方式，您可以告诉框架使用特殊策略将输入值转换为枚举值。

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